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IQ / Programming Quiz (Cannon-Ball Stacks)

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  • S Stephen Dycus

    Wow such complicated answers.... the answer is 4. The question is If the two smaller pyramids are different sizes, however, what would be the minimum number of cannon-balls he could use to make one large tetrahedral pyramid? ... but the thing is, there are still only 20 cannonballs to use to build the pyramid and he never said you had to use all the cannonballs. It asks the MINIMUM... which is 3 on the bottom + 1 on top.

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    AspDotNetDev
    wrote on last edited by
    #53

    You missed this bit from the problem: "assuming he uses every cannon-ball in both pyramids". But nice try. :)

    Thou mewling ill-breeding pignut!

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    • P PhilLenoir

      Maybe not the most elegant solution but might possibly be the fastest way to come up with the answer!: 1 Using Excel I created 3 columns: column 1 being a linear sequence (1,2,3 ....100); column 2 representing each layer (B1=1,B2=A1+A2); the third representing the pyramid (C1=1,C2=B1+B2) 2 I pasted these into an Access table 3 I cross joined the table to itself and added the two columns 3 4 I inner joined the query to the table on sum = column 3 Answer 120 (8 layers) + 560 (14 layers) = 680 (15 layers)

      Life is like a s**t sandwich; the more bread you have, the less s**t you eat.

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      AspDotNetDev
      wrote on last edited by
      #54

      PhilLenoir wrote:

      Using Excel I created 3 columns: column 1 being a linear sequence (1,2,3 ....100); column 2 representing each layer (B1=1,B2=A1+A2); the third representing the pyramid (C1=1,C2=B1+B2)

      That's how I started out on paper, then converted that to C#.

      PhilLenoir wrote:

      I inner joined the query to the table on sum = column 3

      I hadn't considered using a database. Points for innovation. :thumbsup:

      PhilLenoir wrote:

      680

      That's the answer I got. :)

      Thou mewling ill-breeding pignut!

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      • Y YvesDaoust

        Even bruter force:

        def T(n):
        return n * (n + 1) * (n + 2) / 6

        for r in range (1, 1000):
        for q in range(1, r):
        for p in range(1, q):
        if T(p) + T(q) == T(r):
        print T(p), '+', T(q), '=', T(r)

        Yields:

        120 + 560 = 680
        1540 + 27720 = 29260
        4960 + 29260 = 34220
        10660 + 59640 = 70300
        39711 + 182104 = 221815
        102340 + 125580 = 227920
        7140 + 280840 = 287980
        19600 + 447580 = 467180
        ...

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        AspDotNetDev
        wrote on last edited by
        #55

        Points for compact code. :thumbsup:

        Thou mewling ill-breeding pignut!

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        • E el_vez

          Haskell answer:

          layers = scanl1 (+) [1..]
          sizes = scanl1 (+) layers
          combinedSizes = [(s1, s2, s1 + s2) | s1 <- sizes, s2 <- takeWhile (< s1) sizes]
          newPyramids = filter combinesToPyramid combinedSizes
          where combinesToPyramid (s1, s2, sum) = sum `elem` (takeWhile (sum >=) sizes)

          answer = head newPyramids

          -------- SPOILER ------------ this gives the answer as "(560, 120, 680)", (if you load it up in GHCI and type "answer"). If you want the n first solutions, just type "take n newPyramids":

          take 3 newPyramids
          [(560,120,680),(27720,1540,29260),(29260,4960,34220)]

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          AspDotNetDev
          wrote on last edited by
          #56

          I don't know Haskell, but that looks pretty elegant. Points awarded. :)

          Thou mewling ill-breeding pignut!

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          • A AspDotNetDev

            You missed this bit from the problem: "assuming he uses every cannon-ball in both pyramids". But nice try. :)

            Thou mewling ill-breeding pignut!

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            Stephen Dycus
            wrote on last edited by
            #57

            That's an assumption though, not a requirement. A requirement would be worded something like: (as he must use every cannonball from both pyramids) The fact that the problem states exactly how many cannon balls there are should tell you something. With 20 cannonballs the best you could do with 2 pyramids is a 3+1 pyramid and a 6+3+1 pyramid with 6 left over. The question asks if the pyramids are not the same size, what would be the minimum. This doesn't magically give you permission to *add* more cannonballs to the equation :P So if it *is* a poorly worded requirement then the answer is 20. Otherwise, it's 4.

