JS Question
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I used to ur method
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var AllLucky= [];
var ct = 0;
var n = 0;do{
for(var i=arrIns.length; i>0; --i)
{
arrIns[i] = arr[i];
for(var j=0; j<arrIns.lenght; j++)
{
if(!arrIns[arr[j]]) {
arrIns[arr[j]] = AllLucky[ct];
document.write(AllLucky[ct] + "<BR>");
ct++; n++;
}
}
}
}while(n<1);output is 24 must be ?
Hakan cursed chats dealer :)
I will take a look at today's messages later tonight. there is spelling mistake, length
for(var j=0; j
:)
Q. Are you trying to create a 2D table that indexes all of arrIns?
0, "1"
12, "3"
6, "9"
.
.
11, "49"the line below is deleting arrIns[i] items.
problem is arr[i] = undefined (empty like c++ void).
so, arrIns[i] = undefined.arrIns[i] = arr[i];
Not enough code to test it.
I need array AllLucky. ;)"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan
That's what machines are for.
Got a problem?
Sleep on it. -
I used to ur method
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];
var arr = [];
var AllLucky= [];
var ct = 0;
var n = 0;do{
for(var i=arrIns.length; i>0; --i)
{
arrIns[i] = arr[i];
for(var j=0; j<arrIns.lenght; j++)
{
if(!arrIns[arr[j]]) {
arrIns[arr[j]] = AllLucky[ct];
document.write(AllLucky[ct] + "<BR>");
ct++; n++;
}
}
}
}while(n<1);output is 24 must be ?
Hakan cursed chats dealer :)
please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
-
please explain your signature: Hakan cursed chats dealer :) If you are just messing people about, I will stop helping right now. :mad:
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Just kidding!! Please don't offense on you.
Hakan cursed chats dealer :)
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Just kidding!! Please don't offense on you.
Hakan cursed chats dealer :)
ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
-
ok. :| post message explain the arrays, differences AllLucky arrIns arr :confused: Help me to see what each one will look like at the end of code.
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
if(!arrIns[arr[j]])
is 24 AllLucky[ 24 ] differencly
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if(!arrIns[arr[j]])
is 24 AllLucky[ 24 ] differencly
9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
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9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
Q1. is arr[] lucky numbers to add to existing ? Q2. So, you want to add new set of lucky numbers to arrIns, but only if they do not exist in arrIns. Yes? =============================================== from what you told me before I thought old lucky numbers would get replaced var arrIns = [ "1","21","24","28","42","48", // week-2 is removed "9","10","38","40","46","48" // this is new week-2 set "9","13","14","16","24","49", "3","18","19","25","44","45", ]; or var arrIns = [ "1","21","24","28","42","48", "9","13","14","16","24","49", "3","18","19","25","44","45", "9","10","38","40","46","48" // new week-2 ]
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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9 10 38 40 46 48
there is no pick number this week too :) lotto combination is uselessness
If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
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Documentation The lucky numbers, I want to compare the values that are encountering the same. Anyone can help on this topic?
. . if(arrLot\[i\] == arrIns\[18\]) if(arrLot\[i\] == arrIns\[19\]){ lucky\[add++\] = arrLot\[i\]; if(lucky\[add++\] = arrLot\[i\]) { lucky\[add++\] = gb; } }}
var gb = getBNS();
function getBNS()
{
var mf = 0;
return Math.floor(mf+=1);
}do{
if(gb.mf > 1){
lucky[ct].sort(function(a,b){
return a-b}); // end sort
}
document.write(lucky[ct] + " : " + gb + "<BR>");
ct++;
}while(ct<17);mesela burada 18 adet sayı elemanlarını kendi aralarında karşılaştırdıktan sonra hangi sayının ne kadar karşılaştığını hesaplayan ve dökümanlayan bir kod yazmaya çalışıyorum. Tanımla problemi var. mesela şöyle bir çıktı veriyor:
<pre>
Undefined : 1 Undefined : 1 Undefined : 1 Undefined : 1
var arrIns = [
"1","21","24","28","42","48",
"9","13","14","16","24","49",
"3","18","19","25","44","45"
];Burada çıktı
24 : 2
1 : 1
21 : 1olmalı..
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If you get Java SE JRE7 & also install this Rhino Shell You can experiment with Javascript and learn things better. Using a web browser is no good for learning. I will help you get it set up and how to use it. :)
"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.
Thanks for Java SDKs