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  3. In C#: double d = 0.4 - 1.2; What is d?

In C#: double d = 0.4 - 1.2; What is d?

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  • I Ivor S Sargoytchev

    Well? What is d equal to? Ivor S. Sargoytchev Dundas Software

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    Navin
    wrote on last edited by
    #20

    Ivor S. Sargoytchev wrote: Dundas Software THe only way you're going to get an answer in this crowd, when posting in the Lounge, is if you offer to hook us up with those women from the Summer Sale ads. :-D "When a man sits with a pretty girl for an hour, it seems like a minute. But let him sit on a hot stove for a minute and it's longer than any hour. That's relativity." - Albert Einstein

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    • I Ivor S Sargoytchev

      Daniel, This is not true. Double.Epsilon is a very very very small number: Double.Epsilon = 4.94065645841247E-324 But in C# I get 0.4 - 1.2 = -0.79999999999999993. As you can see the deviation from -0.8 is hundreds of times bugger than 4.94065645841247E-324. Ivor S. Sargoytchev Dundas Software

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      Rodolfo Lima
      wrote on last edited by
      #21

      I think that what he meant was something like: if(abs(0.4-1.2)-0.8) < Double.Epsilon) which is the proper way to compare floating point numbers, i guess.

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      • N Navin

        Ivor S. Sargoytchev wrote: Dundas Software THe only way you're going to get an answer in this crowd, when posting in the Lounge, is if you offer to hook us up with those women from the Summer Sale ads. :-D "When a man sits with a pretty girl for an hour, it seems like a minute. But let him sit on a hot stove for a minute and it's longer than any hour. That's relativity." - Albert Einstein

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        John M Drescher
        wrote on last edited by
        #22

        I agree.. :):laugh: John

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        • R Rodolfo Lima

          I think that what he meant was something like: if(abs(0.4-1.2)-0.8) < Double.Epsilon) which is the proper way to compare floating point numbers, i guess.

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          Ivor S Sargoytchev
          wrote on last edited by
          #23

          This cannot be true since the absolute value of ((0.4 - 1.2) + 0.8) is 0.00000000000000011102230246251565. The value of Double.Epsilon is 4.94065645841247E-324, which is much much smaller.

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          • M Michael Dunn

            Chris Maunder wrote: 2.0 == 4.0 * 0.5 Won't that actually be true because all those numbers are powers of 2? :cool: --Mike-- Ericahist | Homepage | RightClick-Encrypt | 1ClickPicGrabber Latest art~!@#2rDFA#@(#*%$Rfa39f3fqwf--= NO CARRIER

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            Ryan Binns
            wrote on last edited by
            #24

            Michael Dunn wrote: Won't that actually be true because all those numbers are powers of 2? Yeah it will. Not a good choice of numbers huh? :)

            Ryan

            "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

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            • C Chris Maunder

              The value represented in a floating point variable is only an approximation to a value, not an exact representation. Because of this you cannot assume that something like 2.0 == 4.0 * 0.5 will return true. When comparing floating point values you need to estimate how close is close enough then do a fuzzy comparision (something like ABS(A-B) < Epsilon) cheers, Chris Maunder

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              Ivor S Sargoytchev
              wrote on last edited by
              #25

              So Epsilon should be some value that you pick up, not Double.Epsilon as some people suggested, right? P.S. Chris, I know you are not supposed to compare 2 doubles with equality test. I was making a point that the result was not -0.8 as a response to leppie who wrote: "Thru a microscope, everything looks big. Believe me that is -0.8. Try Console.Write()." So, I accept your apology.:) Ivor S. Sargoytchev Dundas Software

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              • I Ivor S Sargoytchev

                Well? What is d equal to? Ivor S. Sargoytchev Dundas Software

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                igor1960
                wrote on last edited by
                #26

                I understand that this thread is not serious about anything, but very valid point has been raised. I would give you an answer: nobody knows... until native code is created. During days when C ruled you could heave an option of switching on/off coprocessor, floating point emulator library and etc. So, you can adjust precissions and etc... Now, looks like JIT should be creating best possible code depending on your computer configuration: what exactly does that mean for floating point case -- I didn't figure out yet. But yes, they will be alot of knowledgeable people on this thread willing to answer -- no doubt... "...Ability to type is not enough to become a Programmer. Unless you type in VB. But then again you have to type really fast..." Me

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                • I Ivor S Sargoytchev

                  Well? What is d equal to? Ivor S. Sargoytchev Dundas Software

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                  Maxwell Chen
                  wrote on last edited by
                  #27

                  In Visual C++ 6.0, d = -0.80000004172325 ;P BuggyMax

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                  • I Ivor S Sargoytchev

