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Math Problem ...

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  • P Paul Conrad

    Though it does not qualify as an actual mathematical proof, I've tested your approach and Jun Du's approach in Excel with 10-15 different values and I get the same results. Remember that: θ = arctan( y / x ) x = cos( θ ) y = sin( θ ) from Inverse Tangent[^] You wrote: θ = arctan((d - b) / (c - a)) x = a + (0.2*|AB|*cos(θ) y = b + (0.2*|AB|*sin(θ) and based on the link from MathWorld, (c-a) = cos( θ ) and (d-b) = sin( θ ) PJC

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    Ed Poore
    wrote on last edited by
    #41

    I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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    • E Ed Poore

      I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


      Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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      Paul Conrad
      wrote on last edited by
      #42

      Ed.Poore wrote:

      I stand corrected and apologise if I was dogmatic .

      Hey it's cool. It happens.

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      • C Chris Losinger

        yup. he was right up until the last little bit of arithmetic. Cleek | Image Toolkits | Thumbnail maker

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        Paul Conrad
        wrote on last edited by
        #43

        Chris Losinger wrote:

        he was right up until the last little bit of arithmetic.

        I had that happen when I was in Calculus 15 years ago. It happens. The teacher dinged everyone on arithmetic mistakes even if we displayed knowledge of the material. Now I look back at those old midterm exams and laugh. PJC

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        • E Ed Poore

          I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


          Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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          Chris Losinger
          wrote on last edited by
          #44

          happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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          • C Chris Losinger

            happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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            Paul Conrad
            wrote on last edited by
            #45

            When substituting cos θ by

                 x2 - x1 
            


            √(y2 - y1)² + (x2 - x1)²

            the magnitude of the two vectors cancel out and you are left with

                 x2 - x1
            

            With the equation for the y component, sin θ is substituted by

                 y2 - y1
            


            √(y2 - y1)² + (x2 - x1)²

            the magnitude of the two vectors cancelled out again and you are left with

                 y2 - y1
            

            So in Jun Du's method, the magnitude of the two vectors and the trig functions drop out. PJC

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            • E Ed Poore

              I just wrote it out on paper, basically if you substitute adjacent / hypotenuse in place of cos then the root will cancel out and you'll get what Jun Du gave.  I'm just too exhausted from 12 hours revision plus a 2 hour shooting walk with my father and the dog. I stand corrected and apologise if I was dogmatic :-O.


              Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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              Paul Conrad
              wrote on last edited by
              #46

              As a friendly suggestion, I would recommend bookmarking the www.mathworld.com[^] link. I use it often as a good web reference :) Paul

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              • R Ray Kinsella

                Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                yang__lee
                wrote on last edited by
                #47

                here it is suppose a and b are points.. I want point C 20% from point a then c.x= a.x+ 0.2 * (distnce between a & b ) * cos (angle between a and b ); c.Y= a.y+ 0.2 * (distnce between a & b ) * sin (angle between a and b ); Leya -- modified at 3:04 Wednesday 14th June, 2006

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                • R Ray Kinsella

                  Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                  Baconbutty
                  wrote on last edited by
                  #48

                  Use a tape measure :) I still remember having to write your own code in FORTRAN rather than be a cut and paste merchant being pampered by colour coded Intellisense - ahh proper programming - those were the days :)

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                  • P Paul Conrad

                    As a friendly suggestion, I would recommend bookmarking the www.mathworld.com[^] link. I use it often as a good web reference :) Paul

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                    Ed Poore
                    wrote on last edited by
                    #49

                    I know about MathWorld since I've got a copy of Mathematica, it's just I was being blind to the obvious yesterday, was feeling a bit more awake today but then sat down outside to read a book in the sun, big mistake.. Fell alseep.


