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performance puzzle

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  • D Derek Viljoen

    Mechanical, I checked your profile. You've never authored an article, posted a snippet, entered a blog post, or otherwise shared any original thought, except to snipe at other people's comments on the message boards. In other words, you have yet to provide any empirical evidence for your worth to this site. No be a good boy and go away, please.

    M Offline
    M Offline
    Mechanical
    wrote on last edited by
    #53

    Derek Viljoen wrote:

    In other words, you have yet to provide any empirical evidence for your worth to this site. No be a good boy and go away, please.

    You have much to learn, little one.

    NULL

    R 1 Reply Last reply
    0
    • L Lost User

      Post it?

      S Offline
      S Offline
      Super Lloyd
      wrote on last edited by
      #54

      okay, I ran it from the command line and attached a debugger, here is the release version, run and optimized at its best I guess. what do you think? (well, if you can read that! :~ ) (no inline C# comment this time!) ===============================================

      00000000 push ebp
      00000001 mov ebp,esp
      00000003 push edi
      00000004 push esi
      00000005 push ebx
      00000006 sub esp,48h
      00000009 mov esi,ecx
      0000000b lea edi,[ebp-54h]
      0000000e mov ecx,12h
      00000013 xor eax,eax
      00000015 rep stos dword ptr es:[edi]
      00000017 mov ecx,esi
      00000019 mov dword ptr [ebp-10h],esp
      0000001c mov dword ptr [ebp-54h],496CC9B0h
      00000023 cmp dword ptr [ecx+4],1
      00000027 je 00000043
      00000029 call 620CD310
      0000002e mov ecx,eax
      00000030 mov edx,dword ptr ds:[03522030h]
      00000036 mov eax,dword ptr [ecx]
      00000038 call dword ptr [eax+000000D8h]
      0000003e jmp 0000017B
      00000043 cmp dword ptr [ecx+4],0
      00000047 jbe 00000191
      0000004d mov esi,dword ptr [ecx+0Ch]
      00000050 call 620C0CC0
      00000055 push eax
      00000056 mov ecx,esi
      00000058 mov edx,7
      0000005d call 620CF2F0
      00000062 mov ebx,eax
      00000064 lea edi,[ebp-30h]
      00000067 xor eax,eax
      00000069 stos dword ptr es:[edi]
      0000006a stos dword ptr es:[edi]
      0000006b lea ecx,[ebp-30h]
      0000006e call 62069650
      00000073 call 62069730
      00000078 mov ecx,eax
      0000007a lea eax,[ebp-30h]
      0000007d push dword ptr [eax+4]
      00000080 push dword ptr [eax]
      00000082 lea edx,[ebp-18h]
      00000085 mov eax,dword ptr [ecx]
      00000087 call dword ptr [eax+48h]
      0000008a mov ecx,801h
      0000008f push 0
      00000091 dec ecx
      00000092 jne 0000008F
      00000094 mov ecx,esp
      00000096 mov dword ptr [ebp-10h],esp
      00000099 mov esi,ecx
      0000009b jmp 000000DA
      0000009d xor edx,edx
      0000009f mov byte ptr [esi+edx],1
      000000a3 inc edx
      000000a4 cmp edx,2001h
      000000aa jl 0000009F
      000000ac mov ecx,2
      000000b1 cmp byte ptr [esi+ecx],0
      000000b5 je 000000D1
      000000b7 mov edx,ecx
      000000b9 add edx,edx
      0000

      L D 2 Replies Last reply
      0
      • D Daniel Grunwald

        Super Lloyd wrote:

        Ha, the disassembly I got it from VS! Not sure how to get it otherwise...

        To get the optimized JITted assembly code, you need to run your program from the command line, then attach the debugger to the running process, and click Break. Because your Main function was already running before you attached the debugger, it will still have the real native code. .NET doesn't re-jit anything when attaching a debugger.

