You only need two Parameters: 1. ZipFileName including destination directory 2. The file(s) you wish to zip including source directory. Robert

I see you asked this question in the SharpZipLib forums, that's probably your best bet. As far as I'm aware, there isn't a way to do this. I think you need to create a new zip without the password. Life, family, faith: Give me a visit. From my latest post: "When Constantine severed the Hebrew origins of this faith in Messiah, a new religion was officially created. It is this religion that Orthodox Jews fear their relatives and friends becoming members of." Judah Himango

Ah ok... But it's not possible to get the hostname/address from the SMTP server in C#?

The WSDL file needs <FileData>base64Binary</FileData> but I'm not sure how to convert my data from string to base64Binary. So I wrote the following: string FileDataBase64Binary; SoapBase64Binary base64Binary; FileDataBase64Binary = "???"; base64Binary = SoapBase64Binary.Parse(FileDataBase64Binary); request.FileData = base64Binary; Still not sure what must come by FileDataBase64Binary = "???"; Hope someone can explain to me how to do this? The files I need to send to the webservice are .zip files containing one .txt file.

Yes...I suppose you understand me. I did figure the following out: /* DECALRATIE */ string EmailAddress; string Filename; string FileDataBase64Binary; SoapBase64Binary base64Binary; MTOMDummy AddFileService; /* INITIALISATIE */ EmailAddress = "email@secret.nl"; Filename = "declaratie1.zip"; FileDataBase64Binary = "AgMFBws="; base64Binary = SoapBase64Binary.Parse(FileDataBase64Binary); AddFileService = new MTOMDummy(); AddFileRequestType request = new AddFileRequestType(); request.EmailAddress = EmailAddress; request.Filename = Filename; request.FileData = base64Binary; /* CALLING WEBSERVICE */ AddFileService.AddFile(request); Now is the object "request" filled with the email address, filename but not the filedata. The code above gives me the following error: Cannot implicitly convert type 'System.Runtime.Remoting.Metadata.W3cXsd2001.SoapBase64Binary' to 'byte[]' Any idea how to fill the "request.FileData" in the correct way?

Stream wav = Assembly.GetExecutingAssembly(). GetManifestResourceStream( MethodBase.GetCurrentMethod(). DeclaringType.Namespace + ".Resources." + "attention.wav"); (MethodBase.GetCurrentMethod().DeclaringType.Namespace assuming your calling from within the same namespace) Answered this for you in this thread[^] Dave modified on Wednesday, March 5, 2008 4:22 AM

Hi Ronald, there are some ways to solve your problem: 1. you can distribute your wav file in a specific subfolder of your application, e.g. Sounds. Then you just set the filename variable to the following value: string filename = Application.StartupPath + @"Sounds\attention.wav"; Don't forget to include using System.Windows.Forms. or type the namespace with the Application.StartupPath 2. You add the audio file as manifest into your exe. Then you need to call the following function: System.Reflection.Assembly.GetExecutingAssembly().GetManifestResourceStream(typeof(Program), "attention.wav") Note that you get a System.IO.Stream, so maybe need to save it in a temporary file and then call your PlaySound method (I don't know if your function supports a stream object as a parameter) So, these are the ways, I retrieved quickly from my mind at 23:17 :) (German time) PS: In the second solution I wrote typeof(Program). Program is a class generated by VisualStudio when you create a new project, so I used this here :) I hope I could help you _____________________________ The force of .NET is with me!