Programming Quiz
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So, I don't know shit about Haskell, but shouldn't it be Data.Time.Calendar.Gregorian instead of Data.Time.Calendar.Julian? Unless you're living in Russia that is.
Wrong is evil and must be defeated. - Jeff Ello
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Jörgen Andersson wrote:
shouldn't it be Data.Time.Calendar.Gregorian instead of Data.Time.Calendar.Julian You're quite right - and that's my mistake, getting Gregorian/Julian mixed up! Gregorian is actually the default, baked into `Data.Time.Calendar`, while Julian is the add-on... ```haskell import Data.List.Split import Data.Time.Calendar; import Data.Time.Calendar.Compat; import Text.Printf printMonth :: Integer -> Int -> IO () printMonth year month = printWeeks entriesInMonth where -- printWeeks chunks the month's entries into weeks & prints each week on a new line printWeeks days = mapM_ (putStrLn.unwords) (chunksOf 7 days) -- entriesInMonth concatenates the empty entries at the start of the month with the days entriesInMonth = startPadding ++ daysOfMonth -- daysOfMonth generates a list of days of the month as strings daysOfMonth = map (printf "%2d") [1..(gregorianMonthLength year month)] -- startPadding generates blank strings for each empty entry before day '1' startPadding = replicate blanksBeforeDay1 " " -- blanksBeforeDay1 is the number of empty entries before day '1' blanksBeforeDay1 = (fromEnum $ dayOfWeek (fromGregorian year month 1)) `mod` 7 ``` Being able to use `Data.Time.Calendar` rather than `Data.Time.Calendar.Julian` should have been a giveaway, shouldn't it :-O
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
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OK, reformatted to protect the guilty. Write a function in your favorite language to create a "day view" in an array for a month, like 11/2019. So for that month/year, the array should look like this, where the day numbers not in the month are null or undefined:
1 2 3 4 5 6 7 8 910 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30My solution in C#, which uses an extension method:
int?[] days = new int?[6 * 7];
var dow = (int)new DateTime(2019, 11, 1).DayOfWeek;
Enumerable.Range(1, DateTime.DaysInMonth(2019, 11)).ForEachWithIndex((idx, n) => days[dow + idx] = n);And the output function:
days.ForEachWithIndex((idx, n) => Console.Write(((idx % 7 == 0) ? "\r\n" : "") + (n?.ToString()?.PadLeft(5) ?? " ")));
Which of course generates a leading CRLF, but oh well, that wasn't specifically indicated not to do so in the spec. :laugh: For the curious, this came up in a conversation with a coworker.
Latest Articles:
16 Days: A TypeScript application from concept to implementation -
>
Jörgen Andersson wrote:
shouldn't it be Data.Time.Calendar.Gregorian instead of Data.Time.Calendar.Julian You're quite right - and that's my mistake, getting Gregorian/Julian mixed up! Gregorian is actually the default, baked into `Data.Time.Calendar`, while Julian is the add-on... ```haskell import Data.List.Split import Data.Time.Calendar; import Data.Time.Calendar.Compat; import Text.Printf printMonth :: Integer -> Int -> IO () printMonth year month = printWeeks entriesInMonth where -- printWeeks chunks the month's entries into weeks & prints each week on a new line printWeeks days = mapM_ (putStrLn.unwords) (chunksOf 7 days) -- entriesInMonth concatenates the empty entries at the start of the month with the days entriesInMonth = startPadding ++ daysOfMonth -- daysOfMonth generates a list of days of the month as strings daysOfMonth = map (printf "%2d") [1..(gregorianMonthLength year month)] -- startPadding generates blank strings for each empty entry before day '1' startPadding = replicate blanksBeforeDay1 " " -- blanksBeforeDay1 is the number of empty entries before day '1' blanksBeforeDay1 = (fromEnum $ dayOfWeek (fromGregorian year month 1)) `mod` 7 ``` Being able to use `Data.Time.Calendar` rather than `Data.Time.Calendar.Julian` should have been a giveaway, shouldn't it :-O
Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p
Stuart Dootson wrote:
Being able to use
Data.Time.Calendarrather thanData.Time.Calendar.Julianshould have been a giveaway, shouldn't it :OI wouldn't have known. :doh: :-O
Wrong is evil and must be defeated. - Jeff Ello
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Took this a step further and extended the code, and it should work with culture:
void Main()
{
StringBuilder builder = new StringBuilder();Enumerable.Range(1, 12) .ToList() .ForEach(e => PopulateDayOfMonth(2021, e, builder)); Console.WriteLine(builder.ToString().Trim());}
