Thanks for a hint CPallini :rose: , I will look it. If u can Dream... U can do it

Wouldnt it be enough to put the Logo in the Output Window via BitBlt. If you get the stream it isnt yours, so you cant do your Logo in it. :confused: Greetings from Germany

It will be gr8 if you provide one example. If u can Dream... U can do it

thanks: https://movied.org

krishnadevank wrote: and i want to get those polygons inside that bounding box.It should be fast enough (At least don't take minutes ). Several ways jump out. First You have the zone, you can render one more frame with a clip-buffer which isolates the polygons individually within the zones. You can identify which ones by coloring each differently, or split the work out, by doing so in each 2D image slice. Remember that even at 20-60hz you can take a frame to do some work and then get back to the job of drawing. Multi-rendering methods make great shortcuts. You can also use the obscure test from the ARB and setup an obscuring object everywhere except the zone of interest, and get back only those triangles within the zone. You can also do the same test as you draw, using a multi-render cycle you can check the result of the projection and write to see if it should be clipped or kept with a stencil buffer and test the triangles you need. Once again you can brute force it, or break it down, test slice by slice to see if any triangles are in the zone on cycle 0, then test those triangles in each slice one at a time for zone proximity, cycle 1+. Within a couple of frame cycles you can find all the triangles you need. _________________________ Asu no koto o ieba, tenjo de nezumi ga warau. Talk about things of tomorrow and the mice in the ceiling laugh. (Japanese Proverb)

Thanks Steve.:-D . If u can Dream... U can do it

Hi steve I tried with a value -1.0 for tranlation. I think there still exists some problems. I put a point on the screen using GL_POINT. When the point location was at (0,0) every thing loooks fine , ie the point was on the orgin(0,0,0). then i tried with value (1,0,0) , and translation in z direction glTranslate(0,0,-1). But the result is intersting. it vanished from the screen. ( :(( ) . Then i checked it by resizing the window , then it became visible at some time. There must be problem with aspect ratio i think.(the asepect ration i put was width/height). Any thoughts ? Thanks krishnan If u can Dream... U can do it

SaRath C wrote: how r u doing? :) Fine, Just freaking around here :-D "Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow cheers, Alok Gupta VC Forum Q&A :- I/ IV Support CRY- Child Relief and You

hi Mike Adding CS_DROPSHADOW is good idea .. But i want to chage the color of shadow i want to give color shadows . Thats my problem. Like this The First color will be Color::Red The Second wll be Color::Transparent and i would like to paint it with a LinerGradientBrush. What you think , Mike ? If u can Dream... U can do it -- modified at 1:54 Thursday 4th May, 2006

During my study about operator overloding , this happend. First time I was Surpried.. Then tried to find out the latest changes in the code.. Then i found the reason.. I think this happens while pasrsing done by visual studio to generate class information etc.. I think It is BUG it is not present 2005 If u can Dream... U can do it

The MaxLength property of the TextBox lets you set a maximum number of characters that the user can enter, no matter the width (it can be 10 m's or 10 i's). But if you set the TextBox to be, say, 100 pixels wide, and you want only 100 pixels of letters, be it 5 m's or 8 i's, it's a bit more difficult. As an option, try using the MaxLength property and making the TextBox wide enough. But if you absolutely need to allow only a certain width of characters, try getting the font of the control, and using some graphics function (MeasureString could be, I am no expert.) to measure the current contents plus the new character in the KeyDown event, and if the new text is wider than the control, don't accept the key. I hope to have given you some pointers. Good luck! -- LuisR Luis Alonso Ramos Intelectix - Chihuahua, Mexico Not much here: My CP Blog!

I am saying that instead of using a transform, you should just draw the bit you want to see. Most DrawImage functions take a rect that defines the part of the bitmap to draw. Use them. Christian I have several lifelong friends that are New Yorkers but I have always gravitated toward the weirdo's. - Richard Stringer

the easiest way is to try to open any existing port. If the port exist but already in use, any attemt to open it will fail. For more information about working with COM-ports make a search on MSDN looking for RS232 - a standard for serial communications. "Absolution requires sacrifice" -- Dan Brown 'The Da Vinci code'