It depends on what you really want. For example 3 Years and 2 months could be between 1154 and 1158 days depending on which months you're actually talking about and if a leap year was included. But I think for what you want you're going to have to just check the difference between the years/months/days yourself, I reckon something like this:
public struct Diff
{
public int Years;
public int Months;
public int Days;
};
//Will return incorrect negative values if end < start
public Diff Difference(DateTime start, DateTime end)
{
Diff diff = new Diff();
//Not as far into month, so it doesn't count
if (end.Day < start.Day)
{
end = end.AddMonths(-1);
//Calc diff
int remainDays = DateTime.DaysInMonth(start.Year, start.Month) - start.Day;
diff.Days = remainDays + end.Day;
}
else
diff.Days = end.Day - start.Day;
//Not as far into year, so it doesn't count
if (end.Month < start.Month)
{
end = end.AddYears(-1);
//Calc diff
diff.Months = 12 - (start.Month - end.Month);
}
else
diff.Months = end.Month - start.Month;
diff.Years = end.Year - start.Year;
return diff;
}
Which puts your example at 3 years and 3 months (and 13 days) since your further into September than you are into June, if you used 2008-06-12 ~ 2011-09-8 it would give 3 years 2 months 26 days. Which may or may not be quite what you want, but I think you get the idea. Edit: Fixed function, mustn't write code when sleepy
-SK Genius
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