        S Offline
        S Offline
        Super Lloyd
        wrote on last edited by
        #55

        Thanks, done! Posted there: http://www.codeproject.com/Lounge.aspx?msg=3657593#xx3657593xx[^] However, I'm not conversant in ASM, so I can't tell much from it...

        A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

        1 Reply Last reply
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        • S Super Lloyd

          okay, I ran it from the command line and attached a debugger, here is the release version, run and optimized at its best I guess. what do you think? (well, if you can read that! :~ ) (no inline C# comment this time!) ===============================================

          00000000 push ebp
          00000001 mov ebp,esp
          00000003 push edi
          00000004 push esi
          00000005 push ebx
          00000006 sub esp,48h
          00000009 mov esi,ecx
          0000000b lea edi,[ebp-54h]
          0000000e mov ecx,12h
          00000013 xor eax,eax
          00000015 rep stos dword ptr es:[edi]
          00000017 mov ecx,esi
          00000019 mov dword ptr [ebp-10h],esp
          0000001c mov dword ptr [ebp-54h],496CC9B0h
          00000023 cmp dword ptr [ecx+4],1
          00000027 je 00000043
          00000029 call 620CD310
          0000002e mov ecx,eax
          00000030 mov edx,dword ptr ds:[03522030h]
          00000036 mov eax,dword ptr [ecx]
          00000038 call dword ptr [eax+000000D8h]
          0000003e jmp 0000017B
          00000043 cmp dword ptr [ecx+4],0
          00000047 jbe 00000191
          0000004d mov esi,dword ptr [ecx+0Ch]
          00000050 call 620C0CC0
          00000055 push eax
          00000056 mov ecx,esi
          00000058 mov edx,7
          0000005d call 620CF2F0
          00000062 mov ebx,eax
          00000064 lea edi,[ebp-30h]
          00000067 xor eax,eax
          00000069 stos dword ptr es:[edi]
          0000006a stos dword ptr es:[edi]
          0000006b lea ecx,[ebp-30h]
          0000006e call 62069650
          00000073 call 62069730
          00000078 mov ecx,eax
          0000007a lea eax,[ebp-30h]
          0000007d push dword ptr [eax+4]
          00000080 push dword ptr [eax]
          00000082 lea edx,[ebp-18h]
          00000085 mov eax,dword ptr [ecx]
          00000087 call dword ptr [eax+48h]
          0000008a mov ecx,801h
          0000008f push 0
          00000091 dec ecx
          00000092 jne 0000008F
          00000094 mov ecx,esp
          00000096 mov dword ptr [ebp-10h],esp
          00000099 mov esi,ecx
          0000009b jmp 000000DA
          0000009d xor edx,edx
          0000009f mov byte ptr [esi+edx],1
          000000a3 inc edx
          000000a4 cmp edx,2001h
          000000aa jl 0000009F
          000000ac mov ecx,2
          000000b1 cmp byte ptr [esi+ecx],0
          000000b5 je 000000D1
          000000b7 mov edx,ecx
          000000b9 add edx,edx
          0000

          L Offline
          L Offline
          Lost User
          wrote on last edited by
          #56

          Is it a Debug build?

          S 1 Reply Last reply
          0
          • S Super Lloyd

            okay, I ran it from the command line and attached a debugger, here is the release version, run and optimized at its best I guess. what do you think? (well, if you can read that! :~ ) (no inline C# comment this time!) ===============================================

