how to get date difference

User 9106259

hi i have 4 fields like as bellow 1.start date 2.start time 3.end date 4.end time by using above fields how can i get difference in hours in php project any body can help me. thank you.

Peter_in_2780

A little RTFM goes a long way. Open up the PHP manual (online if you were too stupid or lazy to download a free copy) and type "date difference" into the search box. Work with DateTime and DateInterval objects. Peter

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

User 9106259

that is not happening so that only posted.

Peter_in_2780

?????? Try this link[^] then.

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

Deepthi 21456

<?php
$date1 = "2012-10-04 22:45:00";
$date2 = "2013-12-05 13:44:01";
$diff = abs(strtotime($date2) - strtotime($date1));
$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));
$hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60));
$minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60);
$seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60));
printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);
die;
?>

Anilannu

What is your project... how you help me if i help u

@n!L

Mohibur Rashid

If you searched on google you would find 1000's of solutions. this is copied from PHP site

<?php
$td = time_diff($timestamp1-$timestamp2); // has to be a positive result
$td .= ($td=="now")? "":" ago"; // in this example "ago"
echo $td;

function time_diff($s){

$time = get\_post\_time('G', true, $post);
$s = time() - $time;

if($s>=1) {
$td = "$s sec";
}  

if($s>59) {
    $m = (int)($s/60);
    $s = $s-($m\*60); // sec left over
    $td = "$m min"; if($s>1) $td .="s";
}
if($m>59){
    $hr = (int)($m/60);
    $m = $m-($hr\*60); // min left over
    $td = "$hr hr"; if($hr>1) $td .= "s";
    if($m>0) $td .= ", $m min";
}
if($hr>23){
    $d = (int)($hr/24);
    $hr = $hr-($d\*24); // hr left over
    $td = "$d day"; if($d>1) $td .= "s";
    if($d<3){
        if($hr>0) $td .= ", $hr hr"; if($hr>1) $td .= "s";
    }
}
return $td;

}
?>

I wish I could believe there is an after life.