Hi, Let me see if I understood. You are trying to create a web application that will work like a Windows Explorer showing folders and their contents. But besides the ability to show the folder's content upon clicking on it, you want to be able to show an image when the user hover the mouse over the little yellow folder (the folder). Is that right? Instead of using this interface, why don't exchange message by email. Don't you agree? my email is contact@kynou.com :) www.kynou.com/chat.aspx

Hi, Why don't you create custom control deriving from the WebPart class? In other words, define the webpart entirely in code. Contact me so that I can help you: contact@KYNOU.com :) sfdsfsdf

Hi, It seems to me that you are describing a scenario where you want the web application to check if a certain condition is matched on the server side (in this case the ip and port). If so, the client should get a pop-up. If I understood this correctly, you could use AJAX. AJAX allows you to add code on the client to constantly (without a great penaulty) check with the server if a certain condition was matched. There are several websites out there introducing the concept of AJAX. Even my website www.kynou.com has some introduction tutorials about it. I also have a chat room in my website where I try to spend a lot time there. Try to find me there so that you can give me more details about or email me contact@KYNOU.com :)

Yes you can. You can create a custom control that derives from WebPart class. There is a tutorial that kind of shows you how to do that at www.kynou.com. Search for webpart If you it doesn't help you, leave chat with me in the chat room of the same website. I hope I helped :) sfdsfsdf

Hi, One of the ways is by using parametized report. Assuming that you know how to create parameters in the Crystal Reports report file, all you need to do is pass the value of the parameter dynamically like the code below: reportDocument1.Load(@"c:\inetpub\wwwroot\CrystalReportSample\report.rpt"); reportDocument1.SetDatabaseLogon("sa","password"); reportDocument1.SetParameterValue("state",txtState.Text); CrystalReportViewer1.ReportSource=reportDocument1; CrystalReportViewer1.DataBind(); If that didn't answer your question, contact me: contact@KYNOU.com or see if I'm online in the chat room at www.KYNOU.com I hope I helped :)

Hi, You need to use CSS. In the HTML view, add a STYLE tag within the HEAD tag.For example: .labelCSS { FONT-SIZE: 18px; FONT-FAMILY: Arial } Then, set the cssClass to the name of the css class that you chose (in this example labelCSS. In other words, in the cssClass property of the LAbel control type "labelCSS". Notice that there is no . (dot) in the cssClass property, only when you define the class in the style tag. If you have any question, check if I'm online in the chat room at www.kynou.com I hope I helped :)

Hi, Could you give me more info? I'm not getting the whole pic. Is it a web application or windows app? You can contact me at contact@KYNOU.com or in the chat room at www.KYNOU.com

Hi, I didn't understand. Are you asking a question or just stating something? :) I'm online at www.KYNOU.com if you need help

Hi, If I undersdood correctly, why don't you use nested tables? In other words, place the image in a separate table. I'm usually online in the chat room of the site www.KNYOU.com Stop by if you need help. :) sfdsfsdf

Hi, Use the following code: LinkButton lb = (LinkButton)DataGrid1.Items[e.Item.ItemIndex].Controls[2].Controls[0]; I posted some tutorials on how to customize the DataGrid control at www.KYNOU.com. There is also a chat room there and I try to be there as long as I can. If you have any question please stop by and I will be glad to try to help you. :)

Hi guys, I just want to let you know that I just created a new tutorial that walks you through the steps of creating an ASP.NET Chat application using AJAX. It doesn't just show you how to use AJAX in a chat app but also how to make an ASP.NET control AJAX-enabled. In this example, I make a DataGrid turn into a DataGrid AJAX enabled. To launch the tutorial, go to www.KYNOU.com, click on the "Tutorial Index" link, click on the AJAX node in the tree and click on the "Select" button next to the tutorial called "Ajax enabled DataGrid - Chat Application Example". Keep in mind that this site is a search engine, so another way to find the tutorial (or even other tutorials) is by searching for it. I hope you guys like it :)