                    So Epsilon should be some value that you pick up, not Double.Epsilon as some people suggested, right? P.S. Chris, I know you are not supposed to compare 2 doubles with equality test. I was making a point that the result was not -0.8 as a response to leppie who wrote: "Thru a microscope, everything looks big. Believe me that is -0.8. Try Console.Write()." So, I accept your apology.:) Ivor S. Sargoytchev Dundas Software

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                    Nick Parker
                    wrote on last edited by
                    #28

                    Ivor S. Sargoytchev wrote: So Epsilon should be some value that you pick up, not Double.Epsilon as some people suggested, right? Nope, check your local MSDN documentation on the Double.Epsilon Field. .NET Documentation wrote: For example, the C# expression, (double)1/3 == (double)0.33333, does not compare equal because the division operation on the left-hand side has maximum precision while the constant on the right-hand side is only precise to the visible digits. Instead, determine if the two sides of a comparison are close enough to equal for your purposes by comparing whether the absolute value of the difference between the left and right-hand sides is less than Epsilon. -Nick Parker

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                    • I Ivor S Sargoytchev

                      Well? What is d equal to? Ivor S. Sargoytchev Dundas Software

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                      Stephane Rodriguez
                      wrote on last edited by
                      #29

                      Ok, so MS has still problem defining a simple and safe addition/substract operation on floating points. Nice. Now that's high-tech. Where is the Accessories / calculator SDK when I need it ? :laugh: Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

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                      • N Nemanja Trifunovic

                        Hehehe, I ran into this problem 15 years ago while writing a Fortran program.

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                        Olli
                        wrote on last edited by
                        #30

                        Nemanja Trifunovic wrote: Hehehe, I ran into this problem 15 years ago while writing a Fortran program. AAAAAAAAAAAAAAAAARRRRRRRRRRRRRRRGHHHHHHHHH You made my old trauma come back.... Fortrandoubleintc++verystrangehelpfirstclass :wtf::wtf::wtf::wtf::omg::omg:

                        Olli "Ooooooh, they have the internet on computers now!"
                        Homer Simpson
                        :beer: + :java: = NULL :=> X|

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                        • M Maxwell Chen

                          In Visual C++ 6.0, d = -0.80000004172325 ;P BuggyMax

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                          Brit
                          wrote on last edited by
                          #31

                          BuggyMax wrote: In Visual C++ 6.0, d = -0.80000004172325 How'd you come up with that answer? Because I came up with a different number with Visual Studio 6.0: -0.79999999999999993 BTW, you'd better not say that you did "d += 0.8" and then looked at the value in the debugger. ------------------------------------------ The ousted but stubbornly non-dead leader reportedly released an audiotape this weekend, ending by calling on Iraqis to, quote, "resist the occupation in any way you can, from writing on walls, to boycotting, to demonstrating and taking up arms." adding, "you know, pretty much anything I used to kill you for."

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                          • B Brit

                            BuggyMax wrote: In Visual C++ 6.0, d = -0.80000004172325 How'd you come up with that answer? Because I came up with a different number with Visual Studio 6.0: -0.79999999999999993 BTW, you'd better not say that you did "d += 0.8" and then looked at the value in the debugger. ------------------------------------------ The ousted but stubbornly non-dead leader reportedly released an audiotape this weekend, ending by calling on Iraqis to, quote, "resist the occupation in any way you can, from writing on walls, to boycotting, to demonstrating and taking up arms." adding, "you know, pretty much anything I used to kill you for."

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                            Maxwell Chen
                            wrote on last edited by
                            #32

                            Ooooops! I used this: double d = 0.4F - 1.2F; And the result is wrong (d = -0.800000041723251) because casting float to double. This time I use this with VC++ 6: double d = 0.4 - 1.2; And I got the output message for printf("d = %.15f\n", d); is d = -0.800000000000000 But I still got negative result ("No") in the comparison:

                            if(d == -0.8)
                            std::cout << "Yes\n";
                            else
                            std::cout << "No\n";

                            BuggyMax

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                            • I Ivor S Sargoytchev

                              I guess I should use decimals. Ivor S. Sargoytchev Dundas Software

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                              realJSOP
                              wrote on last edited by
                              #33

                              No, you should be a programmer and write a function called "AlmostEqual" which will compare two floating point numbers asstrings out to a programmer-specified number of positions to the right of the decimal point. I had to do that when I was programming in Pascal over 15 years ago. ------- signature starts "...the staggering layers of obscenity in your statement make it a work of art on so many levels." - Jason Jystad, 10/26/2001 "You won't like me when I'm angry..." - Dr. Bruce Banner Please review the Legal Disclaimer in my bio. ------- signature ends

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                              • S Stephane Rodriguez

                                Ok, so MS has still problem defining a simple and safe addition/substract operation on floating points. Nice. Now that's high-tech. Where is the Accessories / calculator SDK when I need it ? :laugh: Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

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                                Chris Meech
                                wrote on last edited by
                                #34

                                Thanks Stephane. I just knew this had to be an MS screw up all along. :rolleyes: Chris Meech "what makes CP different is the people and sense of community, things people will only discover if they join up and join in." Christian Graus Nov 14, 2002. Oh and for those that ask programming questions in the lounge. Seek the truth here[^].

