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What the NaN?

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  • Sander RosselS Sander Rossel

    I got it from simply running the following code in C#... :~

    double a = 1;
    double b = 0;
    double c = a / b; // c is now double.Infinity

    I'm seeing the result is Infinity right here on my screen and you telling me it isn't and never was :confused:

    Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

    Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

    Regards, Sander

    L Offline
    L Offline
    Lost User
    wrote on last edited by
    #54

    That's just a C# fudge. Mathematically that is not correct.

    T 1 Reply Last reply
    0
    • Sander RosselS Sander Rossel

      0/0 should throw a DivideByZeroException (which it does for integers). And apparently 1/0 equals infinity. Now what is it? NaN, infinity or just plain not possible? Doesn't it sound weird (and, indeed, very wrong) that a NUMERIC type has a value "NOT A NUMBER"!? Anyway, when I said "why would there even be a NaN anyway" I was referring to NaN in actual real life business cases that make sense and have practical use :)

      Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

      Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

      Regards, Sander

      M Offline
      M Offline
      Manfred Rudolf Bihy
      wrote on last edited by
      #55

      1/0 is NOT infinity! I know you've already stated you're weak at maths, but try to do some basic research before posting non sense like that! 1/x with x -> 0 that is something completely different though! X| OK, I know I'm arguing with an idiot who actually thinks infinity is a number!

      "I had the right to remain silent, but I didn't have the ability!"

      Ron White, Comedian

      Sander RosselS 1 Reply Last reply
      0
      • M Manfred Rudolf Bihy

        1/0 is NOT infinity! I know you've already stated you're weak at maths, but try to do some basic research before posting non sense like that! 1/x with x -> 0 that is something completely different though! X| OK, I know I'm arguing with an idiot who actually thinks infinity is a number!

        "I had the right to remain silent, but I didn't have the ability!"

        Ron White, Comedian

        Sander RosselS Offline
        Sander RosselS Offline
        Sander Rossel
        wrote on last edited by
        #56

        I KNOW 1/0 is nonsense and not infinity, but try telling that to C#[^]! X| Then again 1/0 is also not NaN, it's just bogus and an Exception is the only correct outcome, but say that and people go all IEEE on your ass! X|

        Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

        Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

        Regards, Sander

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        • Sander RosselS Sander Rossel

          I'm writing the function that will be called by users that didn't check their input. At least I should know how to handle their crap :)

          Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

          Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

          Regards, Sander

          D Offline
          D Offline
          den2k88
          wrote on last edited by
          #57

          Remember that not only the users can insert unacceptable values but that other parts of your code can produce them. Either you're 100% sure that to some point in your code the values are all ammissible or you check them, or you document that the values must be checked beforehand. For example I made some extrafast buffer rotation procedures in Assembler (we needed them) and they crash if the number of columns is not a multiple of 64. Since checking each time the function is called would lower the extra speed it is clearly documented to make sure the buffers are allocated in 64 colums multiples. Otherwise I should check them.

          GCS d--- s-/++ a- C++++ U+++ P- L- E-- W++ N++ o+ K- w+++ O? M-- V? PS+ PE- Y+ PGP t++ 5? X R++ tv-- b+ DI+++ D++ G e++>+++ h--- ++>+++ y+++*      Weapons extension: ma- k++ F+2 X If you think 'goto' is evil, try writing an Assembly program without JMP. -- TNCaver When I was six, there were no ones and zeroes - only zeroes. And not all of them worked. -- Ravi Bhavnani

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          • L Lost User

            That's just a C# fudge. Mathematically that is not correct.

