one equal to two ?
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There is no error! 1 is indeed equal to 2 for very large value of 1! I think this is what just happened to you! :rolleyes: :-D
My programming get away... The Blog... All in one Menu-Ribbon Bar DirectX for WinRT/C# since 2013! Taking over the world since 1371!
0 = false 1 or 2 or >2 = true 1=true 2=true ... ?? :laugh: :laugh:
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Hey do you want to lend me $2000? If so just give us half of it now, that will mean I owe you $1000 and you owe me $1000 and that will mean we are even.
Abbott and Costello said it better.
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Quote:
a(a-a)=(a+a)(a-a)
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ?The error begins from first assumptions -- saying
1=1at the beginning is meaningless; everthing following can provide no additional insight.a²-a²anda-aare always zero, but this is due to the nonsense above that -- in particular, whilea²-a²=a²-a²may be true, it doesn't follow froma²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh: -
Nah, she didn't day "damn", she said "f......". :-D
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:thumbsdown: I don't think, this is a simple factorization
That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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The error begins from first assumptions -- saying
1=1at the beginning is meaningless; everthing following can provide no additional insight.a²-a²anda-aare always zero, but this is due to the nonsense above that -- in particular, whilea²-a²=a²-a²may be true, it doesn't follow froma²=a². The idiot of a Discrete Math teacher I had in college tried showing this to the class once. :sigh: -
That you do not think so it will not change the fact that, when you move from this line to the next, you actually divide by zero - (a-a)!!! More! A solution of an equation must be traversal to both direction - yours is not! a=a a²=a² This is a one-way step and is forbidden...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
ok !! :thumbsup: My best answer[^]
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:laugh: As I know mathematics doesn't approve 0=0 so, the error is a²-a²=a²-a² (meaning 0=0) exactly it is a teacher who showed it to us.
It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
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It has nothing to do with 0 equal to 0 or not (which is a mathematical game only), but the fact that division by zero is not permitted (or more precisely the outcome is undefined)...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =
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Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ?tayoufabrice wrote:
Where is the error ?
In between your ears: obviously the answer is 42.
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Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ? -
1=1 a=a <=> a/a=1 a²=a² ?? a=b <=> a/b=1 a²=b² ?? then a=b a-c = b-c ? a-a = a-a (assuming a=b and a=c) ?? Where is the division by zero ? I've added c at both sides of =
At the final step, you effectively have
a=0, which means thata/a=1on the second line is division by zero. But why werebandcintroduced? It's just nonsense. Additionally,a²=b²certainly does not meana=b. -
Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ? -
Let read this :
1=1 a=a a²=a² a²-a²=a²-a² a(a-a)=(a+a)(a-a) a=a+a a(1)=a(1+1) 1=1+1 1=2Where is the error ?The error is I haven't had coffee yet.
New version: WinHeist Version 2.1.0 There's a fine line between crazy and free spirited and it's usually a prescription. I'm currently unsupervised, I know it freaks me out too but the possibilities are endless.
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At the final step, you effectively have
a=0, which means thata/a=1on the second line is division by zero. But why werebandcintroduced? It's just nonsense. Additionally,a²=b²certainly does not meana=b. -
a - a = 0
You cannot get anything useful from a multiplication once it has involved a zero term.
5 x 0 = 12012 x 0
does not mean that
5 = 12012
There are two kinds of people in the world: those who can extrapolate from incomplete data.
very very
TRUE:thumbsup::thumbsup: -
tayoufabrice wrote:
Where is the error ?
In between your ears: obviously the answer is 42.
the answer is 42 :laugh: :laugh:
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a=0 never means a/a=0 (a can never be 0). a=a <=> a/a=a/a <=> 1=1 I could fix the post as : Given a C ]--;0[ U ]0;++[ (meaning 0 excluded)
Which means that you have an equation system and not a single equation...It's a different thing to solve...
Skipper: We'll fix it. Alex: Fix it? How you gonna fix this? Skipper: Grit, spit and a whole lotta duct tape.
