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Coding Challenge - Morris Sequence

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  • Richard DeemingR Richard Deeming

    Kenneth Haugland wrote:

    I don't think is enough not if you start at 3,4,5 or any other number, at least I got some 5 then.

    Whatever digit you start with will always be in the last position. No other digit will exceed 3, no matter how many iterations you try. For example, if in iteration n you get 41, then that means iteration n-1 must have had ...x1111.... But given the rules of the sequence, that would have to be written as either (x+1)1 or 21.


    "These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

    K Offline
    K Offline
    Kenneth Haugland
    wrote on last edited by
    #41

    Ah, yes that makes sense. Also seems to be that the higher the number of iterations the higher of LSB seems to be equal? if you can find that formula you might shorten the calculations by quite a bit.

    1 Reply Last reply
    0
    • D Dave Kreskowiak

      Oh, it's possible. My machine is sitting here listing the iteration, length, and time to calculate for each of the 100 numbers.

      System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
      Dave Kreskowiak

      K Offline
      K Offline
      Kenneth Haugland
      wrote on last edited by
      #42

      So how long did it take? Did you do something in parallell or?

      D 1 Reply Last reply
      0
      • K Kenneth Haugland

        So how long did it take? Did you do something in parallell or?

        D Offline
        D Offline
        Dave Kreskowiak
        wrote on last edited by
        #43

        I'll say 82 took my machine 59 seconds.

        System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
        Dave Kreskowiak

        1 Reply Last reply
        0
        • D Dave Kreskowiak

          It's also known as the Conway Sequence, Look and Say Sequence, and probably some others. It's rather simple. Start with a 1 and then describe what you see for the next iteration. So, starting at 1, the next number is one 1 (11), the next is two 1 (21), then one 2 one 1 (1211), and so on:

          1
          11
          21
          1211
          111221
          312211

          The question to answer is what's the length in digits of the 100th number in the chain, starting with "1" as the first? The first six numbers have been given above. You could write it out by hand, but I wouldn't recommend it, and as developers, that's not what we do. The seemingly simple challenge is to write the code to come up with the answer. The only hint you get is the 50th number is 894,810 digits long. Oh, and don't bother Googling for code. Those examples will only get you so far and definitely won't get you to the answer.

          System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
          Dave Kreskowiak

          A Offline
          A Offline
          AVNTizzy
          wrote on last edited by
          #44

          Still running...85 minutes in... currently at: Loop 76: Length 881752750

          D 1 Reply Last reply
          0
          • A AVNTizzy

            Still running...85 minutes in... currently at: Loop 76: Length 881752750

            D Offline
            D Offline
            Dave Kreskowiak
            wrote on last edited by
            #45

            85 MINUTES?! You'll be running this for about a week to get to 100. It can be done a lot quicker than that. The 76th number took 12 seconds on my machine and it's a "nothing special" machine.

            System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
            Dave Kreskowiak

            A 1 Reply Last reply
            0
            • D Dave Kreskowiak

              85 MINUTES?! You'll be running this for about a week to get to 100. It can be done a lot quicker than that. The 76th number took 12 seconds on my machine and it's a "nothing special" machine.

              System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
              Dave Kreskowiak

              A Offline
              A Offline
              AVNTizzy
              wrote on last edited by
              #46

              I thought I would run out ot memory and did it writing to a file...not the smartest idea...now I just can't bring myself to stop the run.

              1 Reply Last reply
              0
              • D Dave Kreskowiak

                It's also known as the Conway Sequence, Look and Say Sequence, and probably some others. It's rather simple. Start with a 1 and then describe what you see for the next iteration. So, starting at 1, the next number is one 1 (11), the next is two 1 (21), then one 2 one 1 (1211), and so on:

                1
                11
                21
                1211
                111221
                312211

                The question to answer is what's the length in digits of the 100th number in the chain, starting with "1" as the first? The first six numbers have been given above. You could write it out by hand, but I wouldn't recommend it, and as developers, that's not what we do. The seemingly simple challenge is to write the code to come up with the answer. The only hint you get is the 50th number is 894,810 digits long. Oh, and don't bother Googling for code. Those examples will only get you so far and definitely won't get you to the answer.