            T Offline
            T Offline
            Theraot
            wrote on last edited by
            #58

            It is not just a C#, it is IEEE 754 And this is how you represented:

            7ff0 0000 0000 000016 = Infinity
            fff0 0000 0000 000016 = −Infinity
            7fff ffff ffff ffff16 = NaN

            Those first 12 bits correspond to the sign and exponent, and the values 7ff and fff are reserved constants with special meaning. Why? I don't freaking know, I didn't invent IEEE 754. But anywhere you find double it is like that because it is standard, and it is even implemented in the CPU. It is very easy to show it is not C#, see this JSFiddle[^]. Does it make mathematical sense? No. A number system that has a representation for not-a-number makes no sense. --- Although I can argue that a number system with 1/0 = Infinity is possible, it would be a two-point compactification[^] of the real numbers to include -Infinity and Infinity*. Another system with 1/0 = Infinity is the Rieammn Sphere**, but that number system has only one Infinity and include the complex numbers. *: To be clear, that means that you create a topological space where the infinite number line is embedded by a projection in a finite segment. Then the points at the extremes of the segment can't ever be reached, there is no real number low or high enough to reach those points. Then you label then "-Infinity" on the negative side and "Infinity" on the positive side. Clearly those points aren't real numbers, and they break traditional algebra, but they are numbers. Why would you want them? I don't know. **: But I know for the Riemman Spehre, you can extend the real numbers to add the complex infinity point. This is embedding the complex plane in the surface of a unit sphere, such that the opposite point from 0 is never reached by any complex number. Then you label that point "Complex Infinity". Then you go to say that 1/0 = Complex Infinity, and 1 / Complex Infinity = 0 - now you can divide by infinity and solve integrations the old way. Yet, it also breaks algebra. Of course, this is problematic, and mathematicians left the idea in favor of Limits. The modern well-behaved solution (that doesn’t break algebra) is Hyperreals.

            H L Sander RosselS 4 Replies Last reply
            0
            • T Theraot

              It is not just a C#, it is IEEE 754 And this is how you represented:

              7ff0 0000 0000 000016 = Infinity
              fff0 0000 0000 000016 = −Infinity
              7fff ffff ffff ffff16 = NaN

              Those first 12 bits correspond to the sign and exponent, and the values 7ff and fff are reserved constants with special meaning. Why? I don't freaking know, I didn't invent IEEE 754. But anywhere you find double it is like that because it is standard, and it is even implemented in the CPU. It is very easy to show it is not C#, see this JSFiddle[^]. Does it make mathematical sense? No. A number system that has a representation for not-a-number makes no sense. --- Although I can argue that a number system with 1/0 = Infinity is possible, it would be a two-point compactification[^] of the real numbers to include -Infinity and Infinity*. Another system with 1/0 = Infinity is the Rieammn Sphere**, but that number system has only one Infinity and include the complex numbers. *: To be clear, that means that you create a topological space where the infinite number line is embedded by a projection in a finite segment. Then the points at the extremes of the segment can't ever be reached, there is no real number low or high enough to reach those points. Then you label then "-Infinity" on the negative side and "Infinity" on the positive side. Clearly those points aren't real numbers, and they break traditional algebra, but they are numbers. Why would you want them? I don't know. **: But I know for the Riemman Spehre, you can extend the real numbers to add the complex infinity point. This is embedding the complex plane in the surface of a unit sphere, such that the opposite point from 0 is never reached by any complex number. Then you label that point "Complex Infinity". Then you go to say that 1/0 = Complex Infinity, and 1 / Complex Infinity = 0 - now you can divide by infinity and solve integrations the old way. Yet, it also breaks algebra. Of course, this is problematic, and mathematicians left the idea in favor of Limits. The modern well-behaved solution (that doesn’t break algebra) is Hyperreals.

              H Offline
              H Offline
              Herbie Mountjoy
              wrote on last edited by
              #59

              This is fun. So what is the value of the interval between -infinity and infinity? Tee hee...

              We're philosophical about power outages here. A.C. come, A.C. go.

              1 Reply Last reply
              0
              • T Theraot

                It is not just a C#, it is IEEE 754 And this is how you represented:

                7ff0 0000 0000 000016 = Infinity
                fff0 0000 0000 000016 = −Infinity
                7fff ffff ffff ffff16 = NaN