            00000000 push ebp
            00000001 mov ebp,esp
            00000003 push edi
            00000004 push esi
            00000005 push ebx
            00000006 sub esp,48h
            00000009 mov esi,ecx
            0000000b lea edi,[ebp-54h]
            0000000e mov ecx,12h
            00000013 xor eax,eax
            00000015 rep stos dword ptr es:[edi]
            00000017 mov ecx,esi
            00000019 mov dword ptr [ebp-10h],esp
            0000001c mov dword ptr [ebp-54h],496CC9B0h
            00000023 cmp dword ptr [ecx+4],1
            00000027 je 00000043
            00000029 call 620CD310
            0000002e mov ecx,eax
            00000030 mov edx,dword ptr ds:[03522030h]
            00000036 mov eax,dword ptr [ecx]
            00000038 call dword ptr [eax+000000D8h]
            0000003e jmp 0000017B
            00000043 cmp dword ptr [ecx+4],0
            00000047 jbe 00000191
            0000004d mov esi,dword ptr [ecx+0Ch]
            00000050 call 620C0CC0
            00000055 push eax
            00000056 mov ecx,esi
            00000058 mov edx,7
            0000005d call 620CF2F0
            00000062 mov ebx,eax
            00000064 lea edi,[ebp-30h]
            00000067 xor eax,eax
            00000069 stos dword ptr es:[edi]
            0000006a stos dword ptr es:[edi]
            0000006b lea ecx,[ebp-30h]
            0000006e call 62069650
            00000073 call 62069730
            00000078 mov ecx,eax
            0000007a lea eax,[ebp-30h]
            0000007d push dword ptr [eax+4]
            00000080 push dword ptr [eax]
            00000082 lea edx,[ebp-18h]
            00000085 mov eax,dword ptr [ecx]
            00000087 call dword ptr [eax+48h]
            0000008a mov ecx,801h
            0000008f push 0
            00000091 dec ecx
            00000092 jne 0000008F
            00000094 mov ecx,esp
            00000096 mov dword ptr [ebp-10h],esp
            00000099 mov esi,ecx
            0000009b jmp 000000DA
            0000009d xor edx,edx
            0000009f mov byte ptr [esi+edx],1
            000000a3 inc edx
            000000a4 cmp edx,2001h
            000000aa jl 0000009F
            000000ac mov ecx,2
            000000b1 cmp byte ptr [esi+ecx],0
            000000b5 je 000000D1
            000000b7 mov edx,ecx
            000000b9 add edx,edx
            0000

            D Offline
            D Offline
            Daniel Grunwald
            wrote on last edited by
            #57

            That looks quite similar to the C++ assembler code! Here, compare the main loop bodies. I've added annotations to the C# assembler code. C#:

            000000b1 cmp byte ptr [esi+ecx],0 // primes[i] != 0
            000000b5 je 000000D1
            // if (primes[i] != 0) {
            000000b7 mov edx,ecx
            000000b9 add edx,edx // int k = 2 * i
            000000bb cmp edx,2001h // k < end
            000000c1 jge 000000D1
            // for {
            000000c3 mov byte ptr [esi+edx],0 // primes[k] = 0;
            000000c7 add edx,ecx // k += i
            000000c9 cmp edx,2001h // k < end
            000000cf jl 000000C3
            // }
            // }
            000000d1 inc ecx // ++i
            000000d2 cmp ecx,2001h // i < end
            000000d8 jl 000000B1

            C++:

                                if (primes\[i\] != 0)
            

            002610A0 cmp byte ptr [esp+ecx+10h],bl
            002610A4 je wmain+0BDh (2610BDh)
            {
            int p = i; // using this extra variable speeds up C++!!! (and slow down C# if I do it)
            for (int k = i + p; k < end; k += p)
            002610A6 lea eax,[ecx+ecx]
            002610A9 cmp eax,2001h
            002610AE jge wmain+0BDh (2610BDh)
            primes[k] = 0;
            002610B0 mov byte ptr [esp+eax+10h],bl
            002610B4 add eax,ecx
            002610B6 cmp eax,2001h
            002610BB jl wmain+0B0h (2610B0h)

            	for (int i = begin; i < end; ++i)
            

            002610BD inc ecx
            002610BE cmp ecx,2001h
            002610C4 jl wmain+0A0h (2610A0h)

