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Interview follow up

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  • J Jonathan Nethercott

    This looks like correlation (autocorrelation?) to me. I would look for a solution along the lines of: num xor (num shift left 1) num xor (num shift left 2) etc. repeat until (number of bits / 2) Not a very good bit of pseudo code, but hopefully you get the idea ;) I'm not sure how you'd deal with leading and trailing parts of a sequence, but I'm sure there must be an elegant way of incorporating that...

    Jon CodeWrite

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    leppie
    wrote on last edited by
    #18

    Jon Nethercott wrote:

    I'm not sure how you'd deal with leading and trailing parts of a sequence, but I'm sure there must be an elegant way of incorporating that...

    There are no leading parts (thank FSM!). As for the trailing bit, my elegant solution was to do a negative right shift (see line 11, when rs is negative) that fits into the rest (test on line 17). Brain too tired to remember exactly what I did there now ;p

    IronScheme
    ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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    • S Septimus Hedgehog

      When will you hear if you've got the job? Best of luck.

      "I do not have to forgive my enemies, I have had them all shot." — Ramón Maria Narváez (1800-68). "I don't need to shoot my enemies, I don't have any." - Me (2012).

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      leppie
      wrote on last edited by
      #19

      PHS241 wrote:

      When will you hear if you've got the job?

      He wants to have another telephonic discussion next week and I guess an offer will be made at that stage, if they so desire.

      IronScheme
      ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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      • L leppie

        Jon Nethercott wrote:

        I'm not sure how you'd deal with leading and trailing parts of a sequence, but I'm sure there must be an elegant way of incorporating that...

        There are no leading parts (thank FSM!). As for the trailing bit, my elegant solution was to do a negative right shift (see line 11, when rs is negative) that fits into the rest (test on line 17). Brain too tired to remember exactly what I did there now ;p

        IronScheme
        ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

        J Offline
        J Offline
        Jonathan Nethercott
        wrote on last edited by
        #20

        I think this should do it:

        private int BinaryPeriod(int num)
        {
        int result = -1;
        int numBits = (int)((Math.Log(num) / Math.Log(2))) + 1;

        for (int i = 1; i <= numBits / 2 && result == -1; i++)
        {
            if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)
                result = i;
        }
        return result;
        

        }

        I've done it in C#, but hopefully it should be fairly generic code. The important line is:

        if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)

        which strips the top i bits and XORs that with num right shifted. If the result is 0 then we have found an autocorrelation.

        Jon CodeWrite

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        • J Jonathan Nethercott

          I think this should do it:

          private int BinaryPeriod(int num)
          {
          int result = -1;
          int numBits = (int)((Math.Log(num) / Math.Log(2))) + 1;

          for (int i = 1; i <= numBits / 2 && result == -1; i++)
          {
              if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)
                  result = i;
          }
          return result;
          

          }

          I've done it in C#, but hopefully it should be fairly generic code. The important line is:

          if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)

          which strips the top i bits and XORs that with num right shifted. If the result is 0 then we have found an autocorrelation.

          Jon CodeWrite

          L Offline
          L Offline
          leppie
          wrote on last edited by
          #21

          Very good! Wish I knew of it :(

          IronScheme
          ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

          J 1 Reply Last reply
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          • J Jonathan Nethercott

            I think this should do it:

            private int BinaryPeriod(int num)
            {
            int result = -1;
            int numBits = (int)((Math.Log(num) / Math.Log(2))) + 1;

            for (int i = 1; i <= numBits / 2 && result == -1; i++)
            {
                if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)
                    result = i;
            }
            return result;
            

            }

            I've done it in C#, but hopefully it should be fairly generic code. The important line is:

            if (((num & ((1 << (numBits - i)) - 1)) ^ (num >> i)) == 0)

            which strips the top i bits and XORs that with num right shifted. If the result is 0 then we have found an autocorrelation.

            Jon CodeWrite

            L Offline
            L Offline
            leppie
            wrote on last edited by
            #22

            And here we have it in Scheme :) http://eval.ironscheme.net/?id=59[^] Thanks again!

