The string literal actually looks exactly the same. In the Javascript you need to escape the backslash characters with a backslash character: var poboxPattern = new RegExp("^(APO|A\\.P\\.O\\.|A P O|FPO|F\\.P\\.O\\.|F P O|POB|P\\.O\\.B\\.|POBOX|P\\.O\\.BOX|PO BOX|P O BOX|P\\.O\\. BOX|POST OFFICE)"); In C#: RegEx postboxExpression = new RegEx("^(APO|A\\.P\\.O\\.|A P O|FPO|F\\.P\\.O\\.|F P O|POB|P\\.O\\.B\\.|POBOX|P\\.O\\.BOX|PO BOX|P O BOX|P\\.O\\. BOX|POST OFFICE)"); However, in C# you can also use a @ delimited string so that you don't need to escape the backslashes: RegEx postboxExpression = new RegEx(@"^(APO|A\.P\.O\.|A P O|FPO|F\.P\.O\.|F P O|POB|P\.O\.B\.|POBOX|P\.O\.BOX|PO BOX|P O BOX|P\.O\. BOX|POST OFFICE)"); Despite everything, the person most likely to be fooling you next is yourself.

thank a lot. I will let u know if that fixes the issue.

I think you should forget about regular expressions as a solution to your problem. You really should consider cleaning up and re-working your code first... at least for the learning experience. Learning how to do these types of manipulations is pretty important and, looking at your code, you're just not there, yet. All those temp variables and creating new strings in the loops area really expensive. Learn how strings work. Learn what immutable means and what happens when you build strings repeatedly within a loop. As a first step, start from the basics. Learn to traverse a string and manipulate it character by character (as you attempted above). Start with something like this: private string CleanString(string dirtyString) { StringBuilder cleanString = new StringBuilder(); // Learn what this does and why to use it foreach (char c in dirtyString) { // Note: C# strings are made up of 2-byte Unicode/UTF-16 characters, not ASCII characters. if ((c != '\u0009') || (c != '\u000B') ... etc. ) { // if character is not dirty, add it to the new string cleanString.Append(c); } } return (cleanString.ToString()); } Get that working, but then start using .NET's built in methods to improve your code. Next, read about string.IndexOf(char) so you can search the entire string at once for a character. Rewrite your code and get that working. Then, try creating an array of "dirty characters" so you can search for them all at once. Start by reading about this stuff: char[] dirtyChars = new char[] { '\u0009', '\u000B', ... etc. }; int dirtyIndex = dirtyString.IndexOfAny(dirtyChars); Then rewrite your code again and get it working. Then read about regular expressions, if you're curious. Will regular expressions work better? Maybe marginally... that's a really small "maybe." Probably not enough to matter. More readable?... I doubt it. Enjoy, Robert C. Cartaino modified on Wednesday, November 19, 2008 5:24 PM

You need to understand the algorithm to store data in a binary tree. It's not hard. Once you understand this, you can write the code yourself.

Additionally to what the others already said, there's also a slightly more advanced, yet more flexible solution: log4net[^] It has some nice features: - you can specify where the log messages should go (like to the console, to a file, via mail and much more) - you can add a custom format to your log messages (like a timestamp) - you can specify the type of the log message, like Info, Warning, Error, Debug and much more regards

1st, I think it's better that you write your LinkedList like this: LinkedList<string> ll = new LinkedList<string>(); LinkedListNode<string> lln = new LinkedListNode<string>(Console.ReadLine()); ll.AddFirst(lln); LinkedListNode<string> Prelln = null; while (true) { Prelln = lln; // Save the current Node, string input = Console.ReadLine(); if (input == "End") // If user type "End", Done! break; lln = new LinkedListNode<string>(input); // Otherwise, Add a new Node ll.AddAfter(Prelln, lln); // Add new Node after previous saved Node } It takes less memory. [Edit] However, It's your choice ;) [\Edit] 2nd, a simple foreach gets you your nodes, for this example: foreach (string i in ll) Console.WriteLine(i); While (true) { Human.isLearnable = true; } modified on Tuesday, October 21, 2008 2:41 PM

thanks anyway. I appreacute any answer :)

leppie wrote: Environment.NewLine.Length = 2 Yes, in Microsoft's implementation of the CLR. If you run the same program in Mono on Linux, the length is one. :) Despite everything, the person most likely to be fooling you next is yourself.

Good to see you again, professor :) "The clue train passed his station without stopping." - John Simmons / outlaw programmer "Real programmers just throw a bunch of 1s and 0s at the computer to see what sticks" - Pete O'Hanlon "Not only do you continue to babble nonsense, you can't even correctly remember the nonsense you babbled just minutes ago." - Rob Graham

I suppose that you want spaces in place of the line breaks? msg = msg.Replace("\r\n", " "); Despite everything, the person most likely to be fooling you next is yourself.

You could take the huge pattern and append |(&nbsp;|\s)+. But you cannot control what the pattern is replaced with - that's in some other place in the code, where the GetRegExpStripHTML().Replace method is called. I would suggest removing the GetRegExpStripHTML() method and instead providing a CleanupHTML(string) method - that way, you can apply multiple regular expressions and don't have to do everything with a single replacement using a monster pattern.