1 = 0

[CPallini]

Quote:

Dividing by (x-y), obtain...

...the silent reproach of a million tear-stained eyes. :((

[CPallini]

Quote:

0,99999.... which is technically 1 but not 100%

Uh?

[HobbyProggy]

Whats the matter ?

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[Rage]

Dominic Burford wrote:

since we started with y nonzero.

oh, the irony.

Do not escape reality : improve reality !

[Nagy Vilmos]

if the numerator and denominator are equal then the value must be 1. Then the second part is almost right, but you missed a very important point, a recurring value is only an *approximation* rather than the absolute. 1/3 is absolute, but the decimal 0.3. is only an approximation. Proof, without bad maths of the 9's reccuring - 0.9. == 1 Multiply by 10: 9.9. = 10 Subtract the original: 9.9. - 0.9. = 9 9 = 9 QED. This is accepted as proper maths, the 1=0 using division by zero is, however, not.

veni bibi saltavi

[HobbyProggy]

Nice :) But i guess as long as we have an approximation i'll go with its not exactly 1 :P

Nagy Vilmos wrote:

This is accepted as proper maths, the 1=0 using division by zero is, however, not.

I already said that in an other statement that hes wrong

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[CPallini]

0.9999... is 1.

[HobbyProggy]

By definition, not by maths :)

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[Marc Clifton]

Ah, the ol' divide by zero trick. I think my math teacher did that when I was in 8th grade. Almost 40 years ago. And I'm sure it's older than that. ;) Marc

Imperative to Functional Programming Succinctly Contributors Wanted for Higher Order Programming Project!

[CPallini]

By maths. There's no difference.

[HobbyProggy]

Allright, tell that the next flightcomputer that breakes down because he multiplied 0,333 and didn't get to 1 ;)

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[CPallini]

You know, float are not real numbers. (likewise Computer Science is not Mathematics) :-D

[HobbyProggy]

CPallini wrote:

(likewise Computer Science is not Mathematics)

But its both logic :) And 0,999 is not 1 it's even written different :sigh: But i guess we could debate ages about that

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[CPallini]

Right: we could follow all the nines until we find a difference. :laugh:

[Richard Deeming]

Take your pick: How Can 0.999... = 1? | Purplemath[^] For example:

  x = 0.999...

10x = 9.999...
10x - x = 9.000...
9x = 9
x = 1

EDIT: As Nagy said[^], 2+ hours ago.

---

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[HobbyProggy]

1/6 ->*6 0,966666666

x = 0,9666
10x = 9,6666
10x -x = 8,7066
9x = 8,7066
x = 0,9674

!

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[HobbyProggy]

1/6 = 0,166666 ->*6 0,9996

x = 0,9996
10x = 9,996
10x -x = 8,9964
9x = 8,9964
x = 0,9996

?

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[Richard Deeming]

HobbyProggy wrote:

1/6 = 0,166666 ->*6 0,9996

Nope - 6 × 0.1666... = 0.9999... It's simple multiplication:

1 x 6 = 6 (0.6)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.96)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.9996)
6 x 6 = 36 = add 3 to the column on the left (6 + 3 = 9), and put 6 in this column (0.99996)
etc.

Because you're repeating the operation an infinite number of times, there's no point where you stop and leave the last digit as 6. There's always another digit to the right which needs to be multiplied by 6, carrying the 3 into the current column.

---

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[HobbyProggy]

So this works only for 0.999999 ? Because the 6 at the end is in this case important to show that it wont be a 1 in the end :) But nevermind, this is all just playing with numbers :)

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[Richard Deeming]

HobbyProggy wrote:

Because the 6 at the end is ...

But there isn't a 6 at the "end", because there isn't an "end"! :laugh: Think of it like this:

using System;

static class Program
{
static void Main()
{
while (true)
{
Console.WriteLine("9");
}

    Console.WriteLine("Squirrel!");
}

}

If you run that program, how long will you have to wait before it prints "Squirrel"?

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