            The C++ compiler was a bit more clever in combining mov+add into lea, but other than that, the instructions are identical. C++ also lifted the 0 literal into a register (bl), but I'm not sure if that gives you a performance advantage over immediates. (this optimization does give you a code size advantage though, at least for data types larger than 1 byte) So I'm not sure if this small optimization (lea) is causing the difference in performance, or if the reason for the difference is outside this loop. Because there's a major difference in the 'reset to 1' loop: C# resets each byte individually, whereas C++ calls the much faster memset. You could try rewriting that C# loop to:

                        int\* primesInt = (int\*)primes;
            	for (int i = 0; i < ((end-1)/sizeof(int))+1; i++)
            		primesInt\[i\] = 0x01010101;
            

            Maybe even try if long is faster on your machine. In fact, I have the suspicion that the C++ memset might use SSE registers to set 16 ele

            S 1 Reply Last reply
            0
            • S Super Lloyd

              Well it's only tip #237, so I guess it's not the 1st thing I should rush to do! :)

              A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

              D Offline
              D Offline
              Dan Neely
              wrote on last edited by
              #58

              Super Lloyd wrote:

              Well it's only tip #237, so I guess it's not the 1st thing I should rush to do! Smile

              Yeah, but not for that reason. John's higher tips aren't in sequential order. A lot of the high priority ones are probably within this set: 9, 22, 32, 38, 44, 45, 50, 306, 308, 357, 454, 556, 762. :cool:

              3x12=36 2x12=24 1x12=12 0x12=18

              S 1 Reply Last reply
              0
              • M Mechanical

                Derek Viljoen wrote:

                In other words, you have yet to provide any empirical evidence for your worth to this site. No be a good boy and go away, please.

                You have much to learn, little one.

                NULL

                R Offline
                R Offline
                Richard A Dalton
                wrote on last edited by
                #59

                Mechanical wrote:

                You have much to learn, little one.

                Ain't it grand....that whole internet anonymity thang?!? Helping people work out their inner troll issues. Go read 'Richter' and stop bothering the grown ups. -Richard

                Hit any user to continue.

                1 Reply Last reply
                0
                • D Daniel Grunwald

                  That looks quite similar to the C++ assembler code! Here, compare the main loop bodies. I've added annotations to the C# assembler code. C#:

                  000000b1 cmp byte ptr [esi+ecx],0 // primes[i] != 0
                  000000b5 je 000000D1
                  // if (primes[i] != 0) {
                  000000b7 mov edx,ecx
                  000000b9 add edx,edx // int k = 2 * i
                  000000bb cmp edx,2001h // k < end
                  000000c1 jge 000000D1
                  // for {
                  000000c3 mov byte ptr [esi+edx],0 // primes[k] = 0;
                  000000c7 add edx,ecx // k += i
                  000000c9 cmp edx,2001h // k < end
                  000000cf jl 000000C3
                  // }
                  // }
                  000000d1 inc ecx // ++i
                  000000d2 cmp ecx,2001h // i < end
                  000000d8 jl 000000B1

                  C++:

                                      if (primes\[i\] != 0)
                  

                  002610A0 cmp byte ptr [esp+ecx+10h],bl
                  002610A4 je wmain+0BDh (2610BDh)
                  {
                  int p = i; // using this extra variable speeds up C++!!! (and slow down C# if I do it)
                  for (int k = i + p; k < end; k += p)
                  002610A6 lea eax,[ecx+ecx]
                  002610A9 cmp eax,2001h
                  002610AE jge wmain+0BDh (2610BDh)
                  primes[k] = 0;
                  002610B0 mov byte ptr [esp+eax+10h],bl
                  002610B4 add eax,ecx
                  002610B6 cmp eax,2001h
                  002610BB jl wmain+0B0h (2610B0h)

                  	for (int i = begin; i < end; ++i)
                  

                  002610BD inc ecx
                  002610BE cmp ecx,2001h
                  002610C4 jl wmain+0A0h (2610A0h)

