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  3. Code Puzzler: How quickly can you figure out why this acting "weird"?

Code Puzzler: How quickly can you figure out why this acting "weird"?

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  • M Marc Clifton

    And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

    public class ModelDataContext : DataContext
    {
        public static ModelDataContext Context;
    
        public ModelDataContext(DbConnection conn) : base(conn)
        {
            Context = this;
        }
    }
    
    class Program
    {
        static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
    
        static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
        {
            conn = new SqlConnection(context.Connection.ConnectionString);
            newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
            Console.WriteLine(context == newContext);
        }
    
        static void Main(string\[\] args)
        {
            SqlConnection conn2;
            DataContext newdc;
            CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
    
            Console.WriteLine(ModelDataContext.Context == newdc);
        }
    }
    

    and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

    Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

    J Offline
    J Offline
    Jon McKee
    wrote on last edited by
    #9

    The problem is that you're assigning a static variable inside the instance constructor to that instance . So every time you create an object you're changing the Context property. The reason the tests are different is because you pass the Context as a parameter so even after the update the parameter still has the old Context. A fix would be to not do that because it's bad design ;P I'd make Context an instance property and implement your own ==, !=, Equals, etc unless you want referential equality.

    1 Reply Last reply
    0
    • M Marc Clifton

      And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

      public class ModelDataContext : DataContext
      {
          public static ModelDataContext Context;
      
          public ModelDataContext(DbConnection conn) : base(conn)
          {
              Context = this;
          }
      }
      
      class Program
      {
          static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
      
          static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
          {
              conn = new SqlConnection(context.Connection.ConnectionString);
              newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
              Console.WriteLine(context == newContext);
          }
      
          static void Main(string\[\] args)
          {
              SqlConnection conn2;
              DataContext newdc;
              CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
      
              Console.WriteLine(ModelDataContext.Context == newdc);
          }
      }
      

      and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

      Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

      Richard DeemingR Offline
      Richard DeemingR Offline
      Richard Deeming
      wrote on last edited by
      #10

      Just read the blog post, and I don't think your fix will work. :)


      "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

      "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

      J 1 Reply Last reply
      0
      • Richard DeemingR Richard Deeming

        Just read the blog post, and I don't think your fix will work. :)


        "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

        J Offline
        J Offline
        Jon McKee
        wrote on last edited by
        #11

        It will work in that specific example because he also changed the CreateInstance call to not use conn anymore. But yes, if the parameterized constructor is called it'll still have the same issue :thumbsup:

        Richard DeemingR 1 Reply Last reply
        0
        • J Jon McKee

          It will work in that specific example because he also changed the CreateInstance call to not use conn anymore. But yes, if the parameterized constructor is called it'll still have the same issue :thumbsup:

          Richard DeemingR Offline
          Richard DeemingR Offline
          Richard Deeming
          wrote on last edited by
          #12

          Well, it will "work", in the sense that it won't overwrite the static instance. But it won't work, in the sense that the returned instance will be using the default connection string for the context, not the connection string from the instance passed in. :)


          "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

          "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

          M 1 Reply Last reply
          0
          • Richard DeemingR Richard Deeming

            Roughly 90 seconds, mostly working out which Console.WriteLine call was which. :) Spoilers ahead - select the block to view:

            Take a copy of the static field; Create a new instance, thus overwriting the static field; Compare the new instance to the copy of the old value of the static field - result = false; Compare the new instance to the current value of the static field - result = true;

            Damnit Chris, we need a <div class="spoiler">!


            "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

            M Offline
            M Offline
            Marc Clifton
            wrote on last edited by
            #13

            Richard Deeming wrote:

            select the block to view:

            Now THAT is snazzy!

            Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

            1 Reply Last reply
            0
            • Richard DeemingR Richard Deeming

              Well, it will "work", in the sense that it won't overwrite the static instance. But it won't work, in the sense that the returned instance will be using the default connection string for the context, not the connection string from the instance passed in. :)


              "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

              M Offline
              M Offline
              Marc Clifton
              wrote on last edited by
              #14

              Richard Deeming wrote:

              But it won't work, in the sense that the returned instance will be using the default connection string for the context, not the connection string from the instance passed in.

              Hmm. But the parameterless constructor uses the connection string of the (hopefully) already initialized context: public ModelDataContext() : base(Context.Connection) However, it's a moot point anyways as I refactored the whole mess into something much less weird. It'll be an interesting question though to pose to a couple of the devs at work, though I'll reduce the complexity of it omitting the DataContext base class - it's rather superfluous to the example.

              Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

              Richard DeemingR 1 Reply Last reply
              0
              • M Marc Clifton

                Richard Deeming wrote:

                But it won't work, in the sense that the returned instance will be using the default connection string for the context, not the connection string from the instance passed in.

                Hmm. But the parameterless constructor uses the connection string of the (hopefully) already initialized context: public ModelDataContext() : base(Context.Connection) However, it's a moot point anyways as I refactored the whole mess into something much less weird. It'll be an interesting question though to pose to a couple of the devs at work, though I'll reduce the complexity of it omitting the DataContext base class - it's rather superfluous to the example.

                Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                Richard DeemingR Offline
                Richard DeemingR Offline
                Richard Deeming
                wrote on last edited by
                #15

                OK, so it's not quite as bad as I though. :) You could still break it though:

                var context1 = new ModelDataContext(new SqlConnection("server=A;database=B"));
                var context2 = new ModelDataContext(new SqlConnection("server=C;database=D"));

                CreateNewContext(context1, out var newConn, out var newContext);

                // As expected:
                Console.WriteLine(newConn.ConnectionString == context1.Connection.ConnectionString); // True

                // Not as expected:
                Console.WriteLine(newContext.Connection.ConnectionString == context1.Connection.ConnectionString); // False
                Console.WriteLine(newContext.Connection.ConnectionString == newConn.ConnectionString); // False
                Console.WriteLine(newContext.Connection == newConn); // False

                // Also not as expected:
                Console.WriteLine(newContext.Connection.ConnectionString == context2.Connection.ConnectionString); // True


                "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                "These people looked deep within my soul and assigned me a number based on the order in which I joined" - Homer

                M 1 Reply Last reply
                0
                • OriginalGriffO OriginalGriff

                  You probably could, with a bit of thinking about it - it's obvious when you see it, but it's a stinker to spot if you didn't write the code (and probably even harder if you did if you are anything like me: I tend to see what I meant to write, rather than what I did :-O )

                  Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!

                  Mike HankeyM Offline
                  Mike HankeyM Offline
                  Mike Hankey
                  wrote on last edited by
                  #16

                  I also see what I meant to write as opposed to what I actually wrote. I've been tired and looked at two spellings of same word and get compiler errors and don't spot the error for some time.

                  Everyone has a photographic memory; some just don't have film. Steven Wright

                  OriginalGriffO 1 Reply Last reply
                  0
                  • Mike HankeyM Mike Hankey

                    I also see what I meant to write as opposed to what I actually wrote. I've been tired and looked at two spellings of same word and get compiler errors and don't spot the error for some time.

                    Everyone has a photographic memory; some just don't have film. Steven Wright

                    OriginalGriffO Offline
                    OriginalGriffO Offline
                    OriginalGriff
                    wrote on last edited by
                    #17

                    Annoying, isn't it? :-D

                    Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!

                    "I have no idea what I did, but I'm taking full credit for it." - ThisOldTony
                    "Common sense is so rare these days, it should be classified as a super power" - Random T-shirt

                    Mike HankeyM 1 Reply Last reply
                    0
                    • OriginalGriffO OriginalGriff

                      Annoying, isn't it? :-D

                      Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!

                      Mike HankeyM Offline
                      Mike HankeyM Offline
                      Mike Hankey
                      wrote on last edited by
                      #18

                      Yes very frustrating. As I get older it seems to be more prevalent.

                      Everyone has a photographic memory; some just don't have film. Steven Wright

                      1 Reply Last reply
                      0
                      • Richard DeemingR Richard Deeming

                        OK, so it's not quite as bad as I though. :) You could still break it though:

                        var context1 = new ModelDataContext(new SqlConnection("server=A;database=B"));
                        var context2 = new ModelDataContext(new SqlConnection("server=C;database=D"));

                        CreateNewContext(context1, out var newConn, out var newContext);

                        // As expected:
                        Console.WriteLine(newConn.ConnectionString == context1.Connection.ConnectionString); // True

                        // Not as expected:
                        Console.WriteLine(newContext.Connection.ConnectionString == context1.Connection.ConnectionString); // False
                        Console.WriteLine(newContext.Connection.ConnectionString == newConn.ConnectionString); // False
                        Console.WriteLine(newContext.Connection == newConn); // False

                        // Also not as expected:
                        Console.WriteLine(newContext.Connection.ConnectionString == context2.Connection.ConnectionString); // True


                        "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

                        M Offline
                        M Offline
                        Marc Clifton
                        wrote on last edited by
                        #19

                        Richard Deeming wrote:

                        You could still break it though:

                        Yeah, but it's never used that way - two different connection strings. But ideally, it shouldn't be possible to use it that way. Sigh. The irony of this is that it's code I wrote a while back that my DataContext extension methods rely on, and looking at this now, it's some serious code smell. Fortunately, fixing it affects only a couple web servers that are in operation, but I feel embarrassed. But I blame .NET's DataContext. :laugh: It does way to much with regards to the state of the Table object. I get what they're trying to do, but there must be a better way that doesn't end up throwing exceptions like "this object was created in a different data context."