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            • Y YvesDaoust
              1. looked up the tetrahedral numbers in Wikipedia and found this list: 1, 4, 10, 20, 35, 56, 84, 120, 165, 220, 286, 364, 455, 560, 680, 816, 969... (10 seconds of work) 2) opened an Excel sheet and created the table of sums 2 5 11 21 36 57... 5 8 14 24 39 60... 11 14 20 30 45 66... 21 24 30 40 55 76... 36 39 45 55 70 91... ... (just needed to recall the appropriate syntax to form the cell expression; 1 minute of work) 3) sorted all sums in increasing order 2, 5, 5, 8, 11, 11, 14, 14, 20, 21, 21, 24, 24, 30, 30, 36, 36, 39, 39, 40, 45, 45, 55, 55, 57, 57, 60, 60, 66, 66, 70, 76, 76, 85, 85, 88, 88, 91, 91, ... (moved to Word to flatten the table structure; 1 minute of work) 4) spotted by eye in the list the first tetrahedral number larger than 20: 680, the sum of 120 and 560. (Lucky the Wikipedia list was long enough :)) (2 extra minutes) 5) explained the answer in CodeProject (half an hour)
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              AspDotNetDev
              wrote on last edited by
              #58

              Points awarded for getting as close as possible to cheating without fully qualifying as cheating. ;P

              Thou mewling ill-breeding pignut!

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              • J jsc42

                I did this using an old technique: pencil and paper. It is more complicated to explain than it was to do. Basically, I wrote 3 columns of numbers: Col 1: 1, 2, 3, 4, etc [represents the no of levels in the pyramid) Col 2: 1, (corresponding no in col 1 + prev number in col 2), ... [represents the no of new balls in the new level of the pyramid] Col 3: 1, (corresponding no in col 2 + prev number in col 3), ... [represents the total no of balls in the pyramid] and then looked for a number in col 2 that was the same as a number in col 3 which is a pyramid's worth of balls that is also a level's worth of balls [Actually, I didn't bother with col 1 - I could work that one out without writing it down, but it is easier to explain with it there] My solution is ... The first one found was 120, so the solution is 120 + 560 (no in col 3 before the 120 in col 2) = 680 (no in col 3 next to 120 in col 2). (select the text in the gap above, e.g. by dragging the mouse, to read it) Of course, this discounts the possibility that a pyramid might split across multiple levels in a combined pyramid. Just in case I had made a simple arithmetic error, I checked in MS-Excel: Cell A1 = 1, B1 = 1, C1 = 1 Cell A2 = =A1+1, B2 = =A2+B1, C2 = =B2+C1 Cells A3 through C17 = Copy and paste A2 through C2 [I've had to edit this entry twice - suffering from lysdexia (!) today].

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                AspDotNetDev
                wrote on last edited by
                #59

                Good call on confirming you didn't make an error. I started out on paper and indeed made an error, which I happened to spot when I made the C# program.

                Thou mewling ill-breeding pignut!

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                • J jsc42

                  I did this using an old technique: pencil and paper. It is more complicated to explain than it was to do. Basically, I wrote 3 columns of numbers: Col 1: 1, 2, 3, 4, etc [represents the no of levels in the pyramid) Col 2: 1, (corresponding no in col 1 + prev number in col 2), ... [represents the no of new balls in the new level of the pyramid] Col 3: 1, (corresponding no in col 2 + prev number in col 3), ... [represents the total no of balls in the pyramid] and then looked for a number in col 2 that was the same as a number in col 3 which is a pyramid's worth of balls that is also a level's worth of balls [Actually, I didn't bother with col 1 - I could work that one out without writing it down, but it is easier to explain with it there] My solution is ... The first one found was 120, so the solution is 120 + 560 (no in col 3 before the 120 in col 2) = 680 (no in col 3 next to 120 in col 2). (select the text in the gap above, e.g. by dragging the mouse, to read it) Of course, this discounts the possibility that a pyramid might split across multiple levels in a combined pyramid. Just in case I had made a simple arithmetic error, I checked in MS-Excel: Cell A1 = 1, B1 = 1, C1 = 1 Cell A2 = =A1+1, B2 = =A2+B1, C2 = =B2+C1 Cells A3 through C17 = Copy and paste A2 through C2 [I've had to edit this entry twice - suffering from lysdexia (!) today].

