Maths recommendation.
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I googled and found this page, which explains a vector projection simply enough. Seems like you just place two vectors at the same origin. You then create a triangle by connecting the tip of one to the side of the second using a line perpendicular to the second (so a triangle with one 90 degree corner). Take the vector created by connecting the origin to that point on the second vector where the perpendicular line connects, and you have your vector projection. I am not sure what it is used for in 2D physics.
aspdotnetdev wrote:
Seems like you just place two vectors at the same origin. You then create a triangle by connecting the tip of one to the side of the second using a line perpendicular to the second (so a triangle with one 90 degree corner). Take the vector created by connecting the origin to that point on the second vector where the perpendicular line connects, and you have your vector projection.
That is all I needed to figure it out! :-D
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I (easily) passed the courses Graphics (50% of it was linear algebra), Data-structures (mostly about algorithmic complexity) and even Cryptography without passing the 1st-year Maths course (not until I re-did it for the 3rd time). Knowing a lot about maths may not be as important as they want you to think..
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What are those in CGPA?
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I presume you un univoted me. Thanks But really, how hard is sums? Look it is all just algebra and functions, and once you get that then all is clear.
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
Dalek Dave wrote:
I presume you un univoted me.
I didnt mean to offend you! I take advise seriously so thank you ! :-D
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I dont want to die young :laugh:
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I presume you un univoted me. Thanks But really, how hard is sums? Look it is all just algebra and functions, and once you get that then all is clear.
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
I could swear I did the first time around! Rectified.
Dalek Dave wrote:
But really, how hard is sums?
I don't find them hard, but some were quite tedious. Some of the expansions and transforms that we did back in school.. a recipe for a headache. However, when I first tackled my MS degree, I was dumbstruck by how much harder it was for me to do, what I previously considered simple, calculus. I am certain it was due to my lack of practice.
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I meant the 2.1 and 2.2 :)
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Sadly I have looked there, just seems to be too much association with maths terms I am not familiar with ie: "The vector resolute (also known as the vector projection) of two vectors, A in the direction of B (also A on B")" ... tells me that a projection is a direction between two vectors... The math symbols used some of which I know (dot product for example I know returns a number representing a vectors direction ie 0), but make it hard for me to just look at and understand :(
Ultimately, what it means is that a vector projection is nothing more than the compound of two vectors. An analogy. Two billiard balls approaching each other. Upon collision, if we were to consider only one of them, what is the new vector it results with, due to the impact, starting at the point of impact. Easy, eh? :)
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I meant the 2.1 and 2.2 :)
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I clicked the thumb up though like all comments so far :doh: You deserve a 5 I am trying to click them and it appears to be working.
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I meant the 2.1 and 2.2 :)
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All modules at 'just passed' except the finals, which were boosted by the oral digression and the essays. My finals were a little bland and normal, I feel I am far better at physics than my degree shows, but I can't prove it.
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
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Ultimately, what it means is that a vector projection is nothing more than the compound of two vectors. An analogy. Two billiard balls approaching each other. Upon collision, if we were to consider only one of them, what is the new vector it results with, due to the impact, starting at the point of impact. Easy, eh? :)
If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?
Only easy in conventional physics. Now try it at the quantum level! :) Wonderful....One of them turns into a whale and the other, a bowl of petunias!
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
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I dont want to die young :laugh:
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All modules at 'just passed' except the finals, which were boosted by the oral digression and the essays. My finals were a little bland and normal, I feel I am far better at physics than my degree shows, but I can't prove it.
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
Dalek Dave wrote:
All modules at 'just passed' except the finals, which were boosted by the oral digression and the essays.
OK, Gotcha
Dalek Dave wrote:
which were boosted by the oral digression
That sounds a bit... racy and more like a bribe! :-D
Dalek Dave wrote:
My finals were a little bland and normal, I feel I am far better at physics than my degree shows, but I can't prove it.
I can sympathize with that.
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Only easy in conventional physics. Now try it at the quantum level! :) Wonderful....One of them turns into a whale and the other, a bowl of petunias!
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]
Ah, but that's when you break out the bistro mathematics and the cup of coffee...
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Ultimately, what it means is that a vector projection is nothing more than the compound of two vectors. An analogy. Two billiard balls approaching each other. Upon collision, if we were to consider only one of them, what is the new vector it results with, due to the impact, starting at the point of impact. Easy, eh? :)
If the post was helpful, please vote, eh! Current activities: Playing Star Craft II. Don't bother me, eh? Now and forever, defiant to the end. What is Multiple Sclerosis[^]?
Mustafa Ismail Mustafa wrote:
Two billiard balls approaching each other. Upon collision, if we were to consider only one of them, what is the new vector it results with, due to the impact, starting at the point of impact.
Very easy to understand :D So a ball falling from the sky at an angle when it hits the projection would be the vector that the ball will "bounce" towards?
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Mustafa Ismail Mustafa wrote:
Two billiard balls approaching each other. Upon collision, if we were to consider only one of them, what is the new vector it results with, due to the impact, starting at the point of impact.
Very easy to understand :D So a ball falling from the sky at an angle when it hits the projection would be the vector that the ball will "bounce" towards?
Correct :) To be pedantic, the "ball falling from the sky at an angle" is the ball and its vector details, the angle being the direction in 2D/3D space (depending on how you see it) and upon "impact" with another vector (even an immobile has a vector) results with a projection, again each one has a projection.
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Apparently my thinking apparatus is having a little trouble today, because I don't see any connection between engineering, medicine and dance, other than that they all appear in your post.
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Some more subconsciously than others.
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Some more subconsciously than others.
The best lesson I ever had... I want you to observe an object falling through space, then , having observed, enable via an interaction, immediately, to interject a second object, freely, to interupt the ballistic path of the first object, and, by doing so, cessate the conclusion of its path, taking into consideration such divers data as freefall path, gravity, air resistance and procedural lagging and show, through empirical means, that such an interaction is both possible and, via completion, achievable, in a time frame that is shorter than that achievable by the frame available to that of concious thought. It was easy... Catch!
------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC League Table Link CCC Link[^]