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Special Case

Scheduled Pinned Locked Moved The Weird and The Wonderful
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  • R Rotted Frog

    Just a quick one, but amused me when I saw it in code today.

    if (i == 0)
    return 1;
    else
    return i + 1;

    H Offline
    H Offline
    hollysong
    wrote on last edited by
    #8

    Interesting :) But i can not imagine the reason of the code. Can you give the full scope of code? Thinking but nothing find about the code :)

    1 Reply Last reply
    0
    • R Rotted Frog

      Just a quick one, but amused me when I saw it in code today.

      if (i == 0)
      return 1;
      else
      return i + 1;

      Y Offline
      Y Offline
      YvesDaoust
      wrote on last edited by
      #9

      A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

      if (i < 0)
      return 1 - abs(i);
      else if (i == 0)
      return 1;
      else if (i > 0)
      return 1 + abs(i);

      (with the added benefit that out-of-range values are left unchanged)

      A A S 3 Replies Last reply
      0
      • Y YvesDaoust

        A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

        if (i < 0)
        return 1 - abs(i);
        else if (i == 0)
        return 1;
        else if (i > 0)
        return 1 + abs(i);

        (with the added benefit that out-of-range values are left unchanged)

        A Offline
        A Offline
        Andrei Straut
        wrote on last edited by
        #10

        return (i < 0) ? (1 - abs(i)) : ((i == 0) ? 1 : 1 + abs(i));

        Here. Shorter now, and less obvious to spot. The benefits of multiple ternaries :-D :-D

        Y 1 Reply Last reply
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        • A Andrei Straut

          return (i < 0) ? (1 - abs(i)) : ((i == 0) ? 1 : 1 + abs(i));

          Here. Shorter now, and less obvious to spot. The benefits of multiple ternaries :-D :-D

          Y Offline
          Y Offline
          YvesDaoust
          wrote on last edited by
          #11

          Right. This allows us to move the common constant in front and factor out the abs call:

          return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : + 1));

          But how do we make the i > 0 case explicit ??? Maybe

          return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : ((i > 0) ? + 1 : abort(), 0)));

          A 1 Reply Last reply
          0
          • Y YvesDaoust

            Right. This allows us to move the common constant in front and factor out the abs call:

            return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : + 1));

            But how do we make the i > 0 case explicit ??? Maybe

            return 1 + abs(i) * ((i < 0) ? - 1 : ((i == 0) ? 0 : ((i > 0) ? + 1 : abort(), 0)));

            A Offline
            A Offline
            Andrei Straut
            wrote on last edited by
            #12

            And even better, we can abstract away the "1", who knows, maybe its value will change somewhere in the future:

            final int _CONST = 1;
            return _CONST + abs(i) * ((i < 0) ? - _CONST : ((i == 0) ? 0 : ((i > 0) ? + _CONST : abort(), 0)));

            Can I have that mind bleach now, please? :-D

            Y 1 Reply Last reply
            0
            • R Rotted Frog

              Just a quick one, but amused me when I saw it in code today.

              if (i == 0)
              return 1;
              else
              return i + 1;

              A Offline
              A Offline
              AshenFlowersFalling
              wrote on last edited by
              #13

              Came across this piece of solid-gold coding in Android the other day, in good old SurfaceFlinger.cpp:

              if (mCurrentState.orientation != orientation) {
              if (uint32_t(orientation)<=eOrientation270 || orientation==42) {
              mCurrentState.orientationType = flags;
              mCurrentState.orientation = orientation;
              setTransactionFlags(eTransactionNeeded);
              mTransactionCV.wait(mStateLock);
              } else {
              orientation = BAD_VALUE;
              }
              }

              Sometimes I just don't know what to think any more. :D

              +++DIVIDE BY CUCUMBER ERROR+++

              A 1 Reply Last reply
              0
              • A Andrei Straut

                And even better, we can abstract away the "1", who knows, maybe its value will change somewhere in the future:

                final int _CONST = 1;
                return _CONST + abs(i) * ((i < 0) ? - _CONST : ((i == 0) ? 0 : ((i > 0) ? + _CONST : abort(), 0)));

                Can I have that mind bleach now, please? :-D

                Y Offline
                Y Offline
                YvesDaoust
                wrote on last edited by
                #14

                Sure.

                return -~i;

                1 Reply Last reply
                0
                • R Rotted Frog

                  Just a quick one, but amused me when I saw it in code today.

                  if (i == 0)
                  return 1;
                  else
                  return i + 1;

                  V Offline
                  V Offline
                  VallarasuS
                  wrote on last edited by
                  #15

                  Guess the author is afraid of "AddWithZeroException" :laugh: :laugh: :laugh:

                  Regards Vallarasu S | FSharpMe.blogspot.com

                  1 Reply Last reply
                  0
                  • A AshenFlowersFalling

                    Came across this piece of solid-gold coding in Android the other day, in good old SurfaceFlinger.cpp:

                    if (mCurrentState.orientation != orientation) {
                    if (uint32_t(orientation)<=eOrientation270 || orientation==42) {
                    mCurrentState.orientationType = flags;
                    mCurrentState.orientation = orientation;
                    setTransactionFlags(eTransactionNeeded);
                    mTransactionCV.wait(mStateLock);
                    } else {
                    orientation = BAD_VALUE;
                    }
                    }

