You might consider using/creating a Domain Specific Language (DSL). General description[^]. Microsoft's take[^]. For more information just google domain specific language. That's all I know about them though, except that there are some articles here on The Code Project about them. (Use the Articles|Search menu at the top of the page). Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.” I wouldn't let CG touch my Abacus!

What about : T myObj; if (myObj is ICollectable) variance = 1.2; ?

for 6*6 cells with no more than 8 states each, not really compression, is it? :) Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum Please use <PRE> tags for code snippets, they preserve indentation, and improve readability. modified on Thursday, August 26, 2010 9:21 PM

Awesome, this is pretty much what I'm looking for

To calculate the centroid of a polygon: Source: http://en.wikipedia.org/wiki/Centroid[^] and http://local.wasp.uwa.edu.au/~pbourke/geometry/polyarea/[^] PointF centroid(PointF[] p) { // p is an array with the vertices of the polygon float cx = 0; float cy = 0; float a = 0; float ca; for (int i = 0; i < p.Length; i++) { ca = x[i] * y[(i + 1) % p.Length] - x[(i + 1) % p.Length] * y[i]; cx = cx + (x[i] + x[(i + 1) % p.Length]) * ca; cy = cy + (y[i] + y[(i + 1) % p.Length]) * ca; a = a + ca / 2; } cx = cx / (6 * a); cy = cy / (6 * a); return new PointF(cx , cy); } By the way, I am not sure if what you need is a centroid. Hope this helps, anyway.

peterchen wrote: You'll never make that! Muahaha[^] :P

I need to return to the fold. I turned it off on my old computer due to other issues, and have never loaded it on the newer one. Software Zen: delete this; Fold With Us![^]

I tried co.nr site and noip program which updates the dynamic ip to co.nr... you can google search for noip and just type in the browser as co.nr . they have this feature of forwarding. Since my modem did not have the option of port forwarding i could not set it up completely. Today's Beautiful Moments are Tomorrow's Beautiful Memories

Hi, These two solutions may be applicable to your situation. In both the main form sets a flag if the user chooses to allow a restart and Application.Restart() is called just before the Main() method returns. Method1() is mutex-less and makes the assumption that the first instance will exit before instance two 'gets going' (That's a very vague term!). Method2() will make a second instance wait for 10 seconds and then give up if the first has not released the mutex. static void Main() { //Method1(); Method2(); } private static void Method1() { Form1 f = new Form1(); Application.Run(f); if (f.RestartRequested()) { MessageBox.Show("Click to restart"); Application.Restart(); } } private static void Method2() { const String UniqueIdentifier = "{8F6F0AC4-B9A1-45fd-A8CF-72F04E6BDE8F}"; Mutex mutex; Boolean firstInstance; mutex = new Mutex(true, UniqueIdentifier, out firstInstance); if (!firstInstance) { if (!mutex.WaitOne(TimeSpan.FromSeconds(10))) { MessageBox.Show("2nd instance did not aquire the mutex\n" + "and cannot start"); return; } } Form1 f = new Form1(); Application.Run(f); if (f.RestartRequested()) { Application.Restart(); MessageBox.Show("Click within 10 seconds to start the new instance"); mutex.ReleaseMutex(); } mutex.Close(); } Alan. modified on Thursday, March 4, 2010 7:34 PM

The process is not in my app, so the Activate(); trick wont work for me. The managed code is a microsoft certification requirement. It's fine if there are 3rd party assemblies in my project that call unmanaged code, but there cannot be any in any of the code I've written.