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  4. randomization of numbers without duplication in C#

randomization of numbers without duplication in C#

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  • P Pete OHanlon

    An easier way would be to reseed the randomizer after every call with a value greater than the last returned result. It's not a great way, but it cuts out the checking.

    "WPF has many lovers. It's a veritable porn star!" - Josh Smith

    As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.

    My blog | My articles | MoXAML PowerToys | Onyx

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    molesworth
    wrote on last edited by
    #7

    Would that work? Since the next random value could be less than the seed, you could re-seed with a value you've used previously.

    There are three kinds of people in the world - those who can count and those who can't...

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    • M molesworth

      Would that work? Since the next random value could be less than the seed, you could re-seed with a value you've used previously.

      There are three kinds of people in the world - those who can count and those who can't...

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      Pete OHanlon
      wrote on last edited by
      #8

      What I was thinking was actually using Random.Next with the starting value being the value you've just retrieved + some small amount as the starting point, e.g. Random.Next(lastVal + 1, lastVal + 100).

      "WPF has many lovers. It's a veritable porn star!" - Josh Smith

      As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.

      My blog | My articles | MoXAML PowerToys | Onyx

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      • P Pete OHanlon

        What I was thinking was actually using Random.Next with the starting value being the value you've just retrieved + some small amount as the starting point, e.g. Random.Next(lastVal + 1, lastVal + 100).

        "WPF has many lovers. It's a veritable porn star!" - Josh Smith

        As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.

        My blog | My articles | MoXAML PowerToys | Onyx

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        Luc Pattyn
        wrote on last edited by
        #9

        I'm afraid there is no way you can tell the RNG what all the numbers are that have already been picked, so the best you can achieve is avoid repeating the previous number, not all the older ones. Of course if all the OP wants to avoid is consecutive duplication, then your way would be fine. :)

        Luc Pattyn [Forum Guidelines] [My Articles]


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        • L Luc Pattyn

          that may take forever. :~

          Luc Pattyn [Forum Guidelines] [My Articles]


          The quality and detail of your question reflects on the effectiveness of the help you are likely to get. Show formatted code inside PRE tags, and give clear symptoms when describing a problem.


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          benjymous
          wrote on last edited by
          #10

          Yup, but the OP didn't really specify enough to say what he actually wanted, so I gave a generic, if not necessarily useful answer.

          Help me! I'm turning into a grapefruit! Buzzwords!

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          • L Luc Pattyn

            When N "random" numbers in [0, RANGE) need to be unique, the range typically is small, so I prefer to put them all in a bag and use a random index to get them, one by one. So there is no need for a retry. And the problem has no solution for N>RANGE so some precautions need to be taken in any algorithm based on retrying. :)

            Luc Pattyn [Forum Guidelines] [My Articles]


            The quality and detail of your question reflects on the effectiveness of the help you are likely to get. Show formatted code inside PRE tags, and give clear symptoms when describing a problem.


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            benjymous
            wrote on last edited by
            #11

            You could also shuffle your bag and just pop the top entry each time, depending on where the bottleneck ends up being

            Help me! I'm turning into a grapefruit! Buzzwords!

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            • B benjymous

              You could also shuffle your bag and just pop the top entry each time, depending on where the bottleneck ends up being

              Help me! I'm turning into a grapefruit! Buzzwords!

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              Luc Pattyn
              wrote on last edited by
              #12

              That would take a Random Shuffle Generator, which isn't provided by the .NET Framework as of now. :)

              Luc Pattyn [Forum Guidelines] [My Articles]


              The quality and detail of your question reflects on the effectiveness of the help you are likely to get. Show formatted code inside PRE tags, and give clear symptoms when describing a problem.


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              • P Pete OHanlon

                What I was thinking was actually using Random.Next with the starting value being the value you've just retrieved + some small amount as the starting point, e.g. Random.Next(lastVal + 1, lastVal + 100).

                "WPF has many lovers. It's a veritable porn star!" - Josh Smith

                As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.

                My blog | My articles | MoXAML PowerToys | Onyx

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                molesworth
                wrote on last edited by
                #13

                Pete O'Hanlon wrote:

                Random.Next(lastVal + 1, lastVal + 100)

                Erm, doesn't that just give you a monotonically increasing set of values?

                There are three kinds of people in the world - those who can count and those who can't...

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                • V vasavi p

                  Need the randomization of numbers without repeatation using c#

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                  PIEBALDconsult
                  wrote on last edited by
                  #14

                  People ask that frequently here, have you searched the threads in this forum?

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                  • M molesworth

                    Pete O'Hanlon wrote:

                    Random.Next(lastVal + 1, lastVal + 100)

                    Erm, doesn't that just give you a monotonically increasing set of values?

                    There are three kinds of people in the world - those who can count and those who can't...

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                    Pete OHanlon
                    wrote on last edited by
                    #15

                    Yes - I'm not saying it's the way I'd do it, just that it is a way.

                    "WPF has many lovers. It's a veritable porn star!" - Josh Smith

                    As Braveheart once said, "You can take our freedom but you'll never take our Hobnobs!" - Martin Hughes.

                    My blog | My articles | MoXAML PowerToys | Onyx

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                    • V vasavi p

                      Need the randomization of numbers without repeatation using c#

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                      cmk
                      wrote on last edited by
                      #16

                      How many non-repeating random numbers are you going to want to get ? What is the range of random numbers - are they integers or real.

                      ...cmk The idea that I can be presented with a problem, set out to logically solve it with the tools at hand, and wind up with a program that could not be legally used because someone else followed the same logical steps some years ago and filed for a patent on it is horrifying. - John Carmack

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