                    Sometimes I just don't know what to think any more. :D

                    +++DIVIDE BY CUCUMBER ERROR+++

                    A Offline
                    A Offline
                    Andrei Straut
                    wrote on last edited by
                    #16

                    Well, just hold your phone at 42 degrees :-D. And also, there were worse f'ups: (Steve Jobs "Don't hold it that way", anyone?) Actually, there were none :confused:

                    1 Reply Last reply
                    0
                    • Y YvesDaoust

                      A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                      if (i < 0)
                      return 1 - abs(i);
                      else if (i == 0)
                      return 1;
                      else if (i > 0)
                      return 1 + abs(i);

                      (with the added benefit that out-of-range values are left unchanged)

                      A Offline
                      A Offline
                      ASkoro
                      wrote on last edited by
                      #17

                      Hey but what about i being sqrt(2)???

                      Y 1 Reply Last reply
                      0
                      • Y YvesDaoust

                        A nice piece indeed. Here is a slightly more defensive version that makes sure the sign is properly handled:

                        if (i < 0)
                        return 1 - abs(i);
                        else if (i == 0)
                        return 1;
                        else if (i > 0)
                        return 1 + abs(i);

                        (with the added benefit that out-of-range values are left unchanged)

                        S Offline
                        S Offline
                        sergiogarcianinja
                        wrote on last edited by
                        #18

                        I just tried your method, and my compiler is generating a error about a method must return a value, so I fixed it. There is a version without bugs, hope it helps:

                        if (i < 0)
                        return 1 - abs(i);
                        else if (i == 0)
                        return 1;
                        else if (i > 0)
                        return 1 + abs(i);

                        K 1 Reply Last reply
                        0
                        • R Rotted Frog

                          Just a quick one, but amused me when I saw it in code today.

                          if (i == 0)
                          return 1;
                          else
                          return i + 1;

                          S Offline
                          S Offline
                          sergiogarcianinja
                          wrote on last edited by
                          #19

                          I a very humble opinion, I think the original developer cared about performance. There is a big and ugly monster living in or closes that will eat us if we write less performing code. The problem is, that almost all developers don't understand about performance and do wrong things. Here, I think he/she are trying to avoid a sum using a comparison. In some cases, like division, it will be a great code.

                          1 Reply Last reply
                          0
                          • A ASkoro

                            Hey but what about i being sqrt(2)???

                            Y Offline
                            Y Offline
                            YvesDaoust
                            wrote on last edited by
                            #20

                            Function will return sqrt(2) + 1

                            A 1 Reply Last reply
                            0
                            • Y YvesDaoust

                              Function will return sqrt(2) + 1

                              A Offline
                              A Offline
                              ASkoro
                              wrote on last edited by
                              #21

                              And for sqrt(-2)????

                              Y M K 3 Replies Last reply
                              0
                              • A ASkoro

                                And for sqrt(-2)????

                                Y Offline
                                Y Offline
                                YvesDaoust
                                wrote on last edited by
                                #22

                                SquareRootException + 1

                                1 Reply Last reply
                                0
                                • R Rotted Frog

                                  Just a quick one, but amused me when I saw it in code today.

                                  if (i == 0)
                                  return 1;
                                  else
                                  return i + 1;

                                  L Offline
                                  L Offline
                                  Lost User
                                  wrote on last edited by
                                  #23

                                  For the sake of learning here, why do some of the examples use the abs function in their answers. Why not just i++?

                                  T P K B 4 Replies Last reply
                                  0
                                  • L Lost User

                                    For the sake of learning here, why do some of the examples use the abs function in their answers. Why not just i++?

                                    T Offline
                                    T Offline
                                    thoiness
                                    wrote on last edited by
                                    #24

                                    Rewritten:

                                    return (i == 0) ? 1 : i++;

                                    In division, specifically in the denominator, this code eliminates the divide by zero issue. I think the OP (original programmer) had good intentions.

                                    O 1 Reply Last reply
                                    0
                                    • L Lost User

                                      For the sake of learning here, why do some of the examples use the abs function in their answers. Why not just i++?

                                      P Offline
                                      P Offline
                                      patbob
                                      wrote on last edited by
                                      #25

                                      Why not use i++? Obfuscation. The original coder was trying to obfuscate it by using an if statement, so people are running with that theme :)

                                      We can program with only 1's, but if all you've got are zeros, you've got nothing.

                                      1 Reply Last reply
                                      0
                                      • A ASkoro

                                        And for sqrt(-2)????

                                        M Offline
                                        M Offline
                                        Member 4608898
                                        wrote on last edited by
                                        #26

                                        And for sqrt(-1/64) do we get indigestion tablets?

                                        1 Reply Last reply
                                        0
                                        • T thoiness

                                          Rewritten:

                                          return (i == 0) ? 1 : i++;

                                          In division, specifically in the denominator, this code eliminates the divide by zero issue. I think the OP (original programmer) had good intentions.

                                          O Offline
                                          O Offline
                                          Oscar0
                                          wrote on last edited by
                                          #27

                                          Bug Alert. I think you meant perhaps: return (i == 0) ? 1 : ++i;

                                          1 Reply Last reply
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