Sorry, may I ask, why you try to do so? Do you try to solve HDD performance issue or save flash memory read-write cycles? Thanks!

Have you checked your spam filter? cheers Chris Maunder

computerpublic wrote: Somehow the logic doesn't seem to come to me Might help if you wrote your own class to do infinite digit integer handling. So you want a class that can take a 50 digit integer and add a different 50 digit integer to it. Each class instance represents a single number. So the add operation would look like the following. MyInt op1 = new MyInt("1000....001"); MyInt op2 = new MyInt("9000....019"); MyInt result = op1.add(op2);

Look at type catch (System.OverflowException e) { ... e is my variable name it is short for exception. It is not obligatory to use any name if you wanna catch OverflowException without more information.

You're meant to be teaching this course. What happens when a student asks you a question about something that is, after all, incredibly simple? Do you wait until the following week to give an answer, the same way that you whinged about a previous lecturer of yours? If you can't write this stuff, you shouldn't be teaching it.

If one is limited to basically "text" output, one can create a graph of sorts by outputting lines of various lengths; e.g. List> values = new List>() { new Tuple("Apples", 3), new Tuple("Peaches", 5), new Tuple("Pumpkins", 10), new Tuple("Pies", 7) }; foreach ( Tuple t in values ) { Console.WriteLine( "{0,10}: {1}", t.Item1, "".PadRight( t.Item2, '\*' ) ); } /* Apples: *** Peaches: ***** Pumpkins: ********** Pies: ******* */

This is a duplicate of http://www.codeproject.com/Messages/4770301/Invalid-Argument-in-For-Loop.aspx[^], where it was previously explained that what you are doing makes no sense and is just using memory to no puropse. Little wonder that it crashes. Once again, why not explain what problem you are trying to solve and maybe we can help you?

BillWoodruff wrote: If you really want #90 raised to the 18th. power, I think he wants 9 × (1018), not (9 × 10)18. "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

Hi again, using the Fisher-Yates shuffling algorithm [^] seems to be superior in performance: public static void Shuffle(T[] array) { Random rnd = new Random(); for (int i = array.Length - 1; i >= 0; i--) { int index = rnd.Next(i); T temp = array[index]; array[index] = array[i]; array[i] = temp; } }

That's true as it stands but I'm pretty sure that's not what's intended, because incrementing count multiple times can easily result in an out of range exception.

See http://msdn.microsoft.com/en-us/library/x1xda43a(v=vs.110).aspx[^].

Honestly, how are decimals easier to understand? Note, a byte is a value from 0 to 255. You convert it to decimal and it is a value from 0 to 255. Maybe you are getting confused by the term "binary". Binary means 2 things: A value that can be only 0 or 1. So, instead of seeing 255 you see 11111111. A representation of data that's not text-only. So, a byte is usually used to read binary data. This doesn't mean it only reads 0 or 1. It can still be seen as 0, 1, 2, 3, 100 etc... limited to 255. It is actually not limited to visible characters (so, it is not text). Your conversion from byte to decimal is only converting 8 bit values to 128 bit values that contain the same important data (a value from 0 to 255)... and then you are converting it back. So, it is not redundant. It is completely useless. Redundant is for those cases that it actually generates a result that could be easily obtained. In this case you are doing completely useless work. If what you want is to read a file that has lines like this: 01010101 11111111 00010001 And you want to understand those values, you need to: Read each line as string. Convert each string to a byte. Then, you convert the numeric value back to a string. So, 11111111 (binary) will become 255 (decimal). This is a decimal representation, not the decimal type.

/*If I am generating a series of bits ONE BIT AT A TIME for example {10101000}. How do I turn the entire series into one byte after I generate the 8th bit. I am trying to back track using the example you gave me, but I am getting some errors.*/ using System; using System.IO; using System.Collections; using System.Collections.Generic; using System.Linq; using System.Text; namespace Applica { class Program { static Random _random = new Random ();////Start: Fisher-Yates Array Shuffler public static void Shuffle<T>(T[] array) { var random = _random; for (int i = array.Length; i > 1; i--) { int j = random.Next(i); T tmp = array[j]; array[j] = array[i - 1]; array[i - 1] = tmp; } }////////////////////////////////////////////End: Fisher-Yates Array Shuffer static void Main(string[] args) { byte[] outdata = new byte[1]; BitArray[] bits2 = new BitArray[8]; char[] array = {'1','0','1','0','1','0','1','0'}; Shuffle(array); for (int i = 0; i < 8; i++) bits2[i] = array[1];//Error: Cannot Implicitly convert type 'char' to 'System.Collections.BitArray' outdata[i] = (byte)bits2;//Error: Cannot convert type 'System.Collections.BitArray[]' to 'byte' } } }

It should work without special effort. Did you verify that the bytes you give it are OK?

The issue you are hitting is because you are misusing BitConverter[^]. If you just want to convert a byte to an int, then you can simply assign the values across if you want to because a byte will upcast into an int quite happily. There's no need to do a conversion in this case.

Upvoted ! At the time I wrote my response to this thread, Richard's reply was not available here, which is becoming all too typical: there is often a gap of hours before content on QA and Forums shows up, and, yet, other parts of CodeProject seem to be updated instantly. Had I seen Richard's response, I would not have posted. “But I don't want to go among mad people,” Alice remarked. “Oh, you can't help that,” said the Cat: “we're all mad here. I'm mad. You're mad.” “How do you know I'm mad?” said Alice. “You must be," said the Cat, or you wouldn't have come here.” Lewis Carroll

Thank you. I really appreciate your help in this matter.

I agree in general but you know, statically, what the type of the second item of a Tuple is. If the Tuple is Tuple<T, U> then the type of the second item is U.

A Class (object) is the best way. But if you do not have more than two values, you can always use a Dictionary<>, or KeyValuePair etc System.Collections.Generic.Dictionary : http://msdn.microsoft.com/en-us/library/xfhwa508.aspx KeyValuePair : http://msdn.microsoft.com/en-us/library/5tbh8a42.aspx

I think it's been explained pretty well already, but just in case... static methods are available without an instance of the class. Non static methods are only available through an instance of the class. This gives you two options in your case. Either 1. Make the Test method static public static Double Test(Double Val1, Double Val2, Double Val3) or 2. Create a new instance of the class that holds the method (Program in this case). Double Result = new Program().Test(A,B,C); alternative Program program = new Program(); Double Result = program.Test(A,B,C); Dave Binging is like googling, it just feels dirtier. Please take your VB.NET out of our nice case sensitive forum. Astonish us. Be exceptional. (Pete O'Hanlon) BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)