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  3. one equal to two ?

one equal to two ?

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  • T tayoufabrice

    Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

    P Offline
    P Offline
    PIEBALDconsult
    wrote on last edited by
    #36

    The error begins from first assumptions -- saying 1=1 at the beginning is meaningless; everthing following can provide no additional insight. a²-a² and a-a are always zero, but this is due to the nonsense above that -- in particular, while a²-a²=a²-a² may be true, it doesn't follow from a²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh:

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    • L Lost User

      That's what she said.

      P Offline
      P Offline
      PIEBALDconsult
      wrote on last edited by
      #37

      Nah, she didn't day "damn", she said "f......". :-D

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      • T tayoufabrice

        :thumbsdown: I don't think, this is a simple factorization

        Kornfeld Eliyahu PeterK Offline
        Kornfeld Eliyahu PeterK Offline
        Kornfeld Eliyahu Peter
        wrote on last edited by
        #38

        That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...

        Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

        "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

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        • P PIEBALDconsult

          The error begins from first assumptions -- saying 1=1 at the beginning is meaningless; everthing following can provide no additional insight. a²-a² and a-a are always zero, but this is due to the nonsense above that -- in particular, while a²-a²=a²-a² may be true, it doesn't follow from a²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh:

          T Offline
          T Offline
          tayoufabrice
          wrote on last edited by
          #39

          :laugh: As I know mathematics doesn't approve 0=0 so, the error is a²-a²=a²-a² (meaning 0=0) exactly it is a teacher who showed it to us.

          Kornfeld Eliyahu PeterK 1 Reply Last reply
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          • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

            That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...

            Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

            T Offline
            T Offline
            tayoufabrice
            wrote on last edited by
            #40

            ok !! :thumbsup: My best answer[^]

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            • T tayoufabrice

              :laugh: As I know mathematics doesn't approve 0=0 so, the error is a²-a²=a²-a² (meaning 0=0) exactly it is a teacher who showed it to us.

              Kornfeld Eliyahu PeterK Offline
              Kornfeld Eliyahu PeterK Offline
              Kornfeld Eliyahu Peter
              wrote on last edited by
              #41

              It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

              Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

              "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

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              • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

                It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

                Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                P Offline
                P Offline
                PIEBALDconsult
                wrote on last edited by
                #42

                Yes, but the damage is done before that.

                Kornfeld Eliyahu PeterK 1 Reply Last reply
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                • Kornfeld Eliyahu PeterK Kornfeld Eliyahu Peter

                  It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...

                  Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                  T Offline
                  T Offline
                  tayoufabrice
                  wrote on last edited by
                  #43

                  1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =

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                  • T tayoufabrice

                    Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                    R Offline
                    R Offline
                    R Giskard Reventlov
                    wrote on last edited by
                    #44

                    tayoufabrice wrote:

                    Where is the error ?

                    In between your ears: obviously the answer is 42.

                    T 1 Reply Last reply
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                    • T tayoufabrice

                      Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                      P Offline
                      P Offline
                      phil o
                      wrote on last edited by
                      #45

                      a - a = 0

                      You cannot get anything useful from a multiplication once it has involved a zero term.

                      5 x 0 = 12012 x 0

                      does not mean that

                      5 = 12012

                      There are two kinds of people in the world: those who can extrapolate from incomplete data.

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                      • T tayoufabrice

                        1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =

                        P Offline
                        P Offline
                        PIEBALDconsult
                        wrote on last edited by
                        #46

                        At the final step, you effectively have a=0, which means that a/a=1 on the second line is division by zero. But why were b and c introduced? It's just nonsense. Additionally, a²=b² certainly does not mean a=b.

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                        • T tayoufabrice

                          Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                          P Offline
                          P Offline
                          pt1401
                          wrote on last edited by
                          #47

                          The error is simultaneously in line 5, your misunderstanding of basic maths, and your posting of this question.

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                          • T tayoufabrice

                            Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                            Mike HankeyM Offline
                            Mike HankeyM Offline
                            Mike Hankey
                            wrote on last edited by
                            #48

                            The error is I haven't had coffee yet.

                            New version: WinHeist Version 2.1.0 There's a fine line between crazy and free spirited and it's usually a prescription. I'm currently unsupervised, I know it freaks me out too but the possibilities are endless.

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                            • P PIEBALDconsult

                              At the final step, you effectively have a=0, which means that a/a=1 on the second line is division by zero. But why were b and c introduced? It's just nonsense. Additionally, a²=b² certainly does not mean a=b.

                              T Offline
                              T Offline
                              tayoufabrice
                              wrote on last edited by
                              #49

                              a=0 never means a/a=0 (a can never be 0). a=a <=> a/a=a/a <=> 1=1 I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded)

                              Kornfeld Eliyahu PeterK 1 Reply Last reply
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                              • P phil o

                                a - a = 0

                                You cannot get anything useful from a multiplication once it has involved a zero term.

                                5 x 0 = 12012 x 0

                                does not mean that

                                5 = 12012

                                There are two kinds of people in the world: those who can extrapolate from incomplete data.

                                T Offline
                                T Offline
                                tayoufabrice
                                wrote on last edited by
                                #50

                                very very TRUE:thumbsup::thumbsup:

                                1 Reply Last reply
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                                • R R Giskard Reventlov

                                  tayoufabrice wrote:

                                  Where is the error ?

                                  In between your ears: obviously the answer is 42.

                                  T Offline
                                  T Offline
                                  tayoufabrice
                                  wrote on last edited by
                                  #51

                                  the answer is 42 :laugh: :laugh:

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                                  • T tayoufabrice

                                    a=0 never means a/a=0 (a can never be 0). a=a <=> a/a=a/a <=> 1=1 I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded)

                                    Kornfeld Eliyahu PeterK Offline
                                    Kornfeld Eliyahu PeterK Offline
                                    Kornfeld Eliyahu Peter
                                    wrote on last edited by
                                    #52

                                    Which means that you have an equation system and not a single equation...It's a different thing to solve...

                                    Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                                    "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

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                                    • P PIEBALDconsult

                                      Yes, but the damage is done before that.

                                      Kornfeld Eliyahu PeterK Offline
                                      Kornfeld Eliyahu PeterK Offline
                                      Kornfeld Eliyahu Peter
                                      wrote on last edited by
                                      #53

                                      You mean, when OP went to learn math?

                                      Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.

                                      "It never ceases to amaze me that a spacecraft launched in 1977 can be fixed remotely from Earth." ― Brian Cox

                                      1 Reply Last reply
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                                      • T tayoufabrice

                                        Let read this : 1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2 Where is the error ?

                                        R Offline
                                        R Offline
                                        RedDk
                                        wrote on last edited by
                                        #54

                                        This is best asked here: http://www.codeproject.com/script/Answers/List.aspx?tags=900&alltags=true[^]

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                                        • P PIEBALDconsult

                                          Abbott and Costello said it better.

                                          M Offline
                                          M Offline
                                          Mark_Wallace
                                          wrote on last edited by
                                          #55

                                          PIEBALDconsult wrote:

                                          Abbott and Costello_, who were on first,_ said it better.

                                          It was missing something.

                                          I wanna be a eunuchs developer! Pass me a bread knife!

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