                    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                    • C Chris Losinger

                      happens to the best of us... and the least :) without sitting down and working it through, i don't see how DU's solution works. maybe i'll give it some time later tonight. Cleek | Image Toolkits | Thumbnail maker

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                      Ed Poore
                      wrote on last edited by
                      #50

                      Chris Losinger wrote:

                      happens to the best of us

                      God I hope you're not implying I'm one of the best :laugh: Far from it.


                      Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                      • B Baconbutty

                        Use a tape measure :) I still remember having to write your own code in FORTRAN rather than be a cut and paste merchant being pampered by colour coded Intellisense - ahh proper programming - those were the days :)

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                        Ed Poore
                        wrote on last edited by
                        #51

                        I was told I was making things too complicated (which I was by the way), I think you're oversimplifying a bit here :laugh: But it's the most realiable method, I've got to give you that.


                        Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                        • E Ed Poore

                          I know about MathWorld since I've got a copy of Mathematica, it's just I was being blind to the obvious yesterday, was feeling a bit more awake today but then sat down outside to read a book in the sun, big mistake.. Fell alseep.


                          Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                          Paul Conrad
                          wrote on last edited by
                          #52

                          Ed.Poore wrote:

                          Mathematica

                          I've always liked mathematica. Haven't worked with it in some time :sigh:

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                          • P Paul Conrad

                            Ed.Poore wrote:

                            Mathematica

                            I've always liked mathematica. Haven't worked with it in some time :sigh:

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                            Ed Poore
                            wrote on last edited by
                            #53

                            Havn't used it much but liked what I saw, but I find it's more fun to program your own stuff rather than getting Mathematica to do it. Mind you, you do get a sense of satisfaction when asking it to calculate Pi to 5,000,000 places, you think it's crashed and then you go off to supper, lo and behold when you come back it's done it.


                            Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                            • R Ray Kinsella

                              Hey Guys, I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ? Regards Ray "Je Suis Mort De Rire" Blogging @ Keratoconus Watch

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                              Lost User
                              wrote on last edited by
                              #54

                              Ray Kinsella wrote:

                              I have a math issue, I know how you like brain teasers so I thought I would post it here, say I have two points ab & cd, how do I find the point 20% of distance between these two points on the same slope ?

                              Ask an Asian? Michael Martin Australia "I controlled my laughter and simple said "No,I am very busy,so I can't write any code for you". The moment they heard this all the smiling face turned into a sad looking face and one of them farted. So I had to leave the place as soon as possible." - Mr.Prakash 24/04/2004

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                              • E Ed Poore

                                Havn't used it much but liked what I saw, but I find it's more fun to program your own stuff rather than getting Mathematica to do it. Mind you, you do get a sense of satisfaction when asking it to calculate Pi to 5,000,000 places, you think it's crashed and then you go off to supper, lo and behold when you come back it's done it.


                                Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                Paul Conrad
                                wrote on last edited by
                                #55

                                Ed.Poore wrote:

                                it's more fun to program your own stuff rather than getting Mathematica to do it

                                I agree. It's nice to use a tool like Mathematica to check the program to ensure it is working correctly :) Took a Graduate course called Super Visualization and tools like Mathematica and SciLab were quite useful.

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                                • P Paul Conrad

                                  Ed.Poore wrote:

                                  it's more fun to program your own stuff rather than getting Mathematica to do it

                                  I agree. It's nice to use a tool like Mathematica to check the program to ensure it is working correctly :) Took a Graduate course called Super Visualization and tools like Mathematica and SciLab were quite useful.

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                                  Ed Poore
                                  wrote on last edited by
                                  #56

                                  What's your opinion of SciLab?


                                  Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                  • E Ed Poore

                                    What's your opinion of SciLab?


                                    Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                    Paul Conrad
                                    wrote on last edited by
                                    #57

                                    Ed.Poore wrote:

                                    What's your opinion of SciLab?

                                    It is pretty alright. Had to use it in conjunction with MuPad to solve a problem with wavelet transforms. PJC

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                                    • P Paul Conrad

                                      Ed.Poore wrote:

                                      What's your opinion of SciLab?