                  The C++ compiler was a bit more clever in combining mov+add into lea, but other than that, the instructions are identical. C++ also lifted the 0 literal into a register (bl), but I'm not sure if that gives you a performance advantage over immediates. (this optimization does give you a code size advantage though, at least for data types larger than 1 byte) So I'm not sure if this small optimization (lea) is causing the difference in performance, or if the reason for the difference is outside this loop. Because there's a major difference in the 'reset to 1' loop: C# resets each byte individually, whereas C++ calls the much faster memset. You could try rewriting that C# loop to:

                              int\* primesInt = (int\*)primes;
                  	for (int i = 0; i < ((end-1)/sizeof(int))+1; i++)
                  		primesInt\[i\] = 0x01010101;
                  

                  Maybe even try if long is faster on your machine. In fact, I have the suspicion that the C++ memset might use SSE registers to set 16 ele

                  S Offline
                  S Offline
                  Super Lloyd
                  wrote on last edited by
                  #60

                  Thanks Daniel, this is all very enligthening comments! :-D Further I tried your suggestion and changed the setting to 1 as follow (remember prime is a stackalloc in C# so it's already a pointer)

                  var lprim = (long*)primes;
                  for (int i = 0; i < (end / 8); i++)
                  lprim[i] = 0x0101010101010101L;

                  and the speed is now very close to C++ (5% slower) overall it's quite good for C# after reflection hey! :)

                  A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                  1 Reply Last reply
                  0
                  • D Dan Neely

                    Super Lloyd wrote:

                    Well it's only tip #237, so I guess it's not the 1st thing I should rush to do! Smile

                    Yeah, but not for that reason. John's higher tips aren't in sequential order. A lot of the high priority ones are probably within this set: 9, 22, 32, 38, 44, 45, 50, 306, 308, 357, 454, 556, 762. :cool:

                    3x12=36 2x12=24 1x12=12 0x12=18

                    S Offline
                    S Offline
                    Super Lloyd
                    wrote on last edited by
                    #61

                    It's all clear now! :-D

                    A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                    1 Reply Last reply
                    0
                    • L Lost User

                      Is it a Debug build?

                      S Offline
                      S Offline
                      Super Lloyd
                      wrote on last edited by
                      #62

                      Hey, it's not so bad! Look at the latest comment from Daniel from the assembly code which has been found by attaching to a running process: http://www.codeproject.com/Lounge.aspx?msg=3657636#xx3657636xx[^] Further I managed to get quite close to C++ (5% slower) by changing the loop which sets the bytes to 1, by writing something close to what the C++ compiler did, thanks to Daniel's comment!

                      A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                      L 1 Reply Last reply
                      0
                      • S Super Lloyd

                        Hey, it's not so bad! Look at the latest comment from Daniel from the assembly code which has been found by attaching to a running process: http://www.codeproject.com/Lounge.aspx?msg=3657636#xx3657636xx[^] Further I managed to get quite close to C++ (5% slower) by changing the loop which sets the bytes to 1, by writing something close to what the C++ compiler did, thanks to Daniel's comment!

                        A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                        L Offline
                        L Offline
                        Lost User
                        wrote on last edited by
                        #63

                        It's not too bad, but it has an int3 in it

                        S 1 Reply Last reply
                        0
                        • L Lost User

                          It's not too bad, but it has an int3 in it

                          S Offline
                          S Offline
                          Super Lloyd
                          wrote on last edited by
                          #64

                          int3!?! I don't speak assembly :sigh: , please explain! ;)

                          A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                          L 1 Reply Last reply
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                          • S Super Lloyd

                            int3!?! I don't speak assembly :sigh: , please explain! ;)

                            A train station is where the train stops. A bus station is where the bus stops. On my desk, I have a work station.... _________________________________________________________ My programs never have bugs, they just develop random features.

                            L Offline
                            L Offline
                            Lost User
                            wrote on last edited by
                            #65

                            int3 is "debug break", on windows, if there is no debugger attached it causes the program to be halted and you will get a dialog asking you whether you want to debug the program.

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