                        Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                        1 Reply Last reply
                        0
                        • M Marc Clifton

                          And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

                          public class ModelDataContext : DataContext
                          {
                              public static ModelDataContext Context;
                          
                              public ModelDataContext(DbConnection conn) : base(conn)
                              {
                                  Context = this;
                              }
                          }
                          
                          class Program
                          {
                              static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
                          
                              static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
                              {
                                  conn = new SqlConnection(context.Connection.ConnectionString);
                                  newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
                                  Console.WriteLine(context == newContext);
                              }
                          
                              static void Main(string\[\] args)
                              {
                                  SqlConnection conn2;
                                  DataContext newdc;
                                  CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
                          
                                  Console.WriteLine(ModelDataContext.Context == newdc);
                              }
                          }
                          

                          and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

                          Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                          S Offline
                          S Offline
                          soulesurfer
                          wrote on last edited by
                          #20

                          The reason for the results are pretty obvious, when a new instance is created in "CreateNewContext", the parameter "context" is still referring to the original context, not the new one ==> false; When the main program does the compare afterwards, the comparison is done to the static that holds the new context ==> true. Fixing this is not obvious because you didn't specify what the correct behavior should be. Do you wish it to be "True" always, or "False" always :) Simply update the context parameter in the method to get True always, but I would personally recommend to re-write this whole thing, it is full of code smells. Perhaps some practice in TDD would also be helpful. Cheers, Anthony

                          1 Reply Last reply
                          0
                          • M Marc Clifton

                            And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

                            public class ModelDataContext : DataContext
                            {
                                public static ModelDataContext Context;
                            
                                public ModelDataContext(DbConnection conn) : base(conn)
                                {
                                    Context = this;
                                }
                            }
                            
                            class Program
                            {
                                static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
                            
                                static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
                                {
                                    conn = new SqlConnection(context.Connection.ConnectionString);
                                    newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
                                    Console.WriteLine(context == newContext);
                                }
                            
                                static void Main(string\[\] args)
                                {
                                    SqlConnection conn2;
                                    DataContext newdc;
                                    CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
                            
                                    Console.WriteLine(ModelDataContext.Context == newdc);
                                }
                            }
                            

                            and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

                            Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                            E Offline
                            E Offline
                            englebart
                            wrote on last edited by
                            #21

                            It took about a minute to solve. Assigning over the static for each constructor call is a WTF (as others have called out). Way too many statics in this Program, if it was rewritten to eliminate all of the statics, then the Program instance would hold a single context and the Main would look like this:

                            Main(...)
                            {
                            new Program().Run();
                            }

                            If new instances of the "context" are really needed, then create a Copy constructor to reuse the default context settings on a new instance. Or use your favorite IOC container.

                            1 Reply Last reply
                            0
                            • OriginalGriffO OriginalGriff

                              You probably could, with a bit of thinking about it - it's obvious when you see it, but it's a stinker to spot if you didn't write the code (and probably even harder if you did if you are anything like me: I tend to see what I meant to write, rather than what I did :-O )

                              Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!

                              U Offline
                              U Offline
                              User 11542641
                              wrote on last edited by
                              #22

                              OriginalGriff wrote:

                              I tend to see what I meant to write, rather than what I did

                              Yup that's me! As an answer: I haven't gone further in the thread, but at first glance the FALSE comes from comparing 2 different instances, where the TRUE result is comparing the same instance to itself? Fix: the first comparison is not necessary

                              1 Reply Last reply
                              0
                              • M Marc Clifton

                                And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

                                public class ModelDataContext : DataContext
                                {
                                    public static ModelDataContext Context;
                                
                                    public ModelDataContext(DbConnection conn) : base(conn)
                                    {
                                        Context = this;
                                    }
                                }
                                
                                class Program
                                {
                                    static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
                                
                                    static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
                                    {
                                        conn = new SqlConnection(context.Connection.ConnectionString);
                                        newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
                                        Console.WriteLine(context == newContext);
                                    }
                                
