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  • H Hakan Bulut

    var arrIns = [
    "1","21","24","28","42","48",
    "9","13","14","16","24","49",
    "3","18","19","25","44","45"
    ];

    Was that I wanted to do exactly. These numbers are the numbers that are caught in the combination of more than one slip would like to add Forexmple 24 number is 2 winnig number. i want to print this numbers from inside this array..

    Hakan cursed chats dealer :)

    D Offline
    D Offline
    dusty_dex
    wrote on last edited by
    #16

    Sorry I do not understand. :confused: try and explain by breaking up the problem, and show example of array before and after. Maybe I can work it out.

    "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

    1 Reply Last reply
    0
    • H Hakan Bulut

      var arrIns = [
      "1","21","24","28","42","48",
      "9","13","14","16","24","49",
      "3","18","19","25","44","45"
      ];

      Was that I wanted to do exactly. These numbers are the numbers that are caught in the combination of more than one slip would like to add Forexmple 24 number is 2 winnig number. i want to print this numbers from inside this array..

      Hakan cursed chats dealer :)

      D Offline
      D Offline
      dusty_dex
      wrote on last edited by
      #17

      Try adding this line inside the loop for(var i=1; i<50; i++) { // compare t with all lucky numbers t = zeroAdjust(i); if (allLucky.indexOf(t) == -1 ) { arr[count] = t; // arr[] = "nn" count++; }

      if (allLucky.indexOf(t) != -1) document.write("Match: "+t);

      } // for-loop If you need to collect all matched lucky numbers then you should create a new array: var matched = []; var m = 0; change that line to

      if (allLucky.indexOf(t) != -1) {
      matched[m] = t;
      m++;
      }

      "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

      H 1 Reply Last reply
      0
      • D dusty_dex

        Try adding this line inside the loop for(var i=1; i<50; i++) { // compare t with all lucky numbers t = zeroAdjust(i); if (allLucky.indexOf(t) == -1 ) { arr[count] = t; // arr[] = "nn" count++; }

        if (allLucky.indexOf(t) != -1) document.write("Match: "+t);

        } // for-loop If you need to collect all matched lucky numbers then you should create a new array: var matched = []; var m = 0; change that line to

        if (allLucky.indexOf(t) != -1) {
        matched[m] = t;
        m++;
        }

        "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

        H Offline
        H Offline
        Hakan Bulut
        wrote on last edited by
        #18

        I'm customer just now... If it does compare to 49 numbers of dimension so 1 adjust as match each one of numbers and it will no return encounter for the same numbers .. JavaScript is not skilled enough

        Hakan cursed chats dealer :)

        D 1 Reply Last reply
        0
        • H Hakan Bulut

          I'm customer just now... If it does compare to 49 numbers of dimension so 1 adjust as match each one of numbers and it will no return encounter for the same numbers .. JavaScript is not skilled enough

          Hakan cursed chats dealer :)

          D Offline
          D Offline
          dusty_dex
          wrote on last edited by
          #19

          If you are referring to C++ pointers then you are not going to get very far. If I understood problem better. I could work it out. You are not a very good communicator, it is not a problem with javascript. The problem is English to Turkish translation. But you are not giving enough feedback.

          "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

          H 1 Reply Last reply
          0
          • D dusty_dex

            If you are referring to C++ pointers then you are not going to get very far. If I understood problem better. I could work it out. You are not a very good communicator, it is not a problem with javascript. The problem is English to Turkish translation. But you are not giving enough feedback.

            "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

            H Offline
            H Offline
            Hakan Bulut
            wrote on last edited by
            #20

            I know this is possible with Reverse() but IE9.0 is not supported I have to thanks for everything

            Hakan cursed chats dealer :)

            D 1 Reply Last reply
            0
            • H Hakan Bulut

              I know this is possible with Reverse() but IE9.0 is not supported I have to thanks for everything

              Hakan cursed chats dealer :)

              D Offline
              D Offline
              dusty_dex
              wrote on last edited by
              #21

              If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.

              "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

              H 2 Replies Last reply
              0
              • D dusty_dex

                If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.

                "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                H Offline
                H Offline
                Hakan Bulut
                wrote on last edited by
                #22

                Finally, I tried the following code.

                var arrIns = [
                "1","21","24","28","42","48",
                "9","13","14","16","24","49",
                "3","18","19","25","44","45"
                ];
                var arr = [];
                var tmp = 0;
                var IsElm = 0;
                function indexe(){
                for(var i=0; i<arrIns.length-1; i++)
                {
                if(arrIns[i] != arrIns[i+1]) { // arrIns[arrIns.Length - 1] = tmp;
                IsElm = i; // i temp
                arr[tmp++] = arrIns[i];
                arrIns.splice(arrIns[IsElm]);
                }
                return --IsElm;
                document.write(arr[tmp++] + " : " + arrIns.indexOf(arrIns[i]) + "<BR>");
                //return arrIns.indexOf(arrIns[i]);
                }
                }

