Hi everyone, I would like to know if someone have experienced slow issues with Bitmap.SelectActiveFrame in a 64 bit system, or why is the method so much slower in a 64 bit system than in a 32 bit? Here is a sample code that I have used to test:

Bitmap m_bmp = new Bitmap("C:\\01.tif");
String m_Start = DateTime.Now.ToString("hh:mm:ss");
System.Diagnostics.Debug.WriteLine("Started at: " + m_Start);
for (Int32 a = 0; a < 22; a++)
{ m_bmp.SelectActiveFrame(FrameDimension.Page, a); }
String m_Finish = DateTime.Now.ToString("hh:mm:ss");
System.Diagnostics.Debug.WriteLine("Finished at: " + m_Finish.ToString());

The 01.tif file is a black & white image with 1bpp and 23 pages with 300dpi. Test made with Windows7 VS2010 .NetFramework 4.0 32 bit: Less than 1 second. Test made with Windows7 VS2010 .NetFramework 4.0 64 bit: 6 seconds. This is really a lot. Can someone be kind to help me ? Thank you. Best regards.

Scott Dorman wrote:

Not to sound flippant

Not at all, it is a old system, and probably they are processing the xml manually. X| Thanks again.

Hi and thank you for your answer. Yes, your are right, for me it doesn't matter. It is mattering for the other system that am communicating with. I was only trying to check if there was a reason for that or if I could do something about it. Best regards for all. :)

Hi again, Yes i know that. Even if you use the XmlWriteMode.WriteSchema with the xml, edit the schema with VS to match the order, read the edited file and save it again the result is the same. It simply doesn't maintain the order. Thanks ans best regards

Hello and thank you for your answer. And what is more interesting is that I have a xsd file with this xml and it still reorder the xml. X| Humm!

Hello everyone, I would like to know if someone has experienced this problem: I have a xml file:

<?xml version="1.0" standalone="yes"?>
<requests>
<request>
<idRequest>123</idRequest>
<requestType>001AA</requestType>
<subRequest>
<name>Some Name</name>
<birthDate>12-12-2007</birthDate>
<isbirthDateComplete>true</isbirthDateComplete>
</subRequest>
<observations>Some Observations...</observations>
<recordType>Insert</recordType>
</resquest>
</requests>

If I read the xml:

DataSet dsTest = new DataSet();
dsTeste.ReadXml(Application.StartupPath + "\\Test.xml");

and then write it back:

dsTest.WriteXml(Application.StartupPath + "\\Test1.xml");

it gives me:

<?xml version="1.0" standalone="yes"?>
<requests>
<request>
<idRequest>123</idRequest>
<requestType>001AA</requestType>
<observations>Some Observations...</observations>
<recordType>Insert</recordType>
<subRequest>
<name>Some Name</name>
<birthDate>12-12-2007</birthDate>
<isbirthDateComplete>true</isbirthDateComplete>
</subRequest>
</resquest>
</requests>

It simply change the order of the nodes. Is there any reason for this? Thanks in advance.

Hello In your connection string: dim MyConnection As String = "Provider= Microsoft.Jet.OLEDB.4.0; Data Source=MyDatabase.mdb;persist Security Info=False;Jet OLEDB:Database Password=sysadm" Where sysadm is your password. Tip: Don´t use that password :-D Regards

Hello The withevents key word means that you can enable the catching of events in that object. If you are accessing a class with events you need to insert that keyword to catch them.If not you can still access the methods, properties... but you won´t catch events. 'Main Form Private WithEvents Catch_Event as new Test Private Sub Test_Result (ByVal Value as Integer) Handles Catch_Event.Test_Result End Sub 'Class Test Public Class Test Public Event Test_Result (ByVal Value as Integer) Public Function StartEvent() RaiseEvent Test_Result (10) End Function End Class Hope it Helps

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Hello I Think you have to release the image. So try this: PictureBox1.Image.dispose PictureBox1.Image=Nothing Hope it helps

Hello You must allow your service to interact with the desktop. If you go to the properties of the service on the LogOn Tab you must check that item. Hope it helps

Hello Is there any way to get all the child nodes of a selected node? I just need a idea how to do this. Thanks you all

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Hello Dim pic_image As New Bitmap("c:\sample.jpg") MsgBox(pic_image.Size.Height & "---" & pic_image.Size.Width) Hope it helps

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Hello Is there any chance to get the row position in a table using a 'select' statement ? Thanks

Hello Yes you can. Just install the .Net framework on the Windows 98 computer. I dont know what windows 98 the .Net framwork is supported, but I am sure that in windows 98 SE it works.

Hello You can get more information here: http://www.ondotnet.com/pub/a/dotnet/2003/01/20/winformshosting.html?page=last&x-showcontent=text[^]

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