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  4. extracting sustrings from a string and store it in an array

extracting sustrings from a string and store it in an array

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  • W wajans

    Hi I want to extract sustrings from a string and want to store in an array. The string is dynamic it will change but the criteria to extract substring is same. say for example a string str="something is [!better] than [!nothing]" so i need to extract [!better] and [!nothing] from the string and store it in a string array, the string is dynamic it changes but i need to extract data between [ and ] including both the square brackets. If anybody can send any sample code, I will be very thankfull. Thanks Ansari

    P Offline
    P Offline
    PIEBALDconsult
    wrote on last edited by
    #5

    Regular Expressions?

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    • W wajans

      Hi I want to extract sustrings from a string and want to store in an array. The string is dynamic it will change but the criteria to extract substring is same. say for example a string str="something is [!better] than [!nothing]" so i need to extract [!better] and [!nothing] from the string and store it in a string array, the string is dynamic it changes but i need to extract data between [ and ] including both the square brackets. If anybody can send any sample code, I will be very thankfull. Thanks Ansari

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      G Offline
      Guffa
      wrote on last edited by
      #6

      How about a one-liner to extract the strings from the array using a regular expression and placing them in an array? :)

      string[] substrings = Regex.Matches(str, @"\[.*?\]").OfType<match>().Select(m => m.Value).ToArray();

      Despite everything, the person most likely to be fooling you next is yourself.

      modified on Tuesday, September 16, 2008 12:18 PM

      W 1 Reply Last reply
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      • G Guffa

        How about a one-liner to extract the strings from the array using a regular expression and placing them in an array? :)

        string[] substrings = Regex.Matches(str, @"\[.*?\]").OfType<match>().Select(m => m.Value).ToArray();

        Despite everything, the person most likely to be fooling you next is yourself.

        modified on Tuesday, September 16, 2008 12:18 PM

        W Offline
        W Offline
        wajans
        wrote on last edited by
        #7

        Hi Guffa Thanks for your reply. I am getting "Invalid expression term '>'" error. Please help resolve this issue. Thanks Ansari

        W L 2 Replies Last reply
        0
        • realJSOPR realJSOP

          It would probably end up being a three-step process. If it's safe to assume that the stuff you're looking for would always be separated by a space, you could do this:

          string str = "something is [!better] than [!nothing]";
          // split the string on spaces
          string[] parts = str.Split(' ');
          List resultStringList = new List();

          foreach (string part in parts)
          {
          int pos1 = part.IndexOf("[");
          int pos2 = part.IndexOf("]");
          if (pos1 >= 0 && pos2 >= 0)
          {
          // get everything between the brackets, but NOT the brackets themselves
          string result = part.SubString(pos1+1, pos2);
          // add it to the list
          resultStringList.Add(result);
          }
          }

          string[] myResults = new string[resultStringList.Count];
          for (int i = 0; i < resultStringList.Count; i++)
          {
          myResults[i] = resultStringList[i];
          }

          "Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass..." - Dale Earnhardt, 1997
          -----
          "...the staggering layers of obscenity in your statement make it a work of art on so many levels." - Jason Jystad, 10/26/2001

          modified on Tuesday, September 16, 2008 10:23 AM

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          W Offline
          wajans
          wrote on last edited by
          #8

          Hi John I have a string which do not have spaces. Its something like this "

          [!vDescription][!vDate]

          [!vTitle]

          ", Sorry to not mention it in my earlier post. Hope you will reply back with the solution. Thanks for your reply. Thanks Ansari

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          • W wajans

            Hi Guffa Thanks for your reply. I am getting "Invalid expression term '>'" error. Please help resolve this issue. Thanks Ansari

            W Offline
            W Offline
            wajans
            wrote on last edited by
            #9

            Hi After doing r&d on regular expressions I got this answer. If we want to extract a word from a string like "[something]" We could use the Match method in the regular expression. Like this: string s = "

            [!vDescription][!vDate]

            [!vTitle]

            "; Regex rx = new Regex(@"\[.*?\]"); Match mc = rx.Match(s); while(mc.Success) { Response.Write(mc.Value.ToString()); mc = mc.NextMatch(); } Thanks

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            • W wajans

              Hi Guffa Thanks for your reply. I am getting "Invalid expression term '>'" error. Please help resolve this issue. Thanks Ansari

              L Offline
              L Offline
              Lost User
              wrote on last edited by
              #10

              You are probably not using framework 3.5 - Linq

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              • W wajans

                Hi After doing r&d on regular expressions I got this answer. If we want to extract a word from a string like "[something]" We could use the Match method in the regular expression. Like this: string s = "

                [!vDescription][!vDate]

                [!vTitle]

                "; Regex rx = new Regex(@"\[.*?\]"); Match mc = rx.Match(s); while(mc.Success) { Response.Write(mc.Value.ToString()); mc = mc.NextMatch(); } Thanks

                G Offline
                G Offline
                Guffa
                wrote on last edited by
                #11

                Use the Matches method to get them all:

                MatchCollection matches = Regex.Matches(s, "\[.*?\]");
                string substrings[] = new string[Matches.Count];
                for (int i = 0; i < matches.Count; i++) {
                substrings[i] = matches[i].Value;
                }

                Despite everything, the person most likely to be fooling you next is yourself.

                W 1 Reply Last reply
                0
                • G Guffa

                  Use the Matches method to get them all:

                  MatchCollection matches = Regex.Matches(s, "\[.*?\]");
                  string substrings[] = new string[Matches.Count];
                  for (int i = 0; i < matches.Count; i++) {
                  substrings[i] = matches[i].Value;
                  }

                  Despite everything, the person most likely to be fooling you next is yourself.

                  W Offline
                  W Offline
                  wajans
                  wrote on last edited by
                  #12

                  Hi Guffa My requirement changed, I am sure you can help me. I have a string for example str="something [!str1] and something [!str2].." so I want to store the substring from start up till "[" and then from "[" to "]" and so on. so how can we achieve it. Thanks Ansari

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                  • W wajans

                    Hi Guffa My requirement changed, I am sure you can help me. I have a string for example str="something [!str1] and something [!str2].." so I want to store the substring from start up till "[" and then from "[" to "]" and so on. so how can we achieve it. Thanks Ansari

                    G Offline
                    G Offline
                    Guffa
                    wrote on last edited by
                    #13

                    Split on brackets, then you get an array containing the strings between the brackets. string str="something [!str1] and something [!str2] else."; string[] substrings = str.Split(new char[]{ '[', ']' }); This gives you an array with the following strings: "something " "!str1" " and something " "!str2" " else."

                    Despite everything, the person most likely to be fooling you next is yourself.

                    W 1 Reply Last reply
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                    • G Guffa

                      Split on brackets, then you get an array containing the strings between the brackets. string str="something [!str1] and something [!str2] else."; string[] substrings = str.Split(new char[]{ '[', ']' }); This gives you an array with the following strings: "something " "!str1" " and something " "!str2" " else."

                      Despite everything, the person most likely to be fooling you next is yourself.

                      W Offline
                      W Offline
                      wajans
                      wrote on last edited by
                      #14

                      Thanks a lot Guffa for your quick reply. It works great.

                      modified on Friday, September 19, 2008 5:54 AM

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