                Hakan cursed chats dealer :)

                1 Reply Last reply
                0
                • D dusty_dex

                  If you are referring to array.reverse, then it is possible, even with IE 9.0 and as far back as IE 3.0. The browser doesn't affect Javascript features, only the revision (version) supported. Javascript features are not controlled by Microsoft, only the implementation. ECMA controls Javascript features. Most of the time I have to figure out (guess) what you want. And I don't always get a reply. a simple :thumbsup: or Yes, ok. or :thumbsdown: or No, not ok. I think your problem is storing numbers in strings, and applying C++ use (ie pointers) to them. Obviously the lack of computer books in your own language means that you could be learning from bad translation where the meaning of concepts is lost. Maybe you should learn English. Then the barriers to understanding won't slow you down.

                  "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                  H Offline
                  H Offline
                  Hakan Bulut
                  wrote on last edited by
                  #23

                  :thumbsup:

                  Hakan cursed chats dealer :)

                  H 1 Reply Last reply
                  0
                  • H Hakan Bulut

                    :thumbsup:

                    Hakan cursed chats dealer :)

                    H Offline
                    H Offline
                    Hakan Bulut
                    wrote on last edited by
                    #24

                    I used to ur method

                    var arrIns = [
                    "1","21","24","28","42","48",
                    "9","13","14","16","24","49",
                    "3","18","19","25","44","45"
                    ];
                    var arr = [];
                    var AllLucky= [];
                    var ct = 0;
                    var n = 0;

                    do{
                    for(var i=arrIns.length; i>0; --i)
                    {
                    arrIns[i] = arr[i];
                    for(var j=0; j<arrIns.lenght; j++)
                    {
                    if(!arrIns[arr[j]]) {
                    arrIns[arr[j]] = AllLucky[ct];
                    document.write(AllLucky[ct] + "<BR>");
                    ct++; n++;
                    }
                    }
                    }
                    }while(n<1);

                    output is 24 must be ?

                    Hakan cursed chats dealer :)

                    D 2 Replies Last reply
                    0
                    • H Hakan Bulut

                      I used to ur method

                      var arrIns = [
                      "1","21","24","28","42","48",
                      "9","13","14","16","24","49",
                      "3","18","19","25","44","45"
                      ];
                      var arr = [];
                      var AllLucky= [];
                      var ct = 0;
                      var n = 0;

                      do{
                      for(var i=arrIns.length; i>0; --i)
                      {
                      arrIns[i] = arr[i];
                      for(var j=0; j<arrIns.lenght; j++)
                      {
                      if(!arrIns[arr[j]]) {
                      arrIns[arr[j]] = AllLucky[ct];
                      document.write(AllLucky[ct] + "<BR>");
                      ct++; n++;
                      }
                      }
                      }
                      }while(n<1);

                      output is 24 must be ?

                      Hakan cursed chats dealer :)

                      D Offline
                      D Offline
                      dusty_dex
                      wrote on last edited by
                      #25

                      I will take a look at today's messages later tonight. there is spelling mistake, length

                      for(var j=0; j

                      :)

                      Q. Are you trying to create a 2D table that indexes all of arrIns?

                      0, "1"
                      12, "3"
                      6, "9"
                      .
                      .
                      11, "49"

                      the line below is deleting arrIns[i] items.

                      problem is arr[i] = undefined (empty like c++ void).
                      so, arrIns[i] = undefined.

                      arrIns[i] = arr[i];

                      Not enough code to test it.
                      I need array AllLucky. ;)

                      "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan

                      That's what machines are for.

                      Got a problem?
                      Sleep on it.

                      1 Reply Last reply
                      0
                      • H Hakan Bulut

                        I used to ur method

                        var arrIns = [
                        "1","21","24","28","42","48",
                        "9","13","14","16","24","49",
                        "3","18","19","25","44","45"
                        ];
                        var arr = [];
                        var AllLucky= [];
                        var ct = 0;
                        var n = 0;

                        do{
                        for(var i=arrIns.length; i>0; --i)
                        {
                        arrIns[i] = arr[i];
                        for(var j=0; j<arrIns.lenght; j++)
                        {
                        if(!arrIns[arr[j]]) {
                        arrIns[arr[j]] = AllLucky[ct];
                        document.write(AllLucky[ct] + "<BR>");
                        ct++; n++;
                        }
                        }
                        }
                        }while(n<1);

                        output is 24 must be ?

                        Hakan cursed chats dealer :)

                        D Offline
                        D Offline
                        dusty_dex
                        wrote on last edited by
                        #26

                        please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:

                        "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                        H 1 Reply Last reply
                        0
                        • D dusty_dex

                          please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:

                          "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                          H Offline
                          H Offline
                          Hakan Bulut
                          wrote on last edited by
                          #27

                          Just kidding!! Please don't offense on you.

