You're welcome! Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...

You're welcome! Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...

Then use Process.Start() and point to either the debug version or the release version. There are only 10 types of people in the world, those who understand binary and those who don't.

That's a LOT better! Too bad, it's never going to work. You can launch your process (script) on the remote machine. The problem is, because of security concerns, it's not allowed to put up any kind of user interface. The user on the machine will NEVER see the dialog box or anything that asks for input from the user on the remote machine. I think the security implications of code being launched on a users machine from an unknown remote server are quite obvious. There is no way to get around this. What's the purpose of this script running on the remote machine? A guide to posting questions on CodeProject Click this: Asking questions is a skill. Seriously, do it. Dave Kreskowiak

Thank you very much.... i don't even know what the error was. I had to restart the server, and now it works without doing anything :D but thank you :D

As Dave said, you cannot do this. You would have to install a client version of your software that is listening on a certain port. Then you can have a server version of your software that sends messages on that port. However, if you do not need to ask for input and all machines are Win7 or higher, you can use msg. Open a command line and type msg and you'll see the options, http://pcsupport.about.com/od/commandlinereference/p/msg-command.htm[^]. There are only 10 types of people in the world, those who understand binary and those who don't.

Sascha Lefèvre wrote: DateTime- Keep in mind that unfortunately, DateTime, ignores time zone. One should not confuse that with, for example, assuming that it is the same as UTC, because that would be wrong. One should strive to use DateTimeOffset instead.

your welcome... Pankaj Maurya Sr. Software Engineer Gurgaon, India

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Do you really think OP is still waiting for a reply after 9 months?

Okay but how can I show that it is searching?

You can use the SqlQuery method[^] on the Database[^] to execute a raw query: IEnumerable<string> tables = context.Database.SqlQuery<string>("SELECT QUOTENAME(s.name) + '.' + QUOTENAME(t.name) As TableName FROM sys.tables As t INNER JOIN sys.schemas As s ON s.schema_id = t.schema_id ORDER BY s.name, t.name"); Entity Framework Raw SQL Queries[^] "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

:thumbsup: Super! Thanks!

The error message is quite clear - "An item with the same key has already been added". In your dictionary initializer, you have added the key "Inventurart" twice - the 6th and 29th items. Remove one of those items. "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer