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  4. [Resolved] C# to VB Adaption Problem with Lambda Expressions

[Resolved] C# to VB Adaption Problem with Lambda Expressions

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csharplinqhtmlvisual-studiofunctional
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  • S Sonhospa

    Hi guys, I hope you had a nice start into 2012! I've been trying to convert this^ piece of code into VB, using VS Express 2010 and #Develop. In order to avoid problems with conversion of c# 'yield' operator, I put the extensions into a DLL and set a reference to that. The translated code of the test implementation reads like:

    Shared Sub Main(ByVal args() As String)
    Dim worker As New BackgroundWorker()
    worker.WorkerReportsProgress = True
    AddHandler worker.DoWork, Function(sender, e)
    ' pretend we have a collection of items to process
    Dim items(999) As Integer
    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work
    End Function

    AddHandler worker.ProgressChanged, Function(sender, e)
    ' make sure the figure is written to the
    ' same point on screen each time
    Console.SetCursorPosition(1, 0)
    Console.Write(e.ProgressPercentage)
    End Function
    
    worker.RunWorkerAsync()
    Console.Read()
    

    End Sub

    Unfortunately in VB the line

    items.WithProgressReporting(Function(progress) worker.ReportProgress(progress).ForEach(Function(item) Thread.Sleep(10)))

    throws an exception "Expression does not produce a value" at the underlined place. There's no such exception in C# where the test code compiles and executes fine. Having to implement the technique into my VB application, I'd like to understand where the problem arises. Could anyone of you tell me what's wrong in the (automatic) translation of the Lambda expression? Thank you Mick

    D Offline
    D Offline
    DavidSherwood
    wrote on last edited by
    #21

    In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

    ForEach(Sub(item) Thread.Sleep(10))

    S S 2 Replies Last reply
    0
    • D DavidSherwood

      In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

      ForEach(Sub(item) Thread.Sleep(10))

      S Offline
      S Offline
      Simon_Whale
      wrote on last edited by
      #22

      Only true with 2010 though, as there is many time I would loved to of used it in my current project that is 3.5 framework

      Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

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      • S Simon_Whale

        VB2010 has introduced sub(parameter) into the lambda specification. I haven't tested it but wouldn't the following work?

        items.WithProgressReporting(sub(progress) worker.ReportProgress(progress) end sub).forEach(function(item) thread.Sleep(10)))

        Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

        S Offline
        S Offline
        Sonhospa
        wrote on last edited by
        #23

        Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

        items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

        works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

        S 1 Reply Last reply
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        • S Sonhospa

          Hi Simon, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

          items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

          works, as well as Estys suggestion to factor out the subs. No "end" needed here. Regards - Mick

          S Offline
          S Offline
          Simon_Whale
          wrote on last edited by
          #24

          Glad it helped :thumbsup:

          Lobster Thermidor aux crevettes with a Mornay sauce, served in a Provençale manner with shallots and aubergines, garnished with truffle pate, brandy and a fried egg on top and Spam - Monty Python Spam Sketch

          1 Reply Last reply
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          • U User 7825588

            Try changing this line:

            items.WithProgressReporting(Function(progress)
            worker.ReportProgress(progress)).ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

            To this:

            items.WithProgressReporting(Function(progress) _
            worker.ReportProgress(progress)).ToList.ForEach(Function(item) Thread.Sleep(10)) ' simulate some real work

            The .ForEach extension method doesn't work with IEnumerables and since that's what WithProgressReporting returns, the resultset must first be cast as a Generic List. Also, I don't know for sure, but it looks like the converter inserted an extra line break. That's why I added the underscore to the end of the first line.

            S Offline
            S Offline
            Sonhospa
            wrote on last edited by
            #25

            Hi Member... ;) , sorry for the late response which was due to a short holiday of mine. Thanks for your hint which unfortunately didn't work: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

            items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

            works, as well as Estys suggestion to factor out the subs (no "end" or "ToList" constructions needed). Regards - Mick

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            • E Estys

              I always have trouble with anonymous delegates in VB so I factored them out :

              Class Program
              Shared worker As BackgroundWorker
              Public Shared Sub Main() 'ByVal args As String())
              worker = New BackgroundWorker()
              worker.WorkerReportsProgress = True
              AddHandler worker.DoWork, AddressOf DoWork
              AddHandler worker.ProgressChanged, AddressOf ProgressChanged
              worker.RunWorkerAsync()
              Console.Read()
              End Sub

              Private Shared Sub DoWork(ByVal sender As Object, ByVal e As DoWorkEventArgs)
                  Dim items = Enumerable.Range(1, 1000)
                  items.WithProgressReporting(AddressOf ReportProgress).ForEach(AddressOf DoSleep)
              End Sub
              Private Shared Sub ReportProgress(ByVal progress As Integer)
                  worker.ReportProgress(progress)
              End Sub
              Private Shared Sub DoSleep(ByVal item As Integer)
                  Thread.Sleep(10)
              End Sub
              Private Shared Sub ProgressChanged(ByVal sender As Object, ByVal e As ProgressChangedEventArgs)
                  Console.SetCursorPosition(1, 0)
                  Console.Write(e.ProgressPercentage)
              End Sub
              

              End Class

              Cheers

              S Offline
              S Offline
              Sonhospa
              wrote on last edited by
              #26

              Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

              items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

              works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

              Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

              in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

              E 1 Reply Last reply
              0
              • D DavidSherwood

                In VB, a function that returns void is a "Sub". This is true with lambda function as well. So your ForEach lambda should be

                ForEach(Sub(item) Thread.Sleep(10))

                S Offline
                S Offline
                Sonhospa
                wrote on last edited by
                #27

                Hi David, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which pushed me in the right direction: In the end, all I had to do was simply change "function" into "sub" in VB. It's finally solved now, and the line

                items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                works, as well as Estys suggestion to factor out the subs (slightly changed). Thanks again, regards - Mick

                1 Reply Last reply
                0
                • S Sonhospa

                  Hi Estys, sorry for the late response which was due to a short holiday of mine. Thanks for your hint which, together with the other guys' ideas, pushed me in the right direction: In the end, all I had to do was change "function" into "sub" in VB. It's finally solved now, and the line

                  items.WithProgressReporting(Sub(progress) worker.ReportProgress(progress)).ForEach(Sub(item) Thread.Sleep(10))

                  works, as well as your suggestion to factor out the subs. Just to complete: In your snippet I had to change the definition of 'items' to:

                  Dim items As IEnumerable(Of Integer) = Enumerable.Range(1, 1000)

                  in VB. But the most important thing: It works - and I hope I understand it a little better ;) Thanks again, regards - Mick

                  E Offline
                  E Offline
                  Estys
                  wrote on last edited by
                  #28

                  Michael Schäuble wrote:

                  I had to change the definition of 'items'

                  That's odd, with me it worked as I posted it. I'm on .NET 3.5, VB Express 2008 Cheers

                  If you can read this, you don't have Papyrus installed

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