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                  AspDotNetDev
                  wrote on last edited by
                  #60

                  jsc42 wrote:

                  lysdexia

                  :laugh: I thought I was the only one who used that word. Actually, I saw it on some nature show when I was younger and have been using it ever since. :thumbsup:

                  Thou mewling ill-breeding pignut!

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                  • S Stephen Dycus

                    That's an assumption though, not a requirement. A requirement would be worded something like: (as he must use every cannonball from both pyramids) The fact that the problem states exactly how many cannon balls there are should tell you something. With 20 cannonballs the best you could do with 2 pyramids is a 3+1 pyramid and a 6+3+1 pyramid with 6 left over. The question asks if the pyramids are not the same size, what would be the minimum. This doesn't magically give you permission to *add* more cannonballs to the equation :P So if it *is* a poorly worded requirement then the answer is 20. Otherwise, it's 4.

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                    AspDotNetDev
                    wrote on last edited by
                    #61

                    Stephen Dycus wrote:

                    the answer is 20. Otherwise, it's 4

                    Nope and nope. :)

                    Rafiki said:

                    Look harder.

                    Thou mewling ill-breeding pignut!

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                    • A AspDotNetDev

                      Stephen Dycus wrote:

                      the answer is 20. Otherwise, it's 4

                      Nope and nope. :)

                      Rafiki said:

                      Look harder.

                      Thou mewling ill-breeding pignut!

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                      Stephen Dycus
                      wrote on last edited by
                      #62

                      "I will post tomorrow how I arrived at my solution (which may be incorrect, as the book doesn't list what the correct answer is)" You can't say "nope" when you don't even know if you are correct XD

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                      • S Stephen Dycus

                        "I will post tomorrow how I arrived at my solution (which may be incorrect, as the book doesn't list what the correct answer is)" You can't say "nope" when you don't even know if you are correct XD

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                        AspDotNetDev
                        wrote on last edited by
                        #63

                        My not know if I'm correct does not preclude my knowing you are incorrect. :)

                        Thou mewling ill-breeding pignut!

                        S 1 Reply Last reply
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                        • A AspDotNetDev

                          Background

                          I'm reading "The Mammoth Book of IQ Puzzles". It contains, as you may have guessed, a bunch of IQ puzzles. I just solved one of them and thought I'd write the problem down here so you would all have a chance to solve it too. It is called "Cannon-Ball Stacks". In finding the answer, reference materials, books, calculators, and computers are allowed. Since computers are allowed, programs can be created to get the solution.

                          Cannon-Ball Stacks

                          A park ranger has stacked cannon-balls in two tetrahedral pyramids for display at Gettysburg. He later decides to combine the cannon-balls in both of the pyramids in order to create one large pyramid. The smallest number of cannon-balls he can have if the two pyramids are the same size is twenty (assuming he uses every cannon-ball in both pyramids).

                          [10 cannon-ball pyramid] + [10 cannon-ball pyramid] = [20 cannon-ball pyramid]

                          If the two smaller pyramids are different sizes, however, what would be the minimum number of cannon-balls he could use to make one large tetrahedral pyramid? Difficulty: 4 out of 5.

                          AspDotNetDev's Extra Rules

                          Explain how you arrived at the solution. If you create a program to help you solve the problem, paste that in your message. I will reply to this message with the answer in a hidden <span> tag. Don't cheat by looking first though! I will post tomorrow how I arrived at my solution (which may be incorrect, as the book doesn't list what the correct answer is). Points will be awarded for: elegance, quickness, humor, and correcting others (in no particular order). Good luck!

                          Thou mewling ill-breeding pignut!

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                          YvesDaoust
                          wrote on last edited by
                          #64

                          Not-so-brute brute-force: This version is based on a simple test for tetrahedrality: if N = n.(n+1).(n+2), n is the integer cube root of N, so that N gives n gives back the same N. (As one can check, n^3 <= N < (n+1)^3 so that n <= N^1/3 < n+1.) Now all tetrahedral number pairs are tried and their sum tested for tetrahedrality.