                                      It is pretty alright. Had to use it in conjunction with MuPad to solve a problem with wavelet transforms. PJC

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                                      Ed Poore
                                      wrote on last edited by
                                      #58

                                      :nod politely and pretend to understand: :-D


                                      Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                      • E Ed Poore

                                        :nod politely and pretend to understand: :-D


                                        Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                        Paul Conrad
                                        wrote on last edited by
                                        #59

                                        Ed.Poore wrote:

                                        :nod politely and pretend to understand:

                                        :laugh::laugh::laugh: When I look at my old take-home final exam for that Super Visualization course, I still scratch my head over the wavelet transforms stuff :-D

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                                        • E Ed Poore

                                          Jun Du wrote:

                                          This is a perfect example that how people make things more complicated than they should be

                                          Maybe it's more complicated but it works. Here's the proof using simple Pythagorean trig and his theorem.

                                          Start with a 3,4,5 triangle with height 3 and width 4 (and hypotenuse 5).
                                          If A is the bottom left-corner, located over an "origin" of (0,0) then it follows that
                                              A = (0,0) (bottom-left corner)
                                              B = (4,3) (top-right corner)
                                              C = (4,0) (bottom-right corner)
                                              θ = Angle BAC (i.e. bottom-left)
                                          Also it can be shown (through Pythagorean Trigonometry) that:
                                              sin(θ)=3/5
                                              cos(θ)=4/5
                                              tan(θ)=3/4

                                          So you require 20% of the line AB (in this case it is (0.2*5) = 1).
                                          We can let the co-ordinates of the end point of this line (from A along AB for 20% of AB) be X=(x,y).
                                          It then follows that since we have a hypotenuse equal to 1 and the angle has remained the same that:

                                          x = 1*cos(θ) = 4/5
                                              y = 1*sin(θ) = 3/5

                                          So from A the new point X which is 20% of the line AB is A+X, i.e: X = (0 + 4/5, 0 + 3/5) = (4/5, 3/5).

                                          If you take you're equations of:
                                              x = a + 0.2 * (c - a)
                                              y = b + 0.2 * (d - b)
                                          You will get the following answers for this case:
                                              x = 0 + 0.2 * (4 - 0) = 0.2 * 2 = 2/5
                                              y = 0 + 0.2 * (3 - 0) = 0.2 * 3 = 9/10
                                          Which is not the same as the ones above.

                                          The simplest proof that the previous equations are wrong can be shown quite simply by Pythagoras' Theorem.
                                          If we assume that the triangle formed is of height and width 1 then, your equations show that the height and width of the "new" triangle which provides 20% of AB are both 0.2.
                                          If you use Pythagoras on these you get a hypotenuse of √(0.2²+0.2²) which gives √0.08 which is ~0.2828, not 0.2 as you require.


                                          Formula 1 - Short for "F1 Racing" - named after the standard "help" key in Windows, it's a sport where participants desperately search through software help files trying to find actual documentation. It's tedious and somewhat cruel, most matches ending in a draw as no participant is able to find anything helpful. - Shog9

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                                          Jun Du
                                          wrote on last edited by
                                          #60

                                          Ed.Poore wrote:

                                          x = 1*cos(θ) = 4/5 y = 1*sin(θ) = 3/5

                                          This is wrong. The length of hypotenuse is 5, not 1.

                                          Ed.Poore wrote:

                                          x = 0 + 0.2 * (4 - 0) = 0.2 * 2 = 2/5 y = 0 + 0.2 * (3 - 0) = 0.2 * 3 = 9/10

                                          This is wrong. How come 4-0 becomes 2, 0.2*3 becomes 9/10? If you hadn't made these mistakes, you could have just proved my formulas, but in a complicated way. - It's easier to make than to correct a mistake.

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