Hi, Nothing special, the same way you would add swf files into an html file. Just change to the html view of the page and manually add the tag pointing to it. When you launch the application you will see the animation playing. If you want to chat with me live, I will be in the chat room of the site www.kynou.com I hope I helped :) sfdsfsdf

Hello my friend, I didn't quite understand what you're trying to do. Do you want to chat live so that you can give me more details? I'll be in the chat room of www.kynou.com See you there :) ps: My name is going to appear as Viegas

Hi, Use interop to access the twain com object for this purpose: [DllImport("twain_32.dll", EntryPoint="#1")] If you want me to create a tutorial walking you through the process of using this technique, please send me a note through the website: www.KYNOU.com I hoped I helped :)

Hi, First of all, are you using asp.net or windows? If it is windows you can use the code below: private void dataGrid1_Click(object sender, System.EventArgs e) { DataTable dt = dataGrid1.DataSource as DataTable; if(dt!=null) { string firstField = (dt.Rows[dataGrid1.CurrentRowIndex][0].ToString()); } } As you can see, what I'm doing is casting the datasource datagrid's property to a datatable object. Then using the CurrentRowIndex property I can obtain any field's values from the datatable. If it is an asp.net application, then you can use the code below: private void DataGrid1_ItemCommand(object source, System.Web.UI.WebControls.DataGridCommandEventArgs e) { if(e.CommandName=="Select") { string id = e.Item.Cells[1].Text; Response.Write(id); } } In this case, I'm assuming the ID of the row is presented in the second column (since the first one is the SELECT link). I created a tutorial about GridView control (asp.net 2.0) at www.KYNOU.com. I'm always in this website's chat room. If you want to chat with me live logon to it. I hope I helped :)

Sorry!!! When I pasted my code it seems that CodeProject removed the actual code and shows a link. The missing part is showing you that all you have to change in your code is make sure the returned value from the window.open method is stored in a dummy variable. JavaScript:var obj = window.open( Again, if I didn't explain well in this little note, contact me at www.KYNOU.com

Hi, All you have to do is pass the returned value of the window.open method to a variable. the code below shows you how to do that: private void Page_Load(object sender, System.EventArgs e) { string tmpHtml = "event center"; Response.Write(tmpHtml); } As you can see, all I'm doing is setting the dummy obj variable with the returned value of the window.open method. By doing this it eliminates the [object] error. If you want to chat with me live, go to the Chat Room of the www.KYNOU.com website. sfdsfsdf

Hi, If you need to get an ID field in the datagrid, you just need to cast the DataSource property of the datagrid control to a DataTable object. Then, by calling the CurrentRowIndex property of the datagrid control, you can determine the picked row. Let's say the first field in the datatable is the ID field that you want to obtain, you can get its value by using the code below: private void dataGrid1_Click(object sender, System.EventArgs e) { DataTable dt = dataGrid1.DataSource as DataTable; if(dt!=null) { string firstField = (dt.Rows[dataGrid1.CurrentRowIndex][0].ToString()); } } If you need any more help or ask me more questions find me at the chat room of the www.KYNOU.com website. If you want me to post a new tutorial at the www.KYNOU.com website, use the Request New Tutorial link of the website. :)

Hi, Use a

instead of a textbox. Make sure the nowrap property of it is not set. Use the
to break the lines within the

container. When people ask questions, I like to create a tutorial (because I think by doing is how you learn) about the solution of the question. If you want, I can post a new tutorial at www.KYNOU.com (where I place my tutorials) showing you how to do this. Chat with me at the chat room inside of the website. See you there :)

Hi, I posted a tutorial at www.KYNOU.com talking about injecting javascript code into your asp.net project at runtime. Search for "javascript" once you are at the indicated website. I'm usually in the chat room of the website. So, if you want to chat with me so that you can give me info about what you need go to the Chat Room of www.KYNOU.com sfdsfsdf