                          def T(n):
                          return n * (n + 1) * (n + 2)

                          def IsT(N):
                          return N == T(int(pow(N, 1. / 3.)))

                          for q in range(1, 1000):
                          for p in range(1, q):
                          if IsT(T(p) + T(q)):
                          print T(p) / 6, '+', T(q) / 6, '=', (T(p) + T(q)) / 6

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                          • A AspDotNetDev

                            My not know if I'm correct does not preclude my knowing you are incorrect. :)

                            Thou mewling ill-breeding pignut!

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                            Stephen Dycus
                            wrote on last edited by
                            #65

                            Yes it does, if you are incorrect then you do not know the correct answer. With 20 cannonballs there are only 3 possible answers: 3+1 = 4 aka MIN 6+3+1 = 10 10+6+3+1 = 20 aka MAX Since my solution IS a tetrahedral pyramid you cannot deduce that my answer is incorrect without knowing the correct answer.

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                            • A AspDotNetDev

                              Points awarded for getting as close as possible to cheating without fully qualifying as cheating. ;P

                              Thou mewling ill-breeding pignut!

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                              YvesDaoust
                              wrote on last edited by
                              #66

                              ;)

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                              • A AspDotNetDev

                                Points for compact code. :thumbsup:

                                Thou mewling ill-breeding pignut!

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                                YvesDaoust
                                wrote on last edited by
                                #67

                                Thanks. I just released a more efficient compact one.

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                                • R RolfReden

                                  got one, just by accident :) 560 + 120 = 680, which are an 8-layered and a 14-layered pyramid combined to a 15-layered pyramid. still thinking of an smart search or algebraic solution tho [edit for some code] clear clc lines(0) n = 30 m(1) = 1 k(1) = 1 for i = 1:n m(i+1) = m(i) + 1 + (i) k(i+1) = k(i) + m(i+1) end [/edit]

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                                  AspDotNetDev
                                  wrote on last edited by
                                  #68

                                  RolfReden wrote:

                                  still thinking of an smart search or algebraic solution tho

                                  You could start with this equation:

                                  a(a^2 + 3a + 2) + (a + b)((a + b)^2 + 3(a + b) + 2) = (a + b + c)((a + b + c)^2 + 3(a + b + c) + 2)

                                  The variable (a) is the Nth pyramid for the smallest pyramid. (a + b) is the Nth pyramid for the medium pyramid. (a + b + c) is the Nth pyramid for the large pyramid. Once you have solved for those values, you can plug them into this equation:

                                  n(n + 1)(n + 2)/6

                                  That converts the Nth pyramid into the number of cannon-balls in that pyramid. The first equation will have multiple solutions (infinite solutions?), and some values may be negative. Find the solution where a, b, and c are all positive with the smallest value of (a + b + c), and you have found the solution. :)

                                  Thou mewling ill-breeding pignut!

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                                  • S Stephen Dycus

                                    Yes it does, if you are incorrect then you do not know the correct answer. With 20 cannonballs there are only 3 possible answers: 3+1 = 4 aka MIN 6+3+1 = 10 10+6+3+1 = 20 aka MAX Since my solution IS a tetrahedral pyramid you cannot deduce that my answer is incorrect without knowing the correct answer.

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                                    AspDotNetDev
                                    wrote on last edited by
                                    #69

                                    Stephen Dycus wrote:

                                    you cannot deduce that my answer is incorrect without knowing the correct answer

                                    I can, actually. :) Take this equation, for example:

                                    a^2 + b^2 = c^2

                                    Find a solution to this equation where a, b, and c are all positive integers. You might give the solution: a = 1, b = 2, c = 3. Though I may not know a correct answer, I can show that 5 does not equal 9, and so I can show that you are incorrect. Just because I don't know the solution does not mean I can't spot an incorrect solution. :)

                                    Thou mewling ill-breeding pignut!

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                                    • A AspDotNetDev

                                      Nope, 20 + 54 is not 55.

                                      Thou mewling ill-breeding pignut!

