Get create table statements for a database under a schema.
SELECT TABLE_NAME, 'CREATE TABLE '||TABLE_NAME|| ' ('||STRING_AGG(CONCAT( C1, C2, C3, C4, C5, C6 ),', ')||')' AS QUERY FROM ( SELECT C.TABLE_NAME, '"'||C.COLUMN_NAME||'"' || ' ' || CASE WHEN DATA_TYPE='ARRAY' THEN LTRIM(UDT_NAME,'_')||'[]' ELSE DATA_TYPE END AS C1, CASE WHEN CHARACTER_MAXIMUM_LENGTH > 0 THEN '(' || CHARACTER_MAXIMUM_LENGTH || ')' END AS C2, CASE WHEN NUMERIC_PRECISION > 0 AND NUMERIC_SCALE < 1 THEN NULL END AS C3, CASE WHEN NUMERIC_PRECISION > 0 AND NUMERIC_SCALE > 0 THEN NULL END AS C4, CASE WHEN IS_NULLABLE = 'NO' THEN ' NOT NULL' END AS C5, CASE WHEN COLUMN_DEFAULT IS NOT NULL AND COLUMN_DEFAULT NOT LIKE 'nextval%' THEN ' DEFAULT' END || ' ' || REPLACE(COLUMN_DEFAULT, '::CHARACTER VARYING', '') AS C6 FROM INFORMATION_SCHEMA.COLUMNS C, INFORMATION_SCHEMA.TABLES T WHERE C.TABLE_CATALOG='tpch' AND T.TABLE_CATALOG='tpch' AND T.TABLE_SCHEMA='public' AND C.TABLE_NAME=T.TABLE_NAME AND C.TABLE_SCHEMA='public' AND T.TABLE_TYPE IN ('BASE TABLE') ORDER BY C.TABLE_NAME, C.ORDINAL_POSITION ) AS STRING_COLUMNS GROUP BY TABLE_NAME