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  3. one equal to two ?

one equal to two ?

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  • M Member 11330876

    damn it is so hard :/

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    L Offline
    Lost User
    wrote on last edited by
    #30

    That's what she said.

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    • B BillWoodruff

      The error is in your lack of understanding what this Forum is for and so posting an utterly inappropriate message.

      «OOP to me means only messaging, local retention and protection and hiding of state-process, and extreme late-binding of all things. »  Alan Kay's clarification on what he meant by the term "Object" in "Object-Oriented Programming."

      V Offline
      V Offline
      Vikram A Punathambekar
      wrote on last edited by
      #31

      A little unlike your usual self - woke up from the wrong side of the bed today? :) Sure, it's decades old, but hardly inappropriate given the other drivel that goes on here.

      Cheers, विक्रम "We have already been through this, I am not going to repeat myself." - fat_boy, in a global warming thread :doh:

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      • J Jorgen Andersson

        The eleventh commandment: Thou shall not divide with zero.

        Wrong is evil and must be defeated. - Jeff Ello (√-shit)2

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        T Offline
        tayoufabrice
        wrote on last edited by
        #32

        :laugh: :laugh: :laugh:

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        • S Super Lloyd

          There is no error! 1 is indeed equal to 2 for very large value of 1! I think this is what just happened to you! :rolleyes: :-D

          My programming get away... The Blog... All in one Menu-Ribbon Bar DirectX for WinRT/C# since 2013! Taking over the world since 1371!

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          tayoufabrice
          wrote on last edited by
          #33

          0 = false 1 or 2 or >2 = true 1=true 2=true ... ?? :laugh: :laugh:

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          • L Lost User

            Hey do you want to lend me $2000? If so just give us half of it now, that will mean I owe you $1000 and you owe me $1000 and that will mean we are even.

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            P Offline
            PIEBALDconsult
            wrote on last edited by
            #34

            Abbott and Costello said it better.

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            • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

              Quote:

              a(a-a)=(a+a)(a-a)

              Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

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              tayoufabrice
              wrote on last edited by
              #35

              :thumbsdown: I don't think, this is a simple factorization

              Kornfeld Eliyahu PeterK 1 Reply Last reply
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              • T tayoufabrice

                Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

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                PIEBALDconsult
                wrote on last edited by
                #36

                The error begins from first assumptions -- saying 1=1 at the beginning is meaningless; everthing following can provide no additional insight. a²-a² and a-a are always zero, but this is due to the nonsense above that -- in particular, while a²-a²=a²-a² may be true, it doesn't follow from a²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh:

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                • L Lost User

                  That's what she said.

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                  PIEBALDconsult
                  wrote on last edited by
                  #37

                  Nah, she didn't day "damn", she said "f......". :-D

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                  • T tayoufabrice

                    :thumbsdown: I don't think, this is a simple factorization

                    Kornfeld Eliyahu PeterK Offline
                    Kornfeld Eliyahu PeterK Offline
                    Kornfeld Eliyahu Peter
                    wrote on last edited by
                    #38

                    That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...

                    Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                    "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

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                    • P PIEBALDconsult

                      The error begins from first assumptions -- saying 1=1 at the beginning is meaningless; everthing following can provide no additional insight. a²-a² and a-a are always zero, but this is due to the nonsense above that -- in particular, while a²-a²=a²-a² may be true, it doesn't follow from a²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh:

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                      tayoufabrice
                      wrote on last edited by
                      #39

                      :laugh: As I know mathematics doesn't approve 0=0 so, the error is a²-a²=a²-a² (meaning 0=0) exactly it is a teacher who showed it to us.

                      Kornfeld Eliyahu PeterK 1 Reply Last reply
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                      • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

                        That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...

                        Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

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                        T Offline
                        tayoufabrice
                        wrote on last edited by
                        #40

                        ok !! :thumbsup: My best answer[^]

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                        • T tayoufabrice

                          :laugh: As I know mathematics doesn't approve 0=0 so, the error is a²-a²=a²-a² (meaning 0=0) exactly it is a teacher who showed it to us.

                          Kornfeld Eliyahu PeterK Offline
                          Kornfeld Eliyahu PeterK Offline
                          Kornfeld Eliyahu Peter
                          wrote on last edited by
                          #41

                          It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

                          Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                          "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

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                          • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

                            It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

                            Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

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                            PIEBALDconsult
                            wrote on last edited by
                            #42

                            Yes, but the damage is done before that.

                            Kornfeld Eliyahu PeterK 1 Reply Last reply
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                            • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

                              It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

                              Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

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                              T Offline
                              tayoufabrice
                              wrote on last edited by
                              #43

                              1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =

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                              • T tayoufabrice

                                Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                                R Offline
                                R Offline
                                R Giskard Reventlov
                                wrote on last edited by
                                #44

                                tayoufabrice wrote:

                                Where is the error ?

                                In between your ears: obviously the answer is 42.

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                                • T tayoufabrice

                                  Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

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                                  phil o
                                  wrote on last edited by
                                  #45

                                  a - a = 0

                                  You cannot get anything useful from a multiplication once it has involved a zero term.

                                  5 x 0 = 12012 x 0

                                  does not mean that

                                  5 = 12012

                                  There are two kinds of people in the world: those who can extrapolate from incomplete data.

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                                  • T tayoufabrice

                                    1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =

                                    P Offline
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                                    PIEBALDconsult
                                    wrote on last edited by
                                    #46

                                    At the final step, you effectively have a=0, which means that a/a=1 on the second line is division by zero. But why were b and c introduced? It's just nonsense. Additionally, a²=b² certainly does not mean a=b.

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                                    • T tayoufabrice

                                      Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                                      P Offline
                                      P Offline
                                      pt1401
                                      wrote on last edited by
                                      #47

                                      The error is simultaneously in line 5, your misunderstanding of basic maths, and your posting of this question.

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                                      • T tayoufabrice

                                        Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                                        Mike HankeyM Offline
                                        Mike HankeyM Offline
                                        Mike Hankey
                                        wrote on last edited by
                                        #48

                                        The error is I haven't had coffee yet.

                                        New version: WinHeist Version 2.1.0 There's a fine line between crazy and free spirited and it's usually a prescription. I'm currently unsupervised, I know it freaks me out too but the possibilities are endless.

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                                        • P PIEBALDconsult

                                          At the final step, you effectively have a=0, which means that a/a=1 on the second line is division by zero. But why were b and c introduced? It's just nonsense. Additionally, a²=b² certainly does not mean a=b.

                                          T Offline
                                          T Offline
                                          tayoufabrice
                                          wrote on last edited by
                                          #49

                                          a=0 never means a/a=0 (a can never be 0). a=a <=> a/a=a/a <=> 1=1 I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded)

                                          Kornfeld Eliyahu PeterK 1 Reply Last reply
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