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Coding Challenge Of The Day

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  • S Steve Mayfield

    Don't you mean 'V' him?

    Steve _________________ I C(++) therefore I am

    A Offline
    A Offline
    AspDotNetDev
    wrote on last edited by
    #20

    Good catch. Live long and prosper.

    Thou mewling ill-breeding pignut!

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    • C Chris Maunder

      Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

      cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

      K Offline
      K Offline
      Karl Sanford
      wrote on last edited by
      #21

      Chris Maunder wrote:

      Roman numerals to Arabic numbers

      totally read this backward... at least now I have a solution for Arabic to Roman Numerals :doh:

      Be The Noise

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      • C Chris Maunder

        Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

        cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

        L Offline
        L Offline
        Lost User
        wrote on last edited by
        #22

        #!/usr/bin/python

        import sys

        I=1
        V=5
        X=10
        L=50
        C=100
        D=500
        M=1000

        a=0
        b=0
        c=0

        for d in map(eval,sys.argv[1]):
        if d > a:
        b += d - c
        c = 0
        else:
        b += c
        c = d
        a = d
        print b + c

        L 1 Reply Last reply
        0
        • J Joan M

          Chris... you should know that we don't make homework here... :rolleyes:

          [www.tamautomation.com] Robots, CNC and PLC machines for grinding and polishing.

          C Offline
          C Offline
          Corporal Agarn
          wrote on last edited by
          #23

          Tried to leave a similar message earlier but CP locked. I was going to add this is not QA. :)

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          • C Chris Maunder

            Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

            cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

            J Offline
            J Offline
            jesarg
            wrote on last edited by
            #24

            private int ToInt(string rom)
            {
            int length = rom.Length;
            int result = 0;
            for(int loop1=0; loop1 < length; loop1++)
            {
            char current = rom[loop1];
            char next = loop1 < length - 1 ? rom[loop1 + 1] : ' ';
            switch(current)
            {
            case 'I':
            result += next == 'V' || next == 'X' ? -1 : 1;
            break;
            case 'V':
            result += 5;
            break;
            case 'X':
            result += next == 'L' || next == 'C' ? -10 : 10;
            break;
            case 'L':
            result += 50;
            break;
            case 'C':
            result += next == 'D' || next == 'M' ? -100 : 100;
            break;
            case 'D':
            result += 500;
            break;
            case 'M':
            result += 1000;
            break;
            }
            }
            return result;
            }

            1 Reply Last reply
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            • L Lost User

              #!/usr/bin/python

              import sys

              I=1
              V=5
              X=10
              L=50
              C=100
              D=500
              M=1000

              a=0
              b=0
              c=0

              for d in map(eval,sys.argv[1]):
              if d > a:
              b += d - c
              c = 0
              else:
              b += c
              c = d
              a = d
              print b + c

              L Offline
              L Offline
              Lost User
              wrote on last edited by
              #25

              Or, somewhat more tersely,

              def r2d3(r,(s,M,C,X,I,z,V,L,D)=["%%s%d"%v for v in[1001,1000,100,10,1,0,5,50,500]]):
              return eval("".join([
              p%"+-"[eval( p%"%s>"%d%"")]
              for d,p in zip(map(eval,'%sz'%r),map(eval,'s%s'%r))
              ][1:]))

              Y 1 Reply Last reply
              0
              • C Chris Meech

                I once met a well formed roman, when I was touring through Italy. :cool:

                Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                L Offline
                L Offline
                Luc Pattyn
                wrote on last edited by
                #26

                that would be where most Romans are, don't you think? :)

                Luc Pattyn [My Articles] Nil Volentibus Arduum

                1 Reply Last reply
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                • C Chris Maunder

                  Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                  cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                  L Offline
                  L Offline
                  Luc Pattyn
                  wrote on last edited by
                  #27

                  no arrays, no dictionaries, no obscure language, just some original coding:

                  public static bool TryParseRoman(string wellFormedRoman, out int val) {
                  val=0;
                  int prevDigit=0;
                  foreach (char c in wellFormedRoman) {
                  int index="IVXLCDM".IndexOf(c);
                  if (index<0) {val=0; return false;}
                  int digit=1;
                  int factor=5;
                  while (--index>=0) { digit*=factor; factor=7-factor; }
                  if (prevDigit

                  BTW: is it Friday already?

