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  3. Observing Schrodinger's cat [modified]

Observing Schrodinger's cat [modified]

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  • R realJSOP

    Based on what we know of trees, a tree does not grow wihtout a root system and pretty much any tree we see laying on its side has - of course - fallen. We don't have to see it fall to know that it fell. The question is whether or not the tree has fallen until we have observed that it has. If the tree falls and crushes you, even with your back to it, the tree has interacted with you in a number of ways before your untimely demise, via sound, the rush of forest animals trying to run past you to get out of the way of the falling tree, and finally the tree contacting your person. You have, in the end, interacted with the tree without observing it in the classical sense of "observation".

    ".45 ACP - because shooting twice is just silly" - JSOP, 2010
    -----
    You can never have too much ammo - unless you're swimming, or on fire. - JSOP, 2010
    -----
    "Why don't you tie a kerosene-soaked rag around your ankles so the ants won't climb up and eat your candy ass." - Dale Earnhardt, 1997

    modified on Friday, July 22, 2011 8:43 AM

    W Offline
    W Offline
    wizardzz
    wrote on last edited by
    #41

    John Simmons / outlaw programmer wrote:

    If the tree falls and crushes you,

    you had nothing to do with it, right?

    "I have a theory that the truth is never told during the nine-to-five hours. " — Hunter S. Thompson

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    • S S Houghtelin

      So if it wasn't observed, it never happed? That is so "tree falls..." if I never heard it.

      It was broke, so I fixed it.

      S Offline
      S Offline
      SeattleC
      wrote on last edited by
      #42

      S Houghtelin wrote:

      So if it wasn't observed, it never happe[ne]d? That is so "tree falls..." if I never heard it.

      Yes, exactly. Only, you can't even say the tree fell, because nobody observed it. If you already knew that the tree fell, it must have been by observation or by construction, in which case the wave function has already collapsed. I *love* quantum philosophy!

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      • H hairy_hats

        As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

        modified on Friday, July 22, 2011 10:52 AM

        M Offline
        M Offline
        Member 7753803
        wrote on last edited by
        #43

        viaducting wrote:

        As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed?

        Well, if the cat is asleep all the time it stays in the box, then it can't be an active observer.

        modified on Monday, July 25, 2011 12:13 PM

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        • H hairy_hats

          As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

          modified on Friday, July 22, 2011 10:52 AM

          M Offline
          M Offline
          Michael Kernaghan
          wrote on last edited by
          #44

          This discussion is 80 years out of date. Collapse of the wavefunction is an idea from the 1930's.

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          • H hairy_hats

            As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

            modified on Friday, July 22, 2011 10:52 AM

            P Offline
            P Offline
            patbob
            wrote on last edited by
            #45

            "As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed?" More importantly than that, whenever I put my cats in boxes, they usually make it known that they are still very much alive without my having to peek inside, not to mention that they are not terribly happy about their predicament either. Cat in a box? Schrodinger obviously never took his cat to the vet :)

            patbob

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            • H hairy_hats

              As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

              modified on Friday, July 22, 2011 10:52 AM

              B Offline
              B Offline
              Bob work
              wrote on last edited by
              #46

              I always thought that the point of the thought experiment was that "you don't know anything until you get off your behind, open the box, and take a look." Without gathering additional information, the cat is both "as good as new" and "as good as dead" as far as the rest of us are concerned - and the cat doesn't get a vote in the matter. Perhaps I missed the point of the lecture way back when... :doh: As far as the use of synaptic efficiency enhancer goes, I think 3 full shots of a reputable single-malt will get you started nicely.

              -Bob

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              • W Wjousts

                viaducting wrote:

                As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed?

                You're over thinking it. It's a thought experiment and, like an analogy, it only goes so far.

                P Offline
                P Offline
                peterchen
                wrote on last edited by
                #47

                Even moreso, it was a thought experiment to show "this is ridiculous, that's really what you are planning to use?"

                FILETIME to time_t
                | FoldWithUs! | sighist | WhoIncludes - Analyzing C++ include file hierarchy

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                • H hairy_hats

                  As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

                  modified on Friday, July 22, 2011 10:52 AM

                  M Offline
                  M Offline
                  mcuartas
                  wrote on last edited by
                  #48

                  If there is a TRUE observer this piece of reality needs to be simulated. If the observer is part of the simulation, obviously, it is not needed. If it is not simulated their state remains uncertain... It's a matter of resource saving. So the premise is correct if the cat is not a TRUE observer. Hope this helps ;)

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                  • S S Houghtelin

                    Your explaination is well put. :) My point exaclty! :thumbsup: Just because it wasn't observed, doesn't mean it didn't happen. Things happen all the time without being observed. Observation proves that stuff does happen and that observed reactions can be reasonably expected to occur again.

                    It was broke, so I fixed it.

                    G Offline
                    G Offline
                    ghle
                    wrote on last edited by
                    #49

                    I never heard the Big Bang, but I understand that it happened.

                    Gary

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                    • H hairy_hats

                      As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

                      modified on Friday, July 22, 2011 10:52 AM

                      R Offline
                      R Offline
                      rkrishnasanka
                      wrote on last edited by
                      #50

                      The fact that we make the observation is made , means that the system is not in a quantum state (unknown/variable/anything is possible). and about intelligence , just because my retard friend makes the observation; the outcome doesnt change. (id take a shot at IQ saying that its just bullcrap because QM doesnt vary with IQ)

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                      • D Dalek Dave

                        It was only recently when I found out that cats do not, in fact, have nine lives.

                        ------------------------------------ I will never again mention that I was the poster of the One Millionth Lounge Post, nor that it was complete drivel. Dalek Dave CCC Link[^] Trolls[^]

                        D Offline
                        D Offline
                        DarthDana
                        wrote on last edited by
                        #51

                        How do you know he didn't already use up the other eight and you didn't observe it? :-D

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                        • H hairy_hats

                          As the cat is an active observer inside the box, isn't the whole premise of the thought experiment flawed? On a related topic, in a QM collapsing-the-waveform sense, what does an "observation" mean? Does it mean an observation by an intelligence or just an interaction with another system? If the latter, then wouldn't "interaction" be a better description than "observation"? If the former, then how does the QM system being measured know that the interaction it is experiencing is an observation by an intelligence and not just a random interaction with a passing particle/wave? And finally, how much Scotch does it take to make yourself believe you understand this stuff? Edit: An interesting blog entry on this topic is here[^].

                          modified on Friday, July 22, 2011 10:52 AM

                          L Offline
                          L Offline
                          Lost User
                          wrote on last edited by
                          #52

                          Another system. Any dumb particle would do.

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