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  3. Why does most C/C++ developer prefers char *c instead of char* c?

Why does most C/C++ developer prefers char *c instead of char* c?

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  • L Lost User

    cant be a type modifier either, char *c --> * means pointer, "char" is is the default 'pointed to' modifier for that declaration. In the language definition it's valid to cast a * to address any [other] type. If the type was considered "char*" or in fact if "char" had anything to do with 'the type' then casting pointers to address other type would become wrong. hence:

    char* c" /* is wrong, "char*" is NOT the type because there is no such thing, it's wrong, plain wrong! */
    char *c /* is the proper form */

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    Lost User
    wrote on last edited by
    #8

    Can be, it is anyway a more philosophical Thing. In case char* is plain wrong it should not be allowed to do this: typedef char* myCharPtr; :-D

    It does not solve my Problem, but it answers my question

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    • L Lost User

      I would say "*" is a type modifier :-D [Edit]

      Quote:

      In C "char *" is not a type

      Really? Ok I don't know C, but I think this is also allowed in C typedef char@ theCharPointerType; @ instead of *, because * seems to be a Problem in cp And if the above is ok in C, how can you state that a pointer to char is not a type?

      It does not solve my Problem, but it answers my question

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      Lost User
      wrote on last edited by
      #9

      Lopatir is correct. The way to read the declaration

      char *c

      is: c (the name of the variable) is a pointer (the * prefix) to a character (the type) where the pointer property actually belongs to the variable, not the type. Having said that I always write:

      char* c

      ;)

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      • L Lost User

        Lopatir is correct. The way to read the declaration

        char *c

        is: c (the name of the variable) is a pointer (the * prefix) to a character (the type) where the pointer property actually belongs to the variable, not the type. Having said that I always write:

        char* c

        ;)

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        Lost User
        wrote on last edited by
        #10

        How the hell you can break such a rule? Please refracte (does this word really exists?) all your source code ...please!!! :laugh: [Edit] Btw, I don't think Lopidar is right. Started with Modula and read a lot from "Niklaus Wirth" theories, also I did a lot of Compiler implementations ;)

        It does not solve my Problem, but it answers my question

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        • L Lost User

          How the hell you can break such a rule? Please refracte (does this word really exists?) all your source code ...please!!! :laugh: [Edit] Btw, I don't think Lopidar is right. Started with Modula and read a lot from "Niklaus Wirth" theories, also I did a lot of Compiler implementations ;)

          It does not solve my Problem, but it answers my question

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          Lost User
          wrote on last edited by
          #11

          0x01AA wrote:

          Please refracte

          The correct word would be "refactor". But at my age I may not have enough time to get it all done. :((

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          • L Lost User

            0x01AA wrote:

            Please refracte

            The correct word would be "refactor". But at my age I may not have enough time to get it all done. :((

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            Lost User
            wrote on last edited by
            #12

            So I Need to write: Do refactor your code?

            Quote:

            But at my age I may not have enough time to get it all done

            Stop thinking like this!! You have all the time

            It does not solve my Problem, but it answers my question

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            • J jpg 0

              char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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              jschell
              wrote on last edited by
              #13

              I prefer "char* c". Long ago I used the other form but an article I read long ago convinced me that the 'type' should be emphasized as different from the variable.

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              • J jpg 0

                char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                PIEBALDconsult
                wrote on last edited by
                #14

                To remind users that char* a , b may not do what they intend.

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                • J jpg 0

                  char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                  Chris Maunder
                  wrote on last edited by
                  #15

                  the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using the type. You're not, as it were, modifying the type.

                  cheers Chris Maunder

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                  • J jschell

                    I prefer "char* c". Long ago I used the other form but an article I read long ago convinced me that the 'type' should be emphasized as different from the variable.

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                    Lost User
                    wrote on last edited by
                    #16

                    how do you do: "char c[]" ?? "char[] c" wont compile, so that "type/name" logic is already broken for C/C++. The article you read was written by someone that either referred to a different programming language, or doesn't understand the C/C++ language definitions; char* is not a type in C/C++. For real fun, have you considered "char *c[]" ... writing that the wrong way as "char* c[]" obviously looks, reads and is just plain wrong because that would read as an "array of pointers" when what I wanted was a "pointer to an array." Personal style is OK, but justifying it as proper with a mistake isn't. In short: if you prefer the look of "char* c" carry on, just remember it's a pointer, not a type.

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                    • C Chris Maunder

                      the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using the type. You're not, as it were, modifying the type.

                      cheers Chris Maunder

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                      Lost User
                      wrote on last edited by
                      #17

                      Chris Maunder wrote:

                      the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using accessing the type value. You're not, as it were, modifying the type.

