Yes, it can be done from Find and Replace in two steps. Find: __\w+?\(" Replace: " Find: "\) Replace: "

Regex that I gave you will work whatever the string inside parentheses is. It focuses on removing the __X(" and "). You can use this one for any __X

string newExp = Regex.Replace(Regex.Replace(oldExp, @"__\w+?\(""", @""""), @"""\)", @"""");

Does this simple Regex.Replace work for you?

string oldExp = @"__X(""(whatever1)"") alpha __X(""whatever2"") beta";
string newExp = Regex.Replace(Regex.Replace(oldExp, @"__X\(""", @""""), @"""\)", @"""");

I have this text:

                        [18F-FMISO](https://www.sukl.eu/modules/medication/detail.php?kod=0242816 "Detail of medicinal product  18F-FMISO, 1-8GBQ INJ SOL 1GBQ")

I need REGEX that will return word between the last occurence of the </span> and </a>. That word in this case would be 18F-FMISO. How to do that?

I have this simple async web request code:

class AsyncResponse
{
public AsyncResponse()
{
test2();
Console.ReadKey();
}

    public void test2()
    {
  
        for (int i = 0; i < 100; i++)
        {
            string url = "https//www.google.com";

            HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
            request.BeginGetResponse(new AsyncCallback(FinishWebRequest), request);
        }
        
    }

    private void FinishWebRequest(IAsyncResult result)
    {       
            HttpWebResponse response = (result.AsyncState as HttpWebRequest).EndGetResponse(result) as HttpWebResponse;

            Console.WriteLine("Finished");
    }

}

I only got on console two "Finished" lines, meaning FinishWebRequest didn't get finished more then 2 times, but I have 100 requests. What is the issue?

Yes, I think

\w*bad boys\w*

will do it. It's MySQL Regex expression, and it seems that it works for both Latin and non-Latin characters.

I can't place [A-Za-z] since there will be also a non-Latin characters. It has to be .+

If I have string

1213 494 4 toobad boys 1234 4444

I want to match "bad boys" and everything before and after bad boys until word boundary \b. Something like this

"\\b.+?bad boys.+?\\b"

This returns

1213 494 4 toobad boys

and I want it to match "toobad boys" I know that the problem is "\\b.+?bad" which matches everything up to "bad boys", but instead it has to match everything before "bad boys" until word boundary \b. Help?

Vista is on customer's computer, I can't change that. I managed to install TLS 1.1 and TLS 1.2 using this guide Enable TLS 1.1/1.2 on Windows Vista | JohnHaller.com[^] but no TLS 1.3. I found a method to install .NET framework 4.8 on Vista, but not yet tried. Then it would be possible to use in app TLS 1.3. [Tutorial] How to install .Net Framework 4.8 on Windows Vista - Windows Vista - MSFN[^] If that doesn't work, only remaining option is to use third-party library like libcurl as suggested.

I have a C# app in .NET framework 4.6.1 where it uses WebClient.DownloadString(url) to download content from a url that uses TLS 1.3 and it throws exception because app is intended for a use on Windows Vista that doesn't have TLS 1.3 .NET framework 4.8 can't be installed on Vista. How can I solve this problem so that app can work on Vista?