static void PopulateDayOfMonth(int year, int month, StringBuilder builder)
{
builder.AppendLine();
int space = 6;
int dashLine = 1 + (space * 7);IEnumerable days = Enumerable.Range(1, DateTime.DaysInMonth(year, month)) .Select(d => new DateTime(year, month, d)); builder.AppendLine(days.First().ToString("MMMMM")); builder.Append('-', dashLine); builder.AppendLine(); builder.AppendLine($"|{string.Join("|", Enum.GetNames(typeof(DayOfWeek)).Select(d => $" {d.Substring(0, 3)} "))}|" ); builder.Append('-', dashLine); builder.AppendLine(); DayOfWeek dow = days.First().DayOfWeek; while (dow != 0) { builder.Append(' ', space); dow--; } bool first = true; foreach (var d in days) { if (!first && d.DayOfWeek == 0) { builder.AppendLine("|"); builder.Append('-', dashLine); builder.AppendLine(); } builder.Append($"|{d.Day.ToString().PadLeft(space - 2)} "); first = false; } builder.AppendLine("|"); builder.Append('-', dashLine); builder.AppendLine();}
With the following output:
January
| Sun | Mon | Tue | Wed | Thu | Fri | Sat |
| 1 | 2 |
| 3 | 4 | 5 | 6 | 7 | 8 | 9 |
| 10 | 11 | 12 | 13 | 14 | 15 | 16 |
| 17 | 18 | 19 | 20 | 21 | 22 | 23 |
| 24 | 25 | 26 | 27 | 28 | 29 | 30 |
| 31 |
February
| Sun | Mon | Tue | Wed | Thu | Fri | Sat |
| 1 | 2 | 3 | 4 | 5 | 6 |
| 7 | 8 | 9 | 10 | 11 | 12 | 13 |
Unfortunately, that still assumes the first day of the week is Sunday. :)
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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Now make it work for cultures whose week doesn't start on Sunday. ;P
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
The first thing that I thought as well...here in Poland, the week starts on Monday. Almost two years here and this still throws me off.
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Richard Deeming wrote:
Now make it work for cultures whose week doesn't start on Sunday.
I wonder if there are any cultures that don't have a 7 day week? Or even the concept of a week?
Latest Articles:
16 Days: A TypeScript application from concept to implementationFor bonus points, on the management/sales side: - convince a culture with a different week size to adopt the 7 days week. - convince a culture without the concept of calendar to adopt a 10 days week calendar (or 5 day, for the impatient), and then apply previous step.
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Richard Deeming wrote:
cultures whose week doesn't start on Sunday.
That's easy - NUKE 'EM !
"The difference between genius and stupidity is that genius has its limits." - Albert Einstein
"If you are searching for perfection in others, then you seek disappointment. If you seek perfection in yourself, then you will find failure." - Balboos HaGadol Mar 2010
Slow down there Donald.
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Otherwise you could use Genesis 2.2 as a reference.
Wrong is evil and must be defeated. - Jeff Ello
Hold up, this is implying that we need to start working Saturdays, a six work-day week.
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Slow down there Donald.
Not at all - as a humanitarian, I prefer to make in quick and painless. . . . at least I won't feel a thing . . .
"The difference between genius and stupidity is that genius has its limits." - Albert Einstein
"If you are searching for perfection in others, then you seek disappointment. If you seek perfection in yourself, then you will find failure." - Balboos HaGadol Mar 2010
-
OK, reformatted to protect the guilty. Write a function in your favorite language to create a "day view" in an array for a month, like 11/2019. So for that month/year, the array should look like this, where the day numbers not in the month are null or undefined:
1 2 3 4 5 6 7 8 910 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30My solution in C#, which uses an extension method:
int?[] days = new int?[6 * 7];
var dow = (int)new DateTime(2019, 11, 1).DayOfWeek;
Enumerable.Range(1, DateTime.DaysInMonth(2019, 11)).ForEachWithIndex((idx, n) => days[dow + idx] = n);And the output function:
days.ForEachWithIndex((idx, n) => Console.Write(((idx % 7 == 0) ? "\r\n" : "") + (n?.ToString()?.PadLeft(5) ?? " ")));
Which of course generates a leading CRLF, but oh well, that wasn't specifically indicated not to do so in the spec. :laugh: For the curious, this came up in a conversation with a coworker.
Latest Articles:
16 Days: A TypeScript application from concept to implementationI'd go with a Bash script...
#!/bin/sh
cal