                System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                Dave Kreskowiak

                D Offline
                D Offline
                Dave Kreskowiak
                wrote on last edited by
                #47
                1. Strings and string methods are not going to do it. They're too slow and take up too much memory. 2) The only digits you see in any of these numbers are 1, 2, and 3. It seems like a waste to use an entire byte to store each digit. 3) If you graph the math on the progression of the length of these numbers, you'll see that on a LOGARITHMIC SCALE, the graph is about a 40 degree line. What would that look like on a normal X/Y scale? 4) You cannot do this "in memory", without going to the extremes of cleverness, and even then, you'd still need a gargantuan amount of RAM.

                System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                Dave Kreskowiak

                A P 2 Replies Last reply
                0
                • D Dave Kreskowiak

                  4,326,816,254 to be exact.

                  System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                  Dave Kreskowiak

                  G Offline
                  G Offline
                  GuyThiebaut
                  wrote on last edited by
                  #48

                  Yep - that's the count I get too :thumbsup:

                  “That which can be asserted without evidence, can be dismissed without evidence.”

                  ― Christopher Hitchens

                  1 Reply Last reply
                  0
                  • D Dave Kreskowiak
                    1. Strings and string methods are not going to do it. They're too slow and take up too much memory. 2) The only digits you see in any of these numbers are 1, 2, and 3. It seems like a waste to use an entire byte to store each digit. 3) If you graph the math on the progression of the length of these numbers, you'll see that on a LOGARITHMIC SCALE, the graph is about a 40 degree line. What would that look like on a normal X/Y scale? 4) You cannot do this "in memory", without going to the extremes of cleverness, and even then, you'd still need a gargantuan amount of RAM.

                    System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                    Dave Kreskowiak

                    A Offline
                    A Offline
                    AVNTizzy
                    wrote on last edited by
                    #49

                    Good hints...gonna have another crack at this back home.

                    1 Reply Last reply
                    0
                    • K Kenneth Haugland

                      Well, he did only ask about the length of the 100 th number. So according to Look-and-say sequence - Wikipedia[^]. Dave told us that the 50th number had length:

                      L50 = 894810

                      And the wikipedia article said:

                      L_n+1/L_n= lambda = 1.303577269034

                      so....

                      L50*lambda^(50)= 511175198256

                      if my math is right enough. Very hard programming challange :D

                      A Offline
                      A Offline
                      AVNTizzy
                      wrote on last edited by
                      #50

                      close...about 72 million off...

                      1 Reply Last reply
                      0
                      • D Dave Kreskowiak
                        1. Strings and string methods are not going to do it. They're too slow and take up too much memory. 2) The only digits you see in any of these numbers are 1, 2, and 3. It seems like a waste to use an entire byte to store each digit. 3) If you graph the math on the progression of the length of these numbers, you'll see that on a LOGARITHMIC SCALE, the graph is about a 40 degree line. What would that look like on a normal X/Y scale? 4) You cannot do this "in memory", without going to the extremes of cleverness, and even then, you'd still need a gargantuan amount of RAM.

                        System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                        Dave Kreskowiak

                        P Offline
                        P Offline
                        PIEBALDconsult
                        wrote on last edited by
                        #51

                        The length of row n won't exceed twice the length of row n-1 , yes? The result is computable, therefore a Turing Machine can compute it, and, because Turing Machines have virtually unlimited storage, simply use one.

                        D 1 Reply Last reply
                        0
                        • P PIEBALDconsult

                          The length of row n won't exceed twice the length of row n-1 , yes? The result is computable, therefore a Turing Machine can compute