            IronScheme
            ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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            • L leppie

              Very good! Wish I knew of it :(

              IronScheme
              ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

              J Offline
              J Offline
              Jonathan Nethercott
              wrote on last edited by
              #23

              Thank you :) I love solving problems like this - although that has distracted me a bit from what I'm supposed to be doing ;P Good luck with the job!

              Jon CodeWrite

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              • L leppie

                Was given a problem that was suppose to come from the 'easy' bin. Two hours later I was still not finished... On the plus side, the interviewer attempted the problem at the same time, and also got stuck :) He said the problem must have been miscategorized. He told me to finish at home and to send the solution when done ;p Anyways, after a good nights sleep (with some wack apocalyptic dream I had), I started from scratch and coded a solution in about an hour this morning. The given problem: Binary period (dont bother googling for answers as you will likely just end up getting astronomy results or if you have google foo, a few very mathematical papers mostly related to cryptography) Given a number N larger than 0 (range was given, but does not matter), find the minimum period of repeating bit sequences or -1 if none is found. Examples

                110110110 => 3 (as 110 repeats)
                11011011 => 3 (still 3 and valid as the remaining subset, 11, is in 110)
                110110111 => -1 (no period)
                101 => -1 (no repeats, repeat implies at least 2 sequences)
                10101 => 2 (repeat at least over 2 sequences)
                11 => 1

                10101010101 => 2
                111011011101101110 => 7
                111111111111111110 => -1

                My answer in Scheme can be viewed and run here[^]. Edit: Web host seems to be down now... Edit 2: Seems to be back up again, please only look one at a time ;p Damn you shared hosting. If above link is down, view here[^].

                IronScheme
                ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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                Ennis Ray Lynch Jr
                wrote on last edited by
                #24

                Heh, I had to do that in University.

                Need custom software developed? I do custom programming based primarily on MS tools with an emphasis on C# development and consulting. I also do Android Programming as I find it a refreshing break from the MS. "And they, since they Were not the one dead, turned to their affairs" -- Robert Frost

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                • E Ennis Ray Lynch Jr

                  Heh, I had to do that in University.

                  Need custom software developed? I do custom programming based primarily on MS tools with an emphasis on C# development and consulting. I also do Android Programming as I find it a refreshing break from the MS. "And they, since they Were not the one dead, turned to their affairs" -- Robert Frost

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                  leppie
                  wrote on last edited by
                  #25

                  Was that some kind of homework or other task? Perhaps thesis? ;p

                  IronScheme
                  ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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                  • L leppie

                    Was that some kind of homework or other task? Perhaps thesis? ;p

                    IronScheme
                    ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

                    E Offline
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                    Ennis Ray Lynch Jr
                    wrote on last edited by
                    #26

                    Well my degree was computer science. All we did was learn stuff like this. Wouldn't say I knew much about "programming" until after school. But solving problems with code, easy.

                    Need custom software developed? I do custom programming based primarily on MS tools with an emphasis on C# development and consulting. I also do Android Programming as I find it a refreshing break from the MS. "And they, since they Were not the one dead, turned to their affairs" -- Robert Frost

                    L 1 Reply Last reply
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                    • E Ennis Ray Lynch Jr

                      Well my degree was computer science. All we did was learn stuff like this. Wouldn't say I knew much about "programming" until after school. But solving problems with code, easy.

                      Need custom software developed? I do custom programming based primarily on MS tools with an emphasis on C# development and consulting. I also do Android Programming as I find it a refreshing break from the MS. "And they, since they Were not the one dead, turned to their affairs" -- Robert Frost

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                      leppie
                      wrote on last edited by
                      #27

                      Not even in my 2nd year course (just before I decided to go back to working class) we did stuff like this... I left when when we were busy with Data Structures and Algorithms.

                      IronScheme
                      ((λ (x) `(,x ',x)) '(λ (x) `(,x ',x)))

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