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                                      Thor Sigurdsson
                                      wrote on last edited by
                                      #70

                                      You are quite correct. My brainfarts are legendary. When I said 20 and 54, I did of course mean 20 levels and 54 levels...... 20 levels are 1540 balls and 54 levels are 27720 balls. 55 levels are 29260 balls. Simplified, it can be done:

                                      def onelev(x):
                                      '''The x defines number of balls in a single level given the formula f(x)=(x^2)/2+(x/2)'''
                                      return int((float(x)*float(x))/2.0)+(float(x)/2.0))

                                      def tetra(x):
                                      '''The x defines number of levels of balls in the tetrahedron'''
                                      return sum([onelev(y) for y in range(1,x+1)])

                                      tetra(20)
                                      1540
                                      tetra(54)
                                      27720
                                      tetra(55)-tetra(20)
                                      27720

                                      So I guess my answer was in part correct although not very accurate :) But, looking above, there is a smaller answer ( which I haphazardly ignored since I started to work up from 10 :p ) >>> searchtetra(2,18) 560 120 680 14 8 15 My bad there (yeah, don't solve puzzles while working - you don't have time to verify your mess haha :) )

                                      I=I.am()?Code(I):0/0;

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                                      • A AspDotNetDev

                                        Stephen Dycus wrote:

                                        you cannot deduce that my answer is incorrect without knowing the correct answer

                                        I can, actually. :) Take this equation, for example:

                                        a^2 + b^2 = c^2

                                        Find a solution to this equation where a, b, and c are all positive integers. You might give the solution: a = 1, b = 2, c = 3. Though I may not know a correct answer, I can show that 5 does not equal 9, and so I can show that you are incorrect. Just because I don't know the solution does not mean I can't spot an incorrect solution. :)

                                        Thou mewling ill-breeding pignut!

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                                        Stephen Dycus
                                        wrote on last edited by
                                        #71

                                        But you are still under the *assumption* that you HAVE to use all the cannonballs in the two pyramids. You are also *assuming* that the two new pyramids can exceed the original 20 cannonball count from the beginning of the problem, otherwise there would be no solution. (You can only make a 3+1 and 6+3+1 out of 20 balls, to use them all would require a 4+6+3+1 pyramid... which isn't a pyramid. If you use the spares you can make a 10+6+3+1 pyramid though) To read the problem *your* way would require an equation for the expansion of the pyramid: 1(not a pyramid of course) 3+1 height = 2 6+3+1 height = 3 10+6+3+1 height = 4 15+10+6+3+1 height = 5 ... aka new base = old base + n, where n = the new height Then you would compose three equations for the pyramids and differentiate to optimize the problem. However, the book you are reading is a book with IQ problems. These sorts of problems typically have you analyze the question itself to find what it is REALLY asking for. In this case, the question is REALLY asking: what's the smallest pyramid you could make?

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                                        • S Stephen Dycus

                                          But you are still under the *assumption* that you HAVE to use all the cannonballs in the two pyramids. You are also *assuming* that the two new pyramids can exceed the original 20 cannonball count from the beginning of the problem, otherwise there would be no solution. (You can only make a 3+1 and 6+3+1 out of 20 balls, to use them all would require a 4+6+3+1 pyramid... which isn't a pyramid. If you use the spares you can make a 10+6+3+1 pyramid though) To read the problem *your* way would require an equation for the expansion of the pyramid: 1(not a pyramid of course) 3+1 height = 2 6+3+1 height = 3 10+6+3+1 height = 4 15+10+6+3+1 height = 5 ... aka new base = old base + n, where n = the new height Then you would compose three equations for the pyramids and differentiate to optimize the problem. However, the book you are reading is a book with IQ problems. These sorts of problems typically have you analyze the question itself to find what it is REALLY asking for. In this case, the question is REALLY asking: what's the smallest pyramid you could make?

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                                          AspDotNetDev
                                          wrote on last edited by
                                          #72
                                          1. I am not making assumptions, I am reading the entire problem, which consists of more than the final sentence that ends with a question mark. 2) It would not require an equation, though an equation does help. I could work out the problem on paper pretty fast, though using something like Excel helps speed things up (note that computers are allowed, as stated in the book).

                                          Stephen Dycus wrote:

                                          the question is REALLY asking: what's the smallest pyramid you could make?

                                          I thought it was asking for the smallest tetrahedral pyramid. ;)

                                          Stephen Dycus wrote:

                                          1(not a pyramid of course)

                                          Interesting assumption. :)

                                          Thou mewling ill-breeding pignut!

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