Yes, you can get IE developer Toolbar http://www.microsoft.com/downloads/details.aspx?familyid=e59c3964-672d-4511-bb3e-2d5e1db91038&displaylang=en[^] Or can view the source of page and search for the control.

Hello, I am using Asp.net treeview in my application. and on button next and previous I want to traverse through the treeview nodes back and forth. but the problem is, I can not get the property like : Node.NextNode or Node.PrevNode Again there is no property like Node.Index Will you please help me to resolve this problem? Regards, Milind

Yes I am doing it. I can get the values of all controls while postback except Fileuploadcontrol.

Hello, I have one Fileupload control in usercontrol. And I am loading usercontrol to in panel within updatepanel of page dynamically. So the scenario is like this : Masterpage --- Default.aspx ---- UpdatePanel --- ASP Panel ---- Usercontrol loaded according to user request. I have loading the usercontrol dynamically , As User can load the usercontrol multiple times I can able generate usercontrol while postback of the page. The problem is, When I click "Upload" button within usercontrol I am not getting postedfile of fileupload I have also tried following method in usercontrol to solve this problem , but no success yet <asp:UpdatePanel ID="UpdatePanel1" runat="server" UpdateMode="conditional"> <Triggers> <asp:PostBackTrigger ControlID="IbUploadT" /> </Triggers> <ContentTemplate> <asp:FileUpload ID="fupResource" runat="server" EnableViewState="true" /> <asp:ImageButton ID="IbUploadT" runat="server" ImageUrl="~/App_Themes/White/Images/Add.ICO" Height="16px" onclick="IbUploadT_Click" /> </ContentTemplate> </asp:UpdatePanel> Even though the page is postingback , I am not getting the postedfile of Fileupload Please help me. Regards, Milind

Hello, I have one treeview in updatepanel and one asp pannel(with visible = "false") out-side updatepanel. On selectedIndexchanged of treeview, I want a pannel outside of updatepanel needs to be visible. But it is not working. Is there any work around so that I can make my pannel visible w/o postback? Thanks in advance. Regards, Milind.

Hello, The requirement is file transfer via HTTP from local hard drive to Remote server via Http. And I want to show the directories of remote server so I can upload or download file/folder (just work like FTP does but via HTTP) I have one question about showing the virtual directories of remote server from web application in Asp.Net. Please guide me whether it is possible or not. Regards, Milind

I am using the control HTML Editor for ASP.NET AJAX How to Create an HTML Editor for ASP.NET AJAX[^] I want to get the value of the HtmlEditor control in javascript Thanks in advance Milind

Ohh Problem .... It is giving me error on control.RenderControl(htmlWriter) line. public string GetControlRenderedOutput(Control control) { StringBuilder builder = new StringBuilder(); StringWriter writer = new StringWriter(builder); HtmlTextWriter htmlWriter = new HtmlTextWriter(writer); control.RenderControl(htmlWriter); return builder.ToString(); } Error : RegisterForEventValidation can only be called during Render();

Thank you, It works

I am trying to get HTML containing in the Panel object (the panel is contaning tables and gridview)

Hello, I am using a panel control on page. I want a html of the pannel control in codebehind. Thanks in Advance Regards, Milind

Thank you Manas,

Hello, I want to store cookies of multiple user logged in different times on same pc. Is this possible? Thanks in advance Regards, Milind

Hello, I am trying to send email from Microsoft outlook from my application, and I wrote following code : string stSubject=""; string stTo=""; string stCC=""; string stAttachmentFileName = ""; string stDisplayName = ""; string stBody = ""; ApplicationClass oApplicationClass = new ApplicationClass(); NameSpace oNS = null; MailItem oMailItem= (MailItem)oApplicationClass.CreateItem(OlItemType.olMailItem); //stSubject is the mail subject oMailItem.Subject = stSubject; //stTo is the email to address // oMailItem.From = "m.r.chavan@amc.nl"; oMailItem.To = "aa@aa.nl"; oMailItem.CC = "bb@bb.nl"; oMailItem.BodyFormat = OlBodyFormat.olFormatHTML; //if you want it in the plain format, you can set body format as oMailItem.BodyFormat = Outlook.OlBodyFormat.olFormatPlain; oMailItem.HTMLBody = stBody; //oMailItem.Attachments.Add(stAttachmentFileName,(int)OlAttachmentType.olByValue,stBody.Length+1,stDisplayName); oMailItem.Display(true); Can anybody tell me how can i set the oMailItem.From in the mail, I know that the outlook is taking the default user account for mailing, but can I set the FROM property ?

Hello, I am using Microsoft reports with reportviewer control of Microsoft for my website. I have added one RLDC report file into my application and trying to open data sources from Report menu of VS designer. But I am getting following error : --------------------------- Microsoft Visual Studio --------------------------- Could not load file or assembly 'AjaxControlToolkit, Version=3.0.20820.16598, Culture=neutral, PublicKeyToken=28f01b0e84b6d53e' or one of its dependencies. The system cannot find the file specified. --------------------------- OK --------------------------- Please help me out to solve this problem, also if I have put this question in wrong forum. Regards, Milind

Hi, In that case, you can write a javscript function on onmouseover attribute, and in "Opendiv(para)" javascript method you can pass row index and show the appropriate data in DIV control. protected void gridview_RowDataBound(object sender, GridViewRowEventArgs e) { if (e.Row.RowType == DataControlRowType.DataRow) { e.Row.Attributes["onmouseover"] = "javascript:OpenDiv(" + e.Row.RowIndex + ");"; e.Row.Attributes["onmouseout"] = "javascript:CloseDiv();"; } } Regards, Milind

Hi, There are two ways you can do that. 1. If you are using Ajax Updatepannel then, you can easily get info from site http://www.asp.net/AJAX/AjaxControlToolkit/Samples/HoverMenu/HoverMenu.aspx[^] 2. if it is normal Aspx page with no ajax then, on each rowbound write code for mouse hover attribute eg. if (e.Row.RowType == DataControlRowType.DataRow) { e.Row.Attributes["onmouseover"] = "this.style.cursor='hand'"; e.Row.Attributes["onmouseout"] = "this.style.textDecoration='none';"; } you can also call javascript on onmouseover attribute. Regards, Milind

Hi, If the text boxes are not dynamic then it is very easy to make that as : so on and so forth .... in code behind protected void TextBox_TextChanged(object sender, EventArgs e) { TextBox txt = ((System.Web.UI.WebControls.TextBox)(sender)); } you can easily get which textbox changed event is called Regards, Milind

Hi, Just Test the mail by using following code add following in directives Imports System.Web.Mail and write following code : Dim mymsg As New MailMessage() mymsg.Fields.Add("http://schemas.microsoft.com/cdo/configuration/smtpserverport", "25") SmtpMail.SmtpServer = "mail.wunderman-amman.com" mymsg.From = "test@test.com" ' from email id mymsg.[To] = "test@test.com" ' to email id mymsg.Subject = "ATICO Newsletter" mymsg.BodyFormat = MailFormat.Html mymsg.Body = "test" SmtpMail.Send(mymsg) Regrads, Milind

Hi, Please set the 2 parameters before sending SMTP MailMessage : message.Fields.Add("http://schemas.microsoft.com/cdo/configuration/smtpserverport", "25"); SmtpMail.SmtpServer = "Server name"; //please specify your mail server name Again, check the anti virus setting for the smtp mails. Regards, Milind