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                      • J jpg 0

                        char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                        Jon McKee
                        wrote on last edited by
                        #18

                        I've always liked option 3: char * c. It avoids the problems char* c, d; can cause but still keeps it separate from the name. * is just like const or any other modifier. You wouldn't write constchar* c so why mash them together just because it's a single character (and allowed)?

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                        • L Lost User

                          Chris Maunder wrote:

                          the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using accessing the type value. You're not, as it were, modifying the type.

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                          Chris Maunder
                          wrote on last edited by
                          #19

                          OK, fair enough.

                          cheers Chris Maunder

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                          • P PIEBALDconsult

                            To remind users that char* a , b may not do what they intend.

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                            CPallini
                            wrote on last edited by
                            #20

                            Exactly.

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                            • J jpg 0

                              char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                              JesperMadsen123
                              wrote on last edited by
                              #21

                              When doing more than one variable declaration makes sense to put the * correctly, or you do not get what you expect. When writing: char* a,b,c; you get the equivalent of: char *a,b,c; and you would probably expect: char *a,*b,*c;

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                              • J jpg 0

                                char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                                Grand Chain
                                wrote on last edited by
                                #22

                                Because that's how the compiler parses it. The * binds to the variable not the type. Think about char* a, b; This suggests that b is also a char *, but actually it is only a char. Much clearer when you write char *a, b; (Not that I would advocate doing either - even better to have two separate declarations - but it illustrates the point).

                                Ian Brockbank "Legacy systems are systems that are not protected with a suite of tests. ... You are building legacy code every time you build software without associated tests." - Mary and Tom Poppendieck, Implementing Lean Software Development.

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                                • J jpg 0

                                  char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                                  Jonas Hammarberg
                                  wrote on last edited by
                                  #23

                                  If you always puts your declarations on separate lines (or separated by ';') it doesn't matter. But if you do -- be aware. Say that you have; char* c; char* d; char* e; and, for some reason, probably even a good one, decides to put them on one line ... in a bit of hurry so that you ends up with; char* c,d,e; But if you had char *c; char *d; char *e; there is a pretty good chance you would end up with; char *c, *d, *e; This is also the reason for the typedef's of pointers, eg. typedef char * char_p; char_p c; char_p d; char_p e; would be char_p c, d, e; rgds /Jonas ps. char* c, d, e; --> char* c; char d; char e;

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                                  • L Lost User

                                    Chris Maunder wrote:

                                    the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using accessing the type value. You're not, as it were, modifying the type.

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                                    User 9629458
                                    wrote on last edited by
                                    #24

                                    Great answer. When I define a pointer I'm using `char *p;` because this is pointer. It stores an address and points a `char` value in this address. So, '*' is serving as a pointing device for (p) address register, (I think) it must be declared with address register.

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                                    • C Chris Maunder

                                      the variable is the type, and the type stays the type. The * goes with the variable because you're modifying defining how the variable will be using the type. You're not, as it were, modifying the type.

                                      cheers Chris Maunder

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                                      User 9629458
                                      wrote on last edited by
                                      #25

                                      Great answer. When I define a pointer I'm using char *p; because this is pointer. It stores an address and points a char value in this address. So, '*' is serving as a pointing device for p address register, (I think) it must be declared with address register.

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                                      • J Jonas Hammarberg

                                        If you always puts your declarations on separate lines (or separated by ';') it doesn't matter. But if you do -- be aware. Say that you have; char* c; char* d; char* e; and, for some reason, probably even a good one, decides to put them on one line ... in a bit of hurry so that you ends up with; char* c,d,e; But if you had char *c; char *d; char *e; there is a pretty good chance you would end up with; char *c, *d, *e; This is also the reason for the typedef's of pointers, eg. typedef char * char_p; char_p c; char_p d; char_p e; would be char_p c, d, e; rgds /Jonas ps. char* c, d, e; --> char* c; char d; char e;

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                                        SawDid
                                        wrote on last edited by
                                        #26

                                        Bring back ALGOL 68

                                        K 1 Reply Last reply
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                                        • J jpg 0

                                          char is a type and c is a name, to me, it always make more sense to put the name alone and have the type together, like "char* c", I can tell immediately that it is a pointer to a char, so its always goes like [type] [name]. But in contrast, most C/C++ code I found prefer the other way around, like "char *c". Is there any specific reasons why this is so?

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                                          Bob1000
                                          wrote on last edited by
                                          #27

                                          Simple Its C that is the pointer not the char. So char *c makes more sense Or read it in reverse (a standard way to understand C/C++) C is a pointer to char It also looks nicer!

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