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Math Problem ...

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  • P Paul Conrad

    Can't you just accept the fact someone else came up with an easier solution than yours (and yours is correct, too)? You can't even get horizontal and vertical lines correct. Division by zero occurs when you have a vertical line. I knew this BEFORE you were even born. Mr. Losinger even pointed out math errors in your one post.

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    Ed Poore
    wrote on last edited by
    #36

    If I've understood the post correctly he wants to get 20% of the line between the two points.  Agree? If so then how can you simply take 20% of the width of the "triangle" formed and "20%" of the height to get a hypotenuse that is 20% of the original triangle? If you use Pythagoras it'll show you that if you do that you'll actually get a hypotenuse that's ~28% of the original rather than 20%.


    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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    • P Paul Conrad

      Can't you just accept the fact someone else came up with an easier solution than yours (and yours is correct, too)? You can't even get horizontal and vertical lines correct. Division by zero occurs when you have a vertical line. I knew this BEFORE you were even born. Mr. Losinger even pointed out math errors in your one post.

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      Ed Poore
      wrote on last edited by
      #37

      Oooooooooopppppppppppssssssssssssssss :doh::doh::doh::doh::doh: :-O:-O:-O:-O:-O Now I know I should go to bed, sorry I've completely ballsed this up havn't I, just got a pencil and paper out to work it out, forgot to substitute for cos and sin :doh: Combination of too much revision and a late night.


      Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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      • R Ray Kinsella

        Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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        Denevers
        wrote on last edited by
        #38

        man.. these guys like complicated solutions :) let's p be the proportion of the line (0.2) x = (a * (1-p)) + (c * p) y = (b * (1-p)) + (d * p) unless I blew it.. this should work with any lines. Denevers -- modified at 18:08 Tuesday 13th June, 2006

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        • E Ed Poore

          If I've understood the post correctly he wants to get 20% of the line between the two points.  Agree? If so then how can you simply take 20% of the width of the "triangle" formed and "20%" of the height to get a hypotenuse that is 20% of the original triangle? If you use Pythagoras it'll show you that if you do that you'll actually get a hypotenuse that's ~28% of the original rather than 20%.


          Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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          Paul Conrad
          wrote on last edited by
          #39

          Though it does not qualify as an actual mathematical proof, I've tested your approach and Jun Du's approach in Excel with 10-15 different values and I get the same results. Remember that: θ = arctan( y / x ) x = cos( θ ) y = sin( θ ) from Inverse Tangent[^] You wrote: θ = arctan((d - b) / (c - a)) x = a + (0.2*|AB|*cos(θ) y = b + (0.2*|AB|*sin(θ) and based on the link from MathWorld, (c-a) = cos( θ ) and (d-b) = sin( θ ) PJC

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          • C Chris Losinger

            yup. he was right up until the last little bit of arithmetic. Cleek | Image Toolkits | Thumbnail maker

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            Ed Poore
            wrote on last edited by
            #40

            Chris Losinger wrote:

            he was right up until the last little bit of arithmetic.

            Yep, I've now confirmed that I've been a complete and utter nincompoop, see http://www.codeproject.com/lounge.asp?msg=1530321#xx1530321xx[^] for my explanation and excuses.  I now realise I was barking up the wrong tree :doh:


            Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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            • P Paul Conrad

              Though it does not qualify as an actual mathematical proof, I've tested your approach and Jun Du's approach in Excel with 10-15 different values and I get the same results. Remember that: θ = arctan( y / x ) x = cos( θ ) y = sin( θ ) from Inverse Tangent[^] You wrote: θ = arctan((d - b) / (c - a)) x = a + (0.2*|AB|*cos(θ) y = b + (0.2*|AB|*sin(θ) and based on the link from MathWorld, (c-a) = cos( θ ) and (d-b) = sin( θ ) PJC

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              Ed Poore
              wrote on last edited by
              #41

              I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


              Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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              • E Ed Poore

                I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


                Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                Paul Conrad
                wrote on last edited by
                #42

                Ed.Poore wrote:

                I stand corrected and apologise if I was dogmatic .

                Hey it's cool. It happens.

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                • C Chris Losinger

                  yup. he was right up until the last little bit of arithmetic. Cleek | Image Toolkits | Thumbnail maker

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                  Paul Conrad
                  wrote on last edited by
                  #43

                  Chris Losinger wrote:

                  he was right up until the last little bit of arithmetic.

