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Special Case

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • B Brisingr Aerowing

    :doh: What was that coder thinking? EDIT: Or WAS he/she thinking?

    public class SysAdmin : Employee
    {

     public override void DoWork(IWorkItem workItem)
     {
          if (workItem.User.Type == UserType.NoLearn){
             throw new NoIWillNotFixYourComputerException(new Luser(workItem.User));
          }else{
               base.DoWork(workItem);
          }
     }
    

    }

    L Offline
    L Offline
    Lost User
    wrote on last edited by
    #3

    And let those who have never failed to see the obvious throw the first stone :)

    At least artificial intelligence already is superior to natural stupidity

    B P 2 Replies Last reply
    0
    • L Lost User

      And let those who have never failed to see the obvious throw the first stone :)

      At least artificial intelligence already is superior to natural stupidity

      B Offline
      B Offline
      Brisingr Aerowing
      wrote on last edited by
      #4

      :-D

      public class SysAdmin : Employee
      {

       public override void DoWork(IWorkItem workItem)
       {
            if (workItem.User.Type == UserType.NoLearn){
               throw new NoIWillNotFixYourComputerException(new Luser(workItem.User));
            }else{
                 base.DoWork(workItem);
            }
       }
      

      }

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      0
      • L Lost User

        And let those who have never failed to see the obvious throw the first stone :)

        At least artificial intelligence already is superior to natural stupidity

        P Offline
        P Offline
        PIEBALDconsult
        wrote on last edited by
        #5

        Hey now, maybe it was originally written with constants or enumerations. :~

        S 1 Reply Last reply
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        • P PIEBALDconsult

          Hey now, maybe it was originally written with constants or enumerations. :~

          S Offline
          S Offline
          Sentenryu
          wrote on last edited by
          #6

          yeah, sure, increment a enumeration...

          I'm brazilian and english (well, human languages in general) aren't my best skill, so, sorry by my english. (if you want we can speak in C# or VB.Net =p)

          1 Reply Last reply
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          • R Rotted Frog

            Just a quick one, but amused me when I saw it in code today.

            if (i == 0)
            return 1;
            else
            return i + 1;

            R Offline
            R Offline
            RobCroll
            wrote on last edited by
            #7

            That is funny++.

            "You get that on the big jobs."

            1 Reply Last reply
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            • R Rotted Frog

              Just a quick one, but amused me when I saw it in code today.

              if (i == 0)
              return 1;
              else
              return i + 1;

              H Offline
              H Offline
              hollysong
              wrote on last edited by
              #8

              Interesting :) But i can not imagine the reason of the code. Can you give the full scope of code? Thinking but nothing find about the code :)

              1 Reply Last reply
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              • R Rotted Frog

                Just a quick one, but amused me when I saw it in code today.

                if (i == 0)
                return 1;
                else
                return i + 1;

                Y Offline
                Y Offline
                YvesDaoust
                wrote on last edited by
                #9

                A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                if (i < 0)
                return 1 - abs(i);
                else if (i == 0)
                return 1;
                else if (i > 0)
                return 1 + abs(i);

                (with the added benefit that out-of-range values are left unchanged)

                A A S 3 Replies Last reply
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                • Y YvesDaoust

                  A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                  if (i < 0)
                  return 1 - abs(i);
                  else if (i == 0)
                  return 1;
                  else if (i > 0)
                  return 1 + abs(i);

                  (with the added benefit that out-of-range values are left unchanged)

                  A Offline
                  A Offline
                  Andrei Straut
                  wrote on last edited by
                  #10

                  return (i < 0) ? (1 - abs(i)) : ((i == 0) ? 1 : 1 + abs(i));

                  Here. Shorter now, and less obvious to spot. The benefits of multiple ternaries :-D :-D

                  Y 1 Reply Last reply
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                  • A Andrei Straut

                    return (i < 0) ? (1 - abs(i)) : ((i == 0) ? 1 : 1 + abs(i));

                    Here. Shorter now, and less obvious to spot. The benefits of multiple ternaries :-D :-D

                    Y Offline
                    Y Offline
                    YvesDaoust
                    wrote on last edited by
                    #11

                    Right. This allows us to move the common constant in front and factor out the abs call:

                    return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : + 1));

                    But how do we make the i > 0 case explicit ??? Maybe

                    return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : ((i > 0) ? + 1 : abort(), 0)));

                    A 1 Reply Last reply
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                    • Y YvesDaoust

                      Right. This allows us to move the common constant in front and factor out the abs call:

                      return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : + 1));

                      But how do we make the i > 0 case explicit ??? Maybe

                      return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : ((i > 0) ? + 1 : abort(), 0)));

                      A Offline
                      A Offline
                      Andrei Straut
                      wrote on last edited by
                      #12

                      And even better, we can abstract away the "1", who knows, maybe its value will change somewhere in the future:

                      final int _CONST = 1;
                      return _CONST + abs(i) * ((i < 0) ? - _CONST : ((i == 0) ? 0 : ((i > 0) ? + _CONST : abort(), 0)));

                      Can I have that mind bleach now, please? :-D

                      Y 1 Reply Last reply
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                      • R Rotted Frog

                        Just a quick one, but amused me when I saw it in code today.

