Friday riddle...
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Since you started with a maths puzzle here is another. How can this be true? let a = x a+a = a+x [add a to both sides] 2a = a+x [a+a = 2a] 2a-2x = a+x-2x [subtract 2x from both sides] 2(a-x) = a+x-2x [2a-2x = 2(a-x)] 2(a-x) = a-x [x-2x = -x] 2 = 1 [divide both sides by a-x] There is a catch!! See if you can work it out. Ant. I'm hard, yet soft.
I'm coloured, yet clear.
I'm fruity and sweet.
I'm jelly, what am I? Muse on it further, I shall return! - David Williams (Little Britain)Dividing both sides by zero. I can use the same thing to prove that 1 hour is equal to one minute. See if you can do that ? :) "One of the Georges," said Psmith, "I forget which, once said that a certain number of hours' sleep a day--I cannot recall for the moment how many--made a man something, which for the time being has slipped my memory."
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You cannot divide both sides by a-x because a-x = a-a = 0. Can't divide by zero. Every programmer knows that. ;P I have a symbiotic relationship with my computer.
dacris wrote: You cannot divide both sides by a-x because a-x = a-a = 0. Can't divide by zero. Every programmer knows that. Duh! Wanna know why I'm still a hobbiest?
The only way of discovering the limits of the possible is to venture a little past them into the impossible.--Arthur C. Clark