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                                • N Nick Parker

                                  Ivor S. Sargoytchev wrote: So Epsilon should be some value that you pick up, not Double.Epsilon as some people suggested, right? Nope, check your local MSDN documentation on the Double.Epsilon Field. .NET Documentation wrote: For example, the C# expression, (double)1/3 == (double)0.33333, does not compare equal because the division operation on the left-hand side has maximum precision while the constant on the right-hand side is only precise to the visible digits. Instead, determine if the two sides of a comparison are close enough to equal for your purposes by comparing whether the absolute value of the difference between the left and right-hand sides is less than Epsilon. -Nick Parker

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                                  I Offline
                                  Ivor S Sargoytchev
                                  wrote on last edited by
                                  #35

                                  Nick, This cannot be true since the absolute value of ((0.4 - 1.2) + 0.8) is 0.00000000000000011102230246251565. The value of Double.Epsilon is 4.94065645841247E-324, which is much much smaller.

                                  1 Reply Last reply
                                  0
                                  • S Stephane Rodriguez

                                    Ok, so MS has still problem defining a simple and safe addition/substract operation on floating points. Nice. Now that's high-tech. Where is the Accessories / calculator SDK when I need it ? :laugh: Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

                                    E Offline
                                    E Offline
                                    Eco Jones
                                    wrote on last edited by
                                    #36

                                    Stephane Rodriguez. wrote: MS has still problem defining Yeah, and if they'd ignored the IEEE standard then chances are good you would be complaining that they're not "standards compliant." :rolleyes: Eco

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                                    • E Eco Jones

                                      Stephane Rodriguez. wrote: MS has still problem defining Yeah, and if they'd ignored the IEEE standard then chances are good you would be complaining that they're not "standards compliant." :rolleyes: Eco

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                                      Stephane Rodriguez
                                      wrote on last edited by
                                      #37

                                      If MS had ignored IEEE decades ago, then they would still be playing with their dicks. MS products are high priced. So they at least have to deliver. This limitation is beyond my imagination of most stupid case I could think of. Now, I should compare this behaviour to the JVM just to check if the issue was already there back a few years ago (just before they rebranded the JVM into the CLR and sold it like a new development platform). Grrrrr!!!! Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

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                                      • S Stephane Rodriguez

                                        If MS had ignored IEEE decades ago, then they would still be playing with their dicks. MS products are high priced. So they at least have to deliver. This limitation is beyond my imagination of most stupid case I could think of. Now, I should compare this behaviour to the JVM just to check if the issue was already there back a few years ago (just before they rebranded the JVM into the CLR and sold it like a new development platform). Grrrrr!!!! Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

                                        E Offline
                                        E Offline
                                        Eddie Velasquez
                                        wrote on last edited by
                                        #38

                                        Stephane Rodriguez. wrote: (just before they rebranded the JVM into the CLR and sold it like a new development platform What a pile of steamy, stinkin' sh... rubish! This is nothing more than your typical anti-microsoft rant, come on give it break! Provide some useful feedback or abstain for crying out loud! :mad:


                                        The nice thing about C++ is that only your friends can handle your private parts.

                                        S 1 Reply Last reply
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                                        • S Stephane Rodriguez

                                          If MS had ignored IEEE decades ago, then they would still be playing with their dicks. MS products are high priced. So they at least have to deliver. This limitation is beyond my imagination of most stupid case I could think of. Now, I should compare this behaviour to the JVM just to check if the issue was already there back a few years ago (just before they rebranded the JVM into the CLR and sold it like a new development platform). Grrrrr!!!! Taking advantage of InternetExplorer to steal user's name and password. Taking advantage of InternetExplorer to steal user's clipboard.

                                          E Offline
                                          E Offline
                                          Eco Jones
                                          wrote on last edited by
                                          #39

                                          Stephane Rodriguez. wrote: blah, blah, blah, MS EVIL, blah, blah Here's an e-quarter () - call someone who cares. Then you can use the change to buy a notebook where you record the amount of time you spend whining and complaining about Microsoft and the amount of time you spend actually trying to improve the situation and do a comparitive study and post it on slashdot and make a BIGGER frigging pretentious image in your signature and form anti-MS demonstrations and die happy knowing that you haven't really done a single worthwhile thing in your whole miserable existence other than slightly annoy a whole bunch of people. Worst-case scenario, of course. Eco

                                          S 1 Reply Last reply
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