Missed Opportunity for Easter Egg

lewax00

What I don't understand is why they went with 12 and not 13. I feel like that would have fit better.

OriginalGriff

I thought MSDN recommended:

if (23 == 023)
{
...
}

Ideological Purity is no substitute for being able to stick your thumb down a pipe to stop the water

Lost User

2 + 2 = 5 if Big Bro says so.

Computers have been intelligent for a long time now. It just so happens that the program writers are about as effective as a room full of monkeys trying to crank out a copy of Hamlet.

Tadas Budvytis

ha ha. Make it on production and guaranteed next day customers will call u ... ;)

Steve Mayfield

When I first read this, I assumed it was "ell" = 2 :doh:

Steve _________________ I C(++) therefore I am

Sander Rossel

I've unwillingly sent millions of $ to my private bank account because O looked a lot like 0! Well, that's what I'll tell the judge when they find out ;p

It's an OO world.

public class Naerling : Lazy<Person>{
public void DoWork(){ throw new NotImplementedException(); }
}

Manfred Rudolf Bihy

Not f***ed, but rather elephanted or maybe pachydermed. Cheers!

"With sufficient thrust, pigs fly just fine."

Ross Callon, The Twelve Networking Truths, RFC1925

"Der Berg ruft!"

Me, 2012-05-24

lewax00 · Me, 2012-05-24

Of course, how could I be so foolish?

Matthew Dennis

or 9 x 6 = 42

greldak

In VB that expression will always resolve to False In other languages (C included) you could overload the values for 1 and 2 and/or the operator = or command If Good luck figuring out whats going on with that level of obfuscation. Its not something I would expect to see as a simple expression but it can be useful as a clause especially if you need to build up a complex expression at run time. In practice its more likely that some piece of funcionality is wanted to remain in the codebase but not required to run under normal circumstances - probably debug code although there are better ways of doing it.

svella

greldak wrote:

In other languages (C included) you could overload the values for 1 and 2 and/or the operator = or command If
Good luck figuring out whats going on with that level of obfuscation.

I'm pretty sure you're wrong about being able to override either the values or the operator in C (or even C++ for that matter), but I'd welcome a working example.

Sucramsy

If 42 is the answer to life the universe and everything then this statement would be true.

reilly96

in SQL I use that to create tables with no data

select *
into #t
from table1
where 1=2

onemorechance

OriginalGriff wrote:

... my constant values had changed...

Something about that just doesn't seem right ...

ekolis

You can do that in Java as well, though it requires boxing conversions...

OriginalGriff

That's why it took so long to work it out - it's just not something you expect... :laugh:

Ideological Purity is no substitute for being able to stick your thumb down a pipe to stop the water

AspDotNetDev

Neat trick. :thumbsup:

Thou mewling ill-breeding pignut!

Kostya Kovalskyy

compiles on GCC

#define if(X) if(1)

using namespace std;

int main()
{
if (1 == 2) {
cout << "this is executed" << endl;
}
return 0;
}

this would compile on C compiler too, but I just hate using those printfs. But you were right about #defining numbers -- it's impossible. A define identifier name cannot start with a number. But you can overload almost anything else.

svella

Hmmm, yeah, well what you've really done is macro replaced an "if" expression (not really overloaded it in the normal sense of the word, but I guess close enough), but have not really succeeded in overloading 1, 2, or ==.

Kostya Kovalskyy

Even through it does not really "overload" it, it can still lead to a lot of confusion. In C++ you can also do something like this

#include

class T {
public:
int a;
T(int _a) : a(_a) {}
bool operator==(const T &var) {return true;}
};

using namespace std;

int main() {
#define int T //this is defined here because main returns int, and this causes error if defined earlier
int a = 1, b = 2;
if (a == b) {
cout << "this is evaluated" << endl;
}
return 0;
}
}

Of course, you can always put anything in the == operator so it would behave differently :)