1 = 0
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if the numerator and denominator are equal then the value must be 1. Then the second part is almost right, but you missed a very important point, a recurring value is only an *approximation* rather than the absolute. 1/3 is absolute, but the decimal 0.3. is only an approximation. Proof, without bad maths of the 9's reccuring - 0.9. == 1 Multiply by 10: 9.9. = 10 Subtract the original: 9.9. - 0.9. = 9 9 = 9 QED. This is accepted as proper maths, the 1=0 using division by zero is, however, not.
veni bibi saltavi
Nice :) But i guess as long as we have an approximation i'll go with its not exactly 1 :P
Nagy Vilmos wrote:
This is accepted as proper maths, the 1=0 using division by zero is, however, not.
I already said that in an other statement that hes wrong
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x = y. Then x2 = xy. Subtract the same thing from both sides: x2 - y2 = xy - y2. Dividing by (x-y), obtain x + y = y. Since x = y, we see that 2 y = y. Thus 2 = 1, since we started with y nonzero. Subtracting 1 from both sides, 1 = 0. :wtf:
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Ah, the ol' divide by zero trick. I think my math teacher did that when I was in 8th grade. Almost 40 years ago. And I'm sure it's older than that. ;) Marc
Imperative to Functional Programming Succinctly Contributors Wanted for Higher Order Programming Project!
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CPallini wrote:
(likewise Computer Science is not Mathematics)
But its both logic :) And 0,999 is not 1 it's even written different :sigh: But i guess we could debate ages about that
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CPallini wrote:
(likewise Computer Science is not Mathematics)
But its both logic :) And 0,999 is not 1 it's even written different :sigh: But i guess we could debate ages about that
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CPallini wrote:
(likewise Computer Science is not Mathematics)
But its both logic :) And 0,999 is not 1 it's even written different :sigh: But i guess we could debate ages about that
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}Take your pick: How Can 0.999... = 1? | Purplemath[^] For example:
x = 0.999...10x = 9.999...
10x - x = 9.000...
9x = 9
x = 1EDIT: As Nagy said[^], 2+ hours ago.
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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Take your pick: How Can 0.999... = 1? | Purplemath[^] For example:
x = 0.999...10x = 9.999...
10x - x = 9.000...
9x = 9
x = 1EDIT: As Nagy said[^], 2+ hours ago.
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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Take your pick: How Can 0.999... = 1? | Purplemath[^] For example:
x = 0.999...10x = 9.999...
10x - x = 9.000...
9x = 9
x = 1EDIT: As Nagy said[^], 2+ hours ago.
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
1/6 = 0,166666 ->*6 0,9996
x = 0,9996
10x = 9,996
10x -x = 8,9964
9x = 8,9964
x = 0,9996?
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HobbyProggy wrote:
1/6 = 0,166666 ->*6 0,9996
Nope -
6 × 0.1666... = 0.9999...It's simple multiplication:1 x 6 = 6 (0.6)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.96)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.9996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.99996)
etc.Because you're repeating the operation an infinite number of times, there's no point where you stop and leave the last digit as
6. There's always another digit to the right which needs to be multiplied by6, carrying the3into the current column.
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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HobbyProggy wrote:
1/6 = 0,166666 ->*6 0,9996
Nope -
6 × 0.1666... = 0.9999...It's simple multiplication:1 x 6 = 6 (0.6)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.96)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.9996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.99996)
etc.Because you're repeating the operation an infinite number of times, there's no point where you stop and leave the last digit as
6. There's always another digit to the right which needs to be multiplied by6, carrying the3into the current column.
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
So this works only for 0.999999 ? Because the 6 at the end is in this case important to show that it wont be a 1 in the end :) But nevermind, this is all just playing with numbers :)
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So this works only for 0.999999 ? Because the 6 at the end is in this case important to show that it wont be a 1 in the end :) But nevermind, this is all just playing with numbers :)
if(this.signature != "")
{
MessageBox.Show("This is my signature: " + Environment.NewLine + signature);
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}HobbyProggy wrote:
Because the 6 at the end is ...
But there isn't a
6at the "end", because there isn't an "end"! :laugh: Think of it like this:using System;
static class Program
{
static void Main()
{
while (true)
{
Console.WriteLine("9");
}Console.WriteLine("Squirrel!"); }}
If you run that program, how long will you have to wait before it prints "Squirrel"?
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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HobbyProggy wrote:
Because the 6 at the end is ...
But there isn't a
6at the "end", because there isn't an "end"! :laugh: Think of it like this:using System;
static class Program
{
static void Main()
{
while (true)
{
Console.WriteLine("9");
}Console.WriteLine("Squirrel!"); }}
If you run that program, how long will you have to wait before it prints "Squirrel"?
"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer
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Do you mean they are imaginary? :doh: :doh: :doh: This is getting more and more difficult by moments. I think I am grabbing a bier, maybe seeing it double makes it easier :rolleyes: ;P :laugh: :laugh: I'll get my coat
M.D.V. ;) If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about? Help me to understand what I'm saying, and I'll explain it better to you Rating helpful answers is nice, but saying thanks can be even nicer.
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So this works only for 0.999999 ? Because the 6 at the end is in this case important to show that it wont be a 1 in the end :) But nevermind, this is all just playing with numbers :)
if(this.signature != "")
{
MessageBox.Show("This is my signature: " + Environment.NewLine + signature);
}
else
{
MessageBox.Show("404-Signature not found");
}mmm working by 9, not working by 6 what about 69? does it works? Oh, wait... I think I stop now since I am about to break the KSS rule :laugh: :laugh: I am still on the way getting my coat
M.D.V. ;) If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about? Help me to understand what I'm saying, and I'll explain it better to you Rating helpful answers is nice, but saying thanks can be even nicer.
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Ah, the ol' divide by zero trick. I think my math teacher did that when I was in 8th grade. Almost 40 years ago. And I'm sure it's older than that. ;) Marc
Imperative to Functional Programming Succinctly Contributors Wanted for Higher Order Programming Project!
Since I remember it from math about that time it has to be old. :-D How can I remember this but cannot find my car keys?
Mongo: Mongo only pawn... in game of life.
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Dominic Burford wrote:
x2 - y2 = xy - y2. Dividing by (x-y), obtain x + y = y.
Wrong... aint it? x2 -y2 / (x-y) => x+y xy -y2 / (x-y) => y+y xy / x-y => 1*1/1-1 => (actually how could you divide this when there is a minus...) y2 / x-y => y/x-1 => (actually how could you devide this when there is a minus...) But i guess thats bullshit 2 because it "should"? be x2/x-y - y2/x-y which ruins everything :) Okay screw everything... you are wrong, thats all i can say :)
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