                        if (i == 0)
                        return 1;
                        else
                        return i + 1;

                        A Offline
                        A Offline
                        AshenFlowersFalling
                        wrote on last edited by
                        #13

                        Came across this piece of solid-gold coding in Android the other day, in good old SurfaceFlinger.cpp:

                        if (mCurrentState.orientation != orientation) {
                        if (uint32_t(orientation)<=eOrientation270 || orientation==42) {
                        mCurrentState.orientationType = flags;
                        mCurrentState.orientation = orientation;
                        setTransactionFlags(eTransactionNeeded);
                        mTransactionCV.wait(mStateLock);
                        } else {
                        orientation = BAD_VALUE;
                        }
                        }

                        Sometimes I just don't know what to think any more. :D

                        +++DIVIDE BY CUCUMBER ERROR+++

                        A 1 Reply Last reply
                        0
                        • A Andrei Straut

                          And even better, we can abstract away the "1", who knows, maybe its value will change somewhere in the future:

                          final int _CONST = 1;
                          return _CONST + abs(i) * ((i < 0) ? - _CONST : ((i == 0) ? 0 : ((i > 0) ? + _CONST : abort(), 0)));

                          Can I have that mind bleach now, please? :-D

                          Y Offline
                          Y Offline
                          YvesDaoust
                          wrote on last edited by
                          #14

                          Sure.

                          return -~i;

                          1 Reply Last reply
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                          • R Rotted Frog

                            Just a quick one, but amused me when I saw it in code today.

                            if (i == 0)
                            return 1;
                            else
                            return i + 1;

                            V Offline
                            V Offline
                            VallarasuS
                            wrote on last edited by
                            #15

                            Guess the author is afraid of "AddWithZeroException" :laugh: :laugh: :laugh:

                            Regards Vallarasu S | FSharpMe.blogspot.com

                            1 Reply Last reply
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                            • A AshenFlowersFalling

                              Came across this piece of solid-gold coding in Android the other day, in good old SurfaceFlinger.cpp:

                              if (mCurrentState.orientation != orientation) {
                              if (uint32_t(orientation)<=eOrientation270 || orientation==42) {
                              mCurrentState.orientationType = flags;
                              mCurrentState.orientation = orientation;
                              setTransactionFlags(eTransactionNeeded);
                              mTransactionCV.wait(mStateLock);
                              } else {
                              orientation = BAD_VALUE;
                              }
                              }

                              Sometimes I just don't know what to think any more. :D

                              +++DIVIDE BY CUCUMBER ERROR+++

                              A Offline
                              A Offline
                              Andrei Straut
                              wrote on last edited by
                              #16

                              Well, just hold your phone at 42 degrees :-D. And also, there were worse f'ups: (Steve Jobs "Don't hold it that way", anyone?) Actually, there were none :confused:

                              1 Reply Last reply
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                              • Y YvesDaoust

                                A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                                if (i < 0)
                                return 1 - abs(i);
                                else if (i == 0)
                                return 1;
                                else if (i > 0)
                                return 1 + abs(i);

                                (with the added benefit that out-of-range values are left unchanged)

                                A Offline
                                A Offline
                                ASkoro
                                wrote on last edited by
                                #17

                                Hey but what about i being sqrt(2)???

                                Y 1 Reply Last reply
                                0
                                • Y YvesDaoust

                                  A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                                  if (i < 0)
                                  return 1 - abs(i);
                                  else if (i == 0)
                                  return 1;
                                  else if (i > 0)
                                  return 1 + abs(i);

                                  (with the added benefit that out-of-range values are left unchanged)

                                  S Offline
                                  S Offline
                                  sergiogarcianinja
                                  wrote on last edited by
                                  #18

                                  I just tried your method, and my compiler is generating a error about a method must return a value, so I fixed it. There is a version without bugs, hope it helps:

                                  if (i < 0)
                                  return 1 - abs(i);
                                  else if (i == 0)
                                  return 1;
                                  else if (i > 0)
                                  return 1 + abs(i);

                                  K 1 Reply Last reply
                                  0
                                  • R Rotted Frog

                                    Just a quick one, but amused me when I saw it in code today.

                                    if (i == 0)
                                    return 1;
                                    else
                                    return i + 1;

                                    S Offline
                                    S Offline
                                    sergiogarcianinja
                                    wrote on last edited by
                                    #19

                                    I a very humble opinion, I think the original developer cared about performance. There is a big and ugly monster living in or closes that will eat us if we write less performing code. The problem is, that almost all developers don't understand about performance and do wrong things. Here, I think he/she are trying to avoid a sum using a comparison. In some cases, like division, it will be a great code.

                                    1 Reply Last reply
                                    0
                                    • A ASkoro

                                      Hey but what about i being sqrt(2)???

                                      Y Offline
                                      Y Offline
                                      YvesDaoust
                                      wrote on last edited by
                                      #20

                                      Function will return sqrt(2) + 1

                                      A 1 Reply Last reply
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                                      • Y YvesDaoust

                                        Function will return sqrt(2) + 1

                                        A Offline
                                        A Offline
                                        ASkoro
                                        wrote on last edited by
                                        #21

                                        And for sqrt(-2)????

                                        Y M K 3 Replies Last reply
                                        0
                                        • A ASkoro

                                          And for sqrt(-2)????

                                          Y Offline
                                          Y Offline
                                          YvesDaoust
                                          wrote on last edited by
                                          #22

                                          SquareRootException + 1

                                          1 Reply Last reply
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