                                    static void Main(string\[\] args)
                                    {
                                        SqlConnection conn2;
                                        DataContext newdc;
                                        CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
                                
                                        Console.WriteLine(ModelDataContext.Context == newdc);
                                    }
                                }
                                

                                and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

                                Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                                J Offline
                                J Offline
                                jfren484
                                wrote on last edited by
                                #23

                                It's the assignment of the static member from the instance constructor. HUGE no-no. If you want to make a singleton without using a DI framework, at least make the constructor private and have the static "Context" member be a property that will create a new object if one doesn't exist, and set it to a backing field. Something like this (might need to make Current a method instead of property if you need to pass constructor arguments, but you get the idea):

                                public class Singleton
                                {
                                private Singleton _current;

                                public Singleton Current
                                {
                                	get
                                	{
                                		if (\_current == null)
                                		{
                                			\_current = new Singleton();
                                		}
                                		
                                		return \_current;
                                	}
                                }
                                
                                private Singleton()
                                {
                                }
                                

                                }

                                1 Reply Last reply
                                0
                                • M Marc Clifton

                                  And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

                                  public class ModelDataContext : DataContext
                                  {
                                      public static ModelDataContext Context;
                                  
                                      public ModelDataContext(DbConnection conn) : base(conn)
                                      {
                                          Context = this;
                                      }
                                  }
                                  
                                  class Program
                                  {
                                      static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
                                  
                                      static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
                                      {
                                          conn = new SqlConnection(context.Connection.ConnectionString);
                                          newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
                                          Console.WriteLine(context == newContext);
                                      }
                                  
                                      static void Main(string\[\] args)
                                      {
                                          SqlConnection conn2;
                                          DataContext newdc;
                                          CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
                                  
                                          Console.WriteLine(ModelDataContext.Context == newdc);
                                      }
                                  }
                                  

                                  and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

                                  Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

                                  Q Offline
                                  Q Offline
                                  Q The First Timelord
                                  wrote on last edited by
                                  #24

                                  The first 'true' you receive you explicitly cast the object on the function call to a DataContext type. The second you're comparing a ModelDataContext.Context object - which I'm not sure if it's a DataContext type - if not - then you're comparing unlike objects and the call will fail. Try explicitly casting the ModelDataContext.Context, and for overkill the newdc to a DataContext type and do the comparison that way. ie: Console.WriteLine((DataContext) ModelDataContext.Context == (DataContext) newdc);

                                  1 Reply Last reply
                                  0
                                  • M Marc Clifton

                                    And no, this isn't a programming question in the lounge. I started asking this question in the QA forum because it had me totally stumped. As I was filling out the "What I've tried" I had a major :doh: :doh: :doh: :doh: moment. To prove I'm not asking for help on the lounge, I posted a solution on [my blog](https://marcclifton.wordpress.com/2018/05/31/the-fix/). You'll need to use the password "fizbin" as the blog post is specifically for this lounge post and eventually I'll delete the post. It is a fun one though. Here's the code:

                                    public class ModelDataContext : DataContext
                                    {
                                        public static ModelDataContext Context;
                                    
                                        public ModelDataContext(DbConnection conn) : base(conn)
                                        {
                                            Context = this;
                                        }
                                    }
                                    
                                    class Program
                                    {
                                        static ModelDataContext mdc = new ModelDataContext(new SqlConnection("\[some string\]"));
                                    
                                        static void CreateNewContext(DataContext context, out SqlConnection conn, out DataContext newContext)
                                        {
                                            conn = new SqlConnection(context.Connection.ConnectionString);
                                            newContext = (DataContext)Activator.CreateInstance(context.GetType(), new object\[\] { conn });
                                            Console.WriteLine(context == newContext);
                                        }
                                    
                                        static void Main(string\[\] args)
                                        {
                                            SqlConnection conn2;
                                            DataContext newdc;
                                            CreateNewContext(ModelDataContext.Context, out conn2, out newdc);
                                    
                                            Console.WriteLine(ModelDataContext.Context == newdc);
                                        }
                                    }
                                    

                                    and the result is: False True Why is the second equality True when the first is False??? And for the bonus prize, what's a fix?

                                    Latest Article - Building a Prototype Web-Based Diagramming Tool with SVG and Javascript Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you. - DangerBunny Artificial intelligence is the only remedy for natural stupidity. - CDP1802

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                                    AnotherKen
                                    wrote on last edited by
                                    #25

                                    It is a simple newb mistake. Basically, you have written overly complex code making it hard for you to debug. Simplify the syntax as much as possible and the symantec issues will reveal themselves ;)

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