If you are talking about showing text in multiple lines, you can use Environment.NewLine constant to do that. TextBox1.Text = "Line 1" + Environment.NewLine + "Line 2" + Environment.NewLine + "Line 3";

Here is a sample code to accept the value(HTML) from a text field and gives the Plain text out of it: function Check(){ var pattern = new RegExp("<(.|\\n)*?>","g"); //alert(pattern); alert(document.formName.fieldName.value.replace(pattern,"")); } The HTML Portion : String : Text field can be replaced by reading the HTML content from .html file also. INPUT: My html page Hello world OUTPUT : My html page Hello world HTH Sovan

your local machine is NOT an email server. ASP.NET and IIS don't just magically route emails around the world. You NEED an email server send an email. health

hi thanks for the reply but in the code my document.getelementbyid(" ") is not finding the element so only i am using find method.. so now how to proceed plz... K.Gayathri

at first, i don't know why you don't use an it will give you what you want exactly with less effort if it is: it would be like that: you can create items in it dynamically like this: ListItem item = new ListItem("Text"); _radioButtonList.Items.Add(item); and to get SelectedItem , its Text or Value just do like that: ListItem item=_radioButtonList.SelectedItem; string selectedItemText=_radioButtonList.SelectedItem.Text; string selectedItemValue=_radioButtonList.SelectedValue; you can take SelectedValue in the Save Button Click Sincerely, Ibrahim Hebish | SharePoint Software Developer |GlobeSoft(Comp)| EX:EgyptNetwork(Comp) M: +201281744594 Email: Pronto.cs@gmail.com

hi thanks for the reply i am actually doing: i want an editor to be opened(as a new page say page2.aspx) on the click of a button or textarea and retreieve the values from the editor and get in inside the textarea in the first page.now on the click of the save button below the editor in page2.aspx the page should be closed and the values of the editor should be got in the textarea of page1.aspx K.Gayathri

thank you problem solved K.Gayathri

hi friends i am using the following code: int i = Convert.ToInt32(Session["Count"].ToString()); int k = 0; string[] strTextBoxValues = new string[] { }; for (k = 0; k <= i - 1; k++) { string textboxval = "DynamicTextbox" + Convert.ToString(k); TextBox textval = (TextBox)this.Page.FindControl(textboxval); textval.ID = textboxval; Response.Write(textval.Text); } but the findcontrol method returns null....and any one to help me in this issue as i am stuck in my work... K.Gayathri

Seeing that this is posted under asp.net i will give you a client side solution in "jQuery": function GenerateTextBoxes( sender ) { var txtBoxHtml = ''; sender.append( txtBoxHtml );//this will append a new textbox to the already existing ones } To make it easier for you, i added a css class (text-boxes) that you can later use to retrieve the values of your textboxes if need be and below is how you can achieve that using "jQuery": function GetTextBoxValues() { var arrayOfValues = []; $( '.text-boxes' ).each( function(){//loop through all the textboxes with this class names if( $(this).val() != '' ) { arrayOfValues.push( $(this).val() ); //and add the values to an array } }); } Hope that helps, Morgs

Check this Tip/Trick(It contains clear explanation about all things) Browser back button issue after logout[^] thatraja My Dad had a Heart Attack on this day so don't... Pompeyboy3 here | Nobody remains a virgin, Life screws everyone :sigh:

Please read some documentation before trying to use what you don't understand. http://msdn.microsoft.com/en-us/library/ff184050.aspx[^] http://msdn.microsoft.com/en-us/library/879kf95c.aspx[^] No comment

MalarGayu wrote: i am using form authentication using sqlserver as my database and not web.config   so that part i am ok as i can compare the values from the database using my own code and getting redirection to a secure page Your problem probable exists in how you are doing your authorization. It sounds like you are not using the default log-in and membership provider in asp.net by your statement above. Show us the code that you are using to log someone into your site.

yes thanks for all your reply got the logic of it..and understood K.Gayathri

Did you define the new column to not allow NULL ? If so, then you need to define a default value for that column.

MalarGayu wrote: the textbox is a webcontrol textbox.... I dont think that this is a issue. Is your button, textbox are on the same content page? One other way is, Register a javascript variable and assign the ClientId of textbox from Server side (C# code) and use that variable to get the ClientId of textbox in the validate method. Cheers!! Brij Microsoft MVP ASP.NET/IIS Visit my Blog: http://brijbhushan.net

Because the setting made by visual studio 10 are now applied to the project so that's why it's not opening

ASP.net deployement

Go to Project Property -> Web -> Start URL: http://localhost:xxxx/default.aspx Note: xxxx is port no. When you run the application you will see port no that IIS used. Thanks Parwej Ahamad

You can use Link Button,and to provide look like Linkbutton set properties as DEPARTMENTS