                Those first 12 bits correspond to the sign and exponent, and the values 7ff and fff are reserved constants with special meaning. Why? I don't freaking know, I didn't invent IEEE 754. But anywhere you find double it is like that because it is standard, and it is even implemented in the CPU. It is very easy to show it is not C#, see this JSFiddle[^]. Does it make mathematical sense? No. A number system that has a representation for not-a-number makes no sense. --- Although I can argue that a number system with 1/0 = Infinity is possible, it would be a two-point compactification[^] of the real numbers to include -Infinity and Infinity*. Another system with 1/0 = Infinity is the Rieammn Sphere**, but that number system has only one Infinity and include the complex numbers. *: To be clear, that means that you create a topological space where the infinite number line is embedded by a projection in a finite segment. Then the points at the extremes of the segment can't ever be reached, there is no real number low or high enough to reach those points. Then you label then "-Infinity" on the negative side and "Infinity" on the positive side. Clearly those points aren't real numbers, and they break traditional algebra, but they are numbers. Why would you want them? I don't know. **: But I know for the Riemman Spehre, you can extend the real numbers to add the complex infinity point. This is embedding the complex plane in the surface of a unit sphere, such that the opposite point from 0 is never reached by any complex number. Then you label that point "Complex Infinity". Then you go to say that 1/0 = Complex Infinity, and 1 / Complex Infinity = 0 - now you can divide by infinity and solve integrations the old way. Yet, it also breaks algebra. Of course, this is problematic, and mathematicians left the idea in favor of Limits. The modern well-behaved solution (that doesn’t break algebra) is Hyperreals.

                L Offline
                L Offline
                Lost User
                wrote on last edited by
                #60

                The more I read on this subject, the more I regret not doing advanced maths when I was at school.

                1 Reply Last reply
                0
                • L Lost User

                  Sander Rossel wrote:

                  .NET (and I guess IEEE) represents 1 / 0 as Infinity

                  No, it does not, where on earth did you get this idea from? How exactly do you represent infinity as a number in a computer?

                  F Offline
                  F Offline
                  Fly Gheorghe
                  wrote on last edited by
                  #61

                  This is how you represent infinity in a computer: a) For simple precision (32 bits), set sign = 0/1, mantis = 0x7FFFFF, exponent = 0xFF, and you get +/-INF. b) Similar for double and extended precision. This is how you set a NaN in simple precision: Any number except +/-INF above, that has exponent = 0 or 0xFF is a NaN. Gheorghe

                  L 1 Reply Last reply
                  0
                  • L Lost User

                    NaN means Not a Number, so you cannot compare it to a proper number and get a valid response.

                    S Offline
                    S Offline
                    StatementTerminator
                    wrote on last edited by
                    #62

                    More to the point, infinity is not a number.

                    1 Reply Last reply
                    0
                    • T Theraot

                      It is not just a C#, it is IEEE 754 And this is how you represented:

                      7ff0 0000 0000 000016 = Infinity
                      fff0 0000 0000 000016 = −Infinity
                      7fff ffff ffff ffff16 = NaN

                      Those first 12 bits correspond to the sign and exponent, and the values 7ff and fff are reserved constants with special meaning. Why? I don't freaking know, I didn't invent IEEE 754. But anywhere you find double it is like that because it is standard, and it is even implemented in the CPU. It is very easy to show it is not C#, see this JSFiddle[^]. Does it make mathematical sense? No. A number system that has a representation for not-a-number makes no sense. --- Although I can argue that a number system with 1/0 = Infinity is possible, it would be a two-point compactification[^] of the real numbers to include -Infinity and Infinity*. Another system with 1/0 = Infinity is the Rieammn Sphere**, but that number system has only one Infinity and include the complex numbers. *: To be clear, that means that you create a topological space where the infinite number line is embedded by a projection in a finite segment. Then the points at the extremes of the segment can't ever be reached, there is no real number low or high enough to reach those points. Then you label then "-Infinity" on the negative side and "Infinity" on the positive side. Clearly those points aren't real numbers, and they break traditional algebra, but they are numbers. Why would you want them? I don't know. **: But I know for the Riemman Spehre, you can extend the real numbers to add the complex infinity point. This is embedding the complex plane in the surface of a unit sphere, such that the opposite point from 0 is never reached by any complex number. Then you label that point "Complex Infinity". Then you go to say that 1/0 = Complex Infinity, and 1 / Complex Infinity = 0 - now you can divide by infinity and solve integrations the old way. Yet, it also breaks algebra. Of course, this is problematic, and mathematicians left the idea in favor of Limits. The modern well-behaved solution (that doesn’t break algebra) is Hyperreals.

