ReadLine doesn't terminate until it encounters a NewLine; try a different method.

i think you should be opening and closing streams with each write anyway, you dont want to leave a stream open longer than needed. As i also suggested, i think the best way is to: Get string from port, Write it to the log file, then pass it to the parsing thread for whatever that needs to do My opinion is... If someone has already posted an answer, dont post the SAME answer

Hi, I like that very much. I would even add a label showing the hex values of the bytes that get transmitted at the sender, and received at the receiver PC. Observability is key in debugging. :) Luc Pattyn [Forum Guidelines] [My Articles] - before you ask a question here, search CodeProject, then Google - the quality and detail of your question reflects on the effectiveness of the help you are likely to get - use the code block button (PRE tags) to preserve formatting when showing multi-line code snippets modified on Friday, June 10, 2011 11:37 AM

Ok :) Did it help you? Try to use ASCI code. In the past i created chat(server and client) that get stream(text) from tcp connection and show it in textbox. TcpClient newClient; NetworkStream ns; string message=" "; byte[] bytes = new byte[1024]; ns = newClient.GetStream(); bytesRead = ns.Read(bytes, 0, bytes.Length); message = Encoding.ASCII.GetString(bytes, 0, bytesRead);

You're welcome :) The need to optimize rises from a bad design.My articles[^]

ooo thank you... it was very helpful!

Thank you! that was perfect :-D

With ADO.NET and SQL. Christian Graus No longer a Microsoft MVP, but still happy to answer your questions.

Use Anchor property for that textbox. All C# applications should call Application.Quit(); in the beginning to avoid any .NET problems.- Unclyclopedia How to use google | Ask smart questions

check that u have written the dataadapters insert command properly with correct parameters rahul

You will need to define the InsertCommand property of the DataAdapter like so: // Connection & DataAdapter initialization code should go here // ... OleDbCommand insertCommand = connection.CreateCommand(); insertCommand.CommandText = "Insert Into Table(Col1, Col2, Col3) Values (?, ?, ?)"; dataAdapter.InsertCommand = insertCommand; // ... You may also want to check out the UpdateCommand and DeleteCommand properties which will allow your adapter to update and delete records which is what it seems you are also trying to do in your code snippet. /F - .NET Developer

Right click on References in Solution Explorer and choose Add Reference. Click the COM tab and you'll find it in the list. Dave

you can use the static or shared keyword depending on the language that you are using. Regards, Thomas Stockwell Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning. Visit my homepage Oracle Studios Discounted or Free Software for Students: DreamSpark - downloads.channel8.msdn.com MSDN Academic Alliance - www.msdnaa.com

System.IO.StreamReader sr = new System.IO.StreamReader("c:\\1.txt"); String Line = sr.ReadLine(); And Look for String.Split to split string to array based on entry. And using String.Substring to get specific chars of specific lenght. You need to manualy create parser to intercept and convert it to your DB writer

You can't actually have a reference, a control can only be in one place at a time, so you've got no problem there. Like people have said, you will need to create a new instance of the controls and add these new controls to the tab. To see how you can create, setup, and add controls, just check the designers generated code. My current favourite word is: I'm starting to run out of fav. words! -SK Genius Game Programming articles start -here[^]-

hi, you can also use 'FileInfo' class to get some information of your file in the given path.

First of all, i am very sorry, really.unintentionally i added this smile. I do not mean it. i am very nice guy :D And now to the question: I created a GroupBox(groupBox1) that contains textBox and buttons(i created this with the design option on the Form). i want to create a new Tab(only with code without designing) that contains gruopBox(g) exactly like groupbox1. GroupBox g = new GroupBox(); // g=groupbox1 will be Reference; // i want that 'g' will be like 'groupbox1' Thank you for your attention G. modified on Sunday, June 29, 2008 5:30 AM