                  :)

                  Luc Pattyn [My Articles] Nil Volentibus Arduum

                  P 1 Reply Last reply
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                  • C Chris Maunder

                    Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                    cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                    P Offline
                    P Offline
                    PIEBALDconsult
                    wrote on last edited by
                    #28

                    I'm unsure when I wrote this, but it must have been the 90s, in VAX C or DEC C. I'm shocked (shocked! I say) at the inconsistent braces. :wtf:

                    size_t
                    roman2dec
                    (
                    char *subject
                    )
                    {
                    size_t result = 0 , current , high = 0 ;
                    int index ;

                    for ( index = strlen(subject)-1 ; index >= 0 ; index-- ) {
                        switch ( (char) \*(subject + index) )
                        {
                            case 'I' :
                            case 'i' : current =    1 ; break ;
                    
                            case 'V' :
                            case 'v' : current =    5 ; break ;
                    
                            case 'X' :
                            case 'x' : current =   10 ; break ;
                    
                            case 'L' :
                            case 'l' : current =   50 ; break ;
                    
                            case 'C' :
                            case 'c' : current =  100 ; break ;
                    
                            case 'D' :
                            case 'd' : current =  500 ; break ;
                    
                            case 'M' :
                            case 'm' : current = 1000 ; break ;
                    
                            default  : current =    0 ; break ;
                        }
                    
                        if ( current < high )
                            result -= current ;
                        else
                        {
                           result += current ;
                           high = current ;
                        }
                    }
                    
                    return ( result ) ;
                    

                    }

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                    0
                    • R Ravi Bhavnani

                      Spoiler[^] /ravi

                      My new year resolution: 2048 x 1536 Home | Articles | My .NET bits | Freeware ravib(at)ravib(dot)com

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                      PIEBALDconsult
                      wrote on last edited by
                      #29

                      That's dreadful. :wtf:

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                      • C Chris Losinger

                        for well-formed roman numerals, modern rules:

                        int r2d2(const char *r)
                        {
                        int val[128];
                        memset(val,0,sizeof(int)*128);
                        val['I']=1; val['V']=5;
                        val['X']=10; val['L']=50;
                        val['C']=100; val['D']=500; val['M']=1000;

                        int a = 0;
                        for (int cv, pv = 0, i=strlen(r)-1;i>=0;i--)
                        {
                        cv = val[r[i]];
                        a += cv * (pv > cv ? -1 : 1);
                        pv = cv;
                        }

                        return a;
                        

                        }

                        image processing toolkits | batch image processing

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                        P Offline
                        PIEBALDconsult
                        wrote on last edited by
                        #30

                        Seems a waste of RAM.

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                        0
                        • C Chris Meech

                          I once met a well formed roman, when I was touring through Italy. :cool:

                          Chris Meech I am Canadian. [heard in a local bar] In theory there is no difference between theory and practice. In practice there is. [Yogi Berra] posting about Crystal Reports here is like discussing gay marriage on a catholic church’s website.[Nishant Sivakumar]

                          A Offline
                          A Offline
                          arcosupportus
                          wrote on last edited by
                          #31

                          did you get here number?

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                          0
                          • C Chris Maunder

                            Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                            cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                            J Offline
                            J Offline
                            jsc42
                            wrote on last edited by
                            #32

                            Apologies if other respondents have used a similar technique, but I have deliberately not looked at the other replies before attempting this challenge so that I am not influenced by other people's ideas. The following is in JavaScript, not obfuscated. The tricks are: Using an object literal as a lookup table and treating the double chars as subtractors from the second single chars (e.g. CM = [CM] + [M] = -100 + 1000 = 900). The only awkward part is preventing the last char being counted twice - once as a single char and once as a double char with no second char (this is done by appending '?').

                            // Roman to Arabic character translations
                            function RtoA(r) // r is roman numerals in any case
                            {
                            // Roman to Arabic conversion table
                            var Rch =
                            {
                            // Single chars: Add each value separately to the total
                            I: 1, V: 5, X: 10, L: 50, C: 100, D: 500, M: 1000,
                            // Double chars: Modify the sum of the second char as subtractors
                            CM: -100, CD: -100, XC: -10, XL: -10, IX: -1, IV: -1
                            };

                            var	R   = r.toUpperCase();  // Ignore case
                            var	A   = 0;    // Arabic equivalent
                            
                            // Parse the text converting valid single chars and double chars
                            // Set any invalid single or double char combinations as translating to zero
                            for (var i = 0; i < R.length; i++)
                            {
                            	var	ch	= R.charAt(i);
                            	A	+= 
                            		Rch\[ch + (R.charAt(i + 1) || '?')\]	// Double char conversion
                            		||	Rch\[ch\]	// Single char conversion
                            		||	0;	// No conversion - invalid char
                            };	// for
                            
                            return	A;
                            

                            }

                            alert(RtoA('MDC')); // 1600
                            alert(RtoA('mcmxcix')); // 1999

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                            • C Chris Maunder

                              Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                              cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                              R Offline
                              R Offline
                              RobertHarris
                              wrote on last edited by
                              #33

                              First time post so hope this looks OK; 1 CRT "NUMERALS: ": ; INPUT NUM 2 CRT "NUMBER : ":ICONV(NUM, 'NR') 3 END Written in UniVerse BASIC.