                  I had that happen when I was in Calculus 15 years ago. It happens. The teacher dinged everyone on arithmetic mistakes even if we displayed knowledge of the material. Now I look back at those old midterm exams and laugh. PJC

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                  • E Ed Poore

                    I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


                    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                    Chris Losinger
                    wrote on last edited by
                    #44

                    happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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                    • C Chris Losinger

                      happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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                      Paul Conrad
                      wrote on last edited by
                      #45

                      When substituting cos θ by

                           x2 - x1 
                      


                      √(y2 - y1)² + (x2 - x1)²

                      the magnitude of the two vectors cancel out and you are left with

                           x2 - x1
                      

                      With the equation for the y component, sin θ is substituted by

                           y2 - y1
                      


                      √(y2 - y1)² + (x2 - x1)²

                      the magnitude of the two vectors cancelled out again and you are left with

                           y2 - y1
                      

                      So in Jun Du's method, the magnitude of the two vectors and the trig functions drop out. PJC

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                      • E Ed Poore

                        I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


                        Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                        Paul Conrad
                        wrote on last edited by
                        #46

                        As a friendly suggestion, I would recommend bookmarking the www.mathworld.com[^] link. I use it often as a good web reference :) Paul

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                        • R Ray Kinsella

                          Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                          yang__lee
                          wrote on last edited by
                          #47

                          here it is suppose a and b are points.. I want point C 20% from point a then c.x= a.x+ 0.2 * (distnce between a & b ) * cos (angle between a and b ); c.Y= a.y+ 0.2 * (distnce between a & b ) * sin (angle between a and b ); Leya -- modified at 3:04 Wednesday 14th June, 2006

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                          • R Ray Kinsella

                            Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                            Baconbutty
                            wrote on last edited by
                            #48

                            Use a tape measure :) I still remember having to write your own code in FORTRAN rather than be a cut and paste merchant being pampered by colour coded Intellisense - ahh proper programming - those were the days :)

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                            • P Paul Conrad

                              As a friendly suggestion, I would recommend bookmarking the www.mathworld.com[^] link. I use it often as a good web reference :) Paul

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                              Ed Poore
                              wrote on last edited by
                              #49

                              I know about MathWorld since I've got a copy of Mathematica, it's just I was being blind to the obvious yesterday, was feeling a bit more awake today but then sat down outside to read a book in the sun, big mistake.. Fell alseep.


                              Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                              • C Chris Losinger

                                happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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                                Ed Poore
                                wrote on last edited by
                                #50

                                Chris Losinger wrote:

                                happens to the best of us

                                God I hope you're not implying I'm one of the best :laugh: Far from it.


                                Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

                                1 Reply Last reply
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                                • B Baconbutty

                                  Use a tape measure :) I still remember having to write your own code in FORTRAN rather than be a cut and paste merchant being pampered by colour coded Intellisense - ahh proper programming - those were the days :)

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                                  Ed Poore
                                  wrote on last edited by
                                  #51

                                  I was told I was making things too complicated (which I was by the way), I think you're oversimplifying a bit here :laugh: But it's the most realiable method, I've got to give you that.


                                  Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

                                  1 Reply Last reply
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                                  • E Ed Poore

                                    I know about MathWorld since I've got a copy of Mathematica, it's just I was being blind to the obvious yesterday, was feeling a bit more awake today but then sat down outside to read a book in the sun, big mistake.. Fell alseep.


                                    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                    Paul Conrad
                                    wrote on last edited by
                                    #52

                                    Ed.Poore wrote:

                                    Mathematica

                                    I've always liked mathematica. Haven't worked with it in some time :sigh:

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                                    • P Paul Conrad

                                      Ed.Poore wrote:

                                      Mathematica

                                      I've always liked mathematica. Haven't worked with it in some time :sigh:

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                                      Ed Poore
                                      wrote on last edited by
                                      #53

                                      Havn't used it much but liked what I saw, but I find it's more fun to program your own stuff rather than getting Mathematica to do it. Mind you, you do get a sense of satisfaction when asking it to calculate Pi to 5,000,000 places, you think it's crashed and then you go off to supper, lo and behold when you come back it's done it.


                                      Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

                                      P 1 Reply Last reply
                                      0
                                      • R Ray Kinsella

                                        Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                                        L Offline
                                        Lost User
                                        wrote on last edited by
                                        #54

                                        Ray Kinsella wrote:

                                        I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ?

                                        Ask an Asian? Michael Martin Australia "I controlled my laughter and simple said "No,I am very busy,so I can't write any code for you". The moment they heard this all the smiling face turned into a sad looking face and one of them farted. So I had to leave the place as soon as possible." - Mr.Prakash 24/04/2004

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                                        • E Ed Poore

                                          Havn't used it much but liked what I saw, but I find it's more fun to program your own stuff rather than getting Mathematica to do it. Mind you, you do get a sense of satisfaction when asking it to calculate Pi to 5,000,000 places, you think it's crashed and then you go off to supper, lo and behold when you come back it's done it.


                                          Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                          Paul Conrad
                                          wrote on last edited by
                                          #55

                                          Ed.Poore wrote:

                                          it's more fun to program your own stuff rather than getting Mathematica to do it

                                          I agree. It's nice to use a tool like Mathematica to check the program to ensure it is working correctly :) Took a Graduate course called Super Visualization and tools like Mathematica and SciLab were quite useful.

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