                          Hakan cursed chats dealer :)

                          D 1 Reply Last reply
                          0
                          • H Hakan Bulut

                            Just kidding!! Please don't offense on you.

                            Hakan cursed chats dealer :)

                            D Offline
                            D Offline
                            dusty_dex
                            wrote on last edited by
                            #28

                            ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.

                            "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                            H 1 Reply Last reply
                            0
                            • D dusty_dex

                              ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.

                              "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                              H Offline
                              H Offline
                              Hakan Bulut
                              wrote on last edited by
                              #29

                              if(!arrIns[arr[j]])

                              is 24 AllLucky[ 24 ] differencly

                              H 1 Reply Last reply
                              0
                              • H Hakan Bulut

                                if(!arrIns[arr[j]])

                                is 24 AllLucky[ 24 ] differencly

                                H Offline
                                H Offline
                                Hakan Bulut
                                wrote on last edited by
                                #30

                                9 10 38 40 46 48

                                there is no pick number this week too :) lotto combination is uselessness

                                D 2 Replies Last reply
                                0
                                • H Hakan Bulut

                                  9 10 38 40 46 48

                                  there is no pick number this week too :) lotto combination is uselessness

                                  D Offline
                                  D Offline
                                  dusty_dex
                                  wrote on last edited by
                                  #31

                                  Q1. is arr[] lucky numbers to add to existing ? Q2. So, you want to add new set of lucky numbers to arrIns, but only if they do not exist in arrIns. Yes? =============================================== from what you told me before I thought old lucky numbers would get replaced var arrIns = [ "1","21","24","28","42","48", // week-2 is removed "9","10","38","40","46","48" // this is new week-2 set "9","13","14","16","24","49", "3","18","19","25","44","45", ]; or var arrIns = [ "1","21","24","28","42","48", "9","13","14","16","24","49", "3","18","19","25","44","45", "9","10","38","40","46","48" // new week-2 ]

                                  "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                                  1 Reply Last reply
                                  0
                                  • H Hakan Bulut

                                    9 10 38 40 46 48

                                    there is no pick number this week too :) lotto combination is uselessness

                                    D Offline
                                    D Offline
                                    dusty_dex
                                    wrote on last edited by
                                    #32

                                    If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)

                                    "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                                    H 1 Reply Last reply
                                    0
                                    • H Hakan Bulut

                                      Documentation The lucky numbers, I want to compare the values ​​that are encountering the same. Anyone can help on this topic?

                                      .
                                      .
                                      if(arrLot\[i\] == arrIns\[18\])
                                      if(arrLot\[i\] == arrIns\[19\]){
                                          lucky\[add++\] = arrLot\[i\];
                                          if(lucky\[add++\] = arrLot\[i\]) {
                                              lucky\[add++\] = gb;
                                          }
                                      }
                                      

                                      }
                                      var gb = getBNS();
                                      function getBNS()
                                      {
                                      var mf = 0;
                                      return Math.floor(mf+=1);
                                      }

                                      do{
                                      if(gb.mf > 1){
                                      lucky[ct].sort(function(a,b){
                                      return a-b}); // end sort
                                      }
                                      document.write(lucky[ct] + " : " + gb + "<BR>");
                                      ct++;
                                      }while(ct<17);

                                      mesela burada 18 adet sayı elemanlarını kendi aralarında karşılaştırdıktan sonra hangi sayının ne kadar karşılaştığını hesaplayan ve dökümanlayan bir kod yazmaya çalışıyorum. Tanımla problemi var. mesela şöyle bir çıktı veriyor:

                                      <pre>

                                      Undefined : 1 Undefined : 1 Undefined : 1 Undefined : 1

                                      var arrIns = [
                                      "1","21","24","28","42","48",
                                      "9","13","14","16","24","49",
                                      "3","18","19","25","44","45"
                                      ];

                                      Burada çıktı

                                      24 : 2
                                      1 : 1
                                      21 : 1

                                      olmalı..

                                      J Offline
                                      J Offline
                                      jkirkerx
                                      wrote on last edited by
                                      #33

                                      If your working with numbers, why make them strings, how are you going to test if 1 number is less than the other number?, Why not just work with numbers?

                                      var arrIns = [
                                      1,21,24,28,42,48,
                                      9,13,14,16,24,49,
                                      3,18,19,25,44,45
                                      ];

                                      1 Reply Last reply
                                      0
                                      • D dusty_dex

                                        If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)

                                        "It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

                                        H Offline
                                        H Offline
                                        Hakan Bulut
                                        wrote on last edited by
                                        #34

                                        Thanks for Java SDKs

                                        1 Reply Last reply
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