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                              0
                              • L Lost User

                                Or, somewhat more tersely,

                                def r2d3(r,(s,M,C,X,I,z,V,L,D)=["%%s%d"%v for v in[1001,1000,100,10,1,0,5,50,500]]):
                                return eval("".join([
                                p%"+-"[eval( p%"%s>"%d%"")]
                                for d,p in zip(map(eval,'%sz'%r),map(eval,'s%s'%r))
                                ][1:]))

                                Y Offline
                                Y Offline
                                yiangos
                                wrote on last edited by
                                #34

                                Or, somewhere in between:

                                def a6(roman):
                                if len(roman)==0:
                                return 0
                                mapping={"I":1,"V":5,"X":10,"L":50,"C":100,"D":500,"M":1000}
                                values=[mapping[digit] for digit in roman.upper()]
                                for i in range(len(values)):
                                if i

                                also, added capitalization tolerance, so that "MCM" and "mcm" evaluate the same. I haven't added a check that the argument is a valid roman numeral, but that is left as an exercise to the reader ;P

                                Φευ! Εδόμεθα υπό ρηννοσχήμων λύκων!
                                (Alas! We're devoured by lamb-guised wolves!)

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                                • C Chris Maunder

                                  Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                                  cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                                  P Offline
                                  P Offline
                                  Pascal Ganaye
                                  wrote on last edited by
                                  #35

                                  I hope it will be obscure enough. ;)

                                  class Program
                                  class Program
                                  {
                                  static int RomanToArabic(string r)
                                  {
                                  int x, y, z = x = y = 0;
                                  foreach (char c in r)
                                  y += ((z = (int)Math.Pow(10, (z = "ivxlcdm".IndexOf((char)(c | ' '))) / 2) * (1 + 4 * (z & 1))) > x ? -2 * x + (x = z) : x = z);
                                  return y;
                                  }

                                      static void Main(string\[\] args)
                                      {
                                          Console.WriteLine(RomanToArabic("MDC"));	// 1600
                                          Console.WriteLine(RomanToArabic("mcmxcix"));	// 1999
                                          Console.ReadKey();
                                      }
                                      
                                  }
                                  

                                  }

                                  L 1 Reply Last reply
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                                  • L Luc Pattyn

                                    no arrays, no dictionaries, no obscure language, just some original coding:

                                    public static bool TryParseRoman(string wellFormedRoman, out int val) {
                                    val=0;
                                    int prevDigit=0;
                                    foreach (char c in wellFormedRoman) {
                                    int index="IVXLCDM".IndexOf(c);
                                    if (index<0) {val=0; return false;}
                                    int digit=1;
                                    int factor=5;
                                    while (--index>=0) { digit*=factor; factor=7-factor; }
                                    if (prevDigit

                                    BTW: is it Friday already?

                                    :)

                                    Luc Pattyn [My Articles] Nil Volentibus Arduum

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                                    Pascal Ganaye
                                    wrote on last edited by
                                    #36

                                    This is definitely better than my attempt.

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                                    0
                                    • P Pascal Ganaye

                                      I hope it will be obscure enough. ;)

                                      class Program
                                      class Program
                                      {
                                      static int RomanToArabic(string r)
                                      {
                                      int x, y, z = x = y = 0;
                                      foreach (char c in r)
                                      y += ((z = (int)Math.Pow(10, (z = "ivxlcdm".IndexOf((char)(c | ' '))) / 2) * (1 + 4 * (z & 1))) > x ? -2 * x + (x = z) : x = z);
                                      return y;
                                      }

                                          static void Main(string\[\] args)
                                          {
                                              Console.WriteLine(RomanToArabic("MDC"));	// 1600
                                              Console.WriteLine(RomanToArabic("mcmxcix"));	// 1999
                                              Console.ReadKey();
                                          }
                                          
                                      }
                                      

                                      }

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                                      L Offline
                                      Luc Pattyn
                                      wrote on last edited by
                                      #37

                                      Nice. I like the % ' ' bits, and appreciate you used literal VII. :)

                                      Luc Pattyn [My Articles] Nil Volentibus Arduum

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                                      • L Luc Pattyn

                                        Nice. I like the % ' ' bits, and appreciate you used literal VII. :)

                                        Luc Pattyn [My Articles] Nil Volentibus Arduum

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                                        Pascal Ganaye
                                        wrote on last edited by
                                        #38

                                        oops I removed the % ' '... Ok I put back a:

                                        "ivxlcdm".IndexOf((char)(c | ' '))

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                                        • C Chris Maunder

                                          Write a function to convert Roman numerals to Arabic numbers. The smaller the better. Bonus points, as always, for obscure languages and obfuscated assembler.

                                          cheers, Chris Maunder The Code Project | Co-founder Microsoft C++ MVP

                                          P Offline
                                          P Offline
                                          Pascal Ganaye
                                          wrote on last edited by
                                          #39

                                          This is my final answer

                                          static int RomanToArabic(string roman, int x = 0, int y=0)
                                          {
                                          return roman.Length == 0 ? 0 : (y = (int)Math.Pow(10, (y = "ivxlcdm".IndexOf((char)(roman[0] | ' '))) / 2) * (1 + 4 * (y & 1))) + (y > x ? -2 * x : 0) + RomanToArabic(roman.Substring(1), y);
                                          }

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