                      L Offline
                      L Offline
                      Lost User
                      wrote on last edited by
                      #63

                      See The Lounge[^].

                      1 Reply Last reply
                      0
                      • F Fly Gheorghe

                        This is how you represent infinity in a computer: a) For simple precision (32 bits), set sign = 0/1, mantis = 0x7FFFFF, exponent = 0xFF, and you get +/-INF. b) Similar for double and extended precision. This is how you set a NaN in simple precision: Any number except +/-INF above, that has exponent = 0 or 0xFF is a NaN. Gheorghe

                        L Offline
                        L Offline
                        Lost User
                        wrote on last edited by
                        #64

                        See The Lounge[^].

                        1 Reply Last reply
                        0
                        • T Theraot

                          It is not just a C#, it is IEEE 754 And this is how you represented:

                          7ff0 0000 0000 000016 = Infinity
                          fff0 0000 0000 000016 = −Infinity
                          7fff ffff ffff ffff16 = NaN

                          Those first 12 bits correspond to the sign and exponent, and the values 7ff and fff are reserved constants with special meaning. Why? I don't freaking know, I didn't invent IEEE 754. But anywhere you find double it is like that because it is standard, and it is even implemented in the CPU. It is very easy to show it is not C#, see this JSFiddle[^]. Does it make mathematical sense? No. A number system that has a representation for not-a-number makes no sense. --- Although I can argue that a number system with 1/0 = Infinity is possible, it would be a two-point compactification[^] of the real numbers to include -Infinity and Infinity*. Another system with 1/0 = Infinity is the Rieammn Sphere**, but that number system has only one Infinity and include the complex numbers. *: To be clear, that means that you create a topological space where the infinite number line is embedded by a projection in a finite segment. Then the points at the extremes of the segment can't ever be reached, there is no real number low or high enough to reach those points. Then you label then "-Infinity" on the negative side and "Infinity" on the positive side. Clearly those points aren't real numbers, and they break traditional algebra, but they are numbers. Why would you want them? I don't know. **: But I know for the Riemman Spehre, you can extend the real numbers to add the complex infinity point. This is embedding the complex plane in the surface of a unit sphere, such that the opposite point from 0 is never reached by any complex number. Then you label that point "Complex Infinity". Then you go to say that 1/0 = Complex Infinity, and 1 / Complex Infinity = 0 - now you can divide by infinity and solve integrations the old way. Yet, it also breaks algebra. Of course, this is problematic, and mathematicians left the idea in favor of Limits. The modern well-behaved solution (that doesn’t break algebra) is Hyperreals.

                          Sander RosselS Offline
                          Sander RosselS Offline
                          Sander Rossel
                          wrote on last edited by
                          #65

                          Theraot wrote:

                          A number system that has a representation for not-a-number makes no sense.

                          Thank you! :thumbsup: :D

                          Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

                          Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

                          Regards, Sander

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                          • Sander RosselS Sander Rossel

                            var result = new[] { 1, double.PositiveInfinity, double.NegativeInfinity, double.NaN }.Max(); // Infinity
                            var result = new[] { 1, double.PositiveInfinity, double.NegativeInfinity, double.NaN }.Min(); // NaN
                            var isNaNSmaller = double.NaN < 1; // false

                            So NaN is not the biggest value, it's still bigger than one, but it's also the smallest value. I hate to sound infinitely negative, but that's messed up :wtf:

                            Read my (free) ebook Object-Oriented Programming in C# Succinctly. Visit my blog at Sander's bits - Writing the code you need. Or read my articles here on CodeProject.

                            Simplicity is prerequisite for reliability. — Edsger W. Dijkstra

                            Regards, Sander

                            D Offline
                            D Offline
                            Daniel Pfeffer
                            wrote on last edited by
                            #66

                            IIRC, IEEE Std 754-2008 does define a set of recommended functions, including min() and max() of a vector of numbers. C# still uses IEEE Std 754-1985, so they have their own, quirky, handing of min() and max().

                            If you have an important point to make, don't try to be subtle or clever. Use a pile driver. Hit the point once. Then come back and hit it again. Then hit it a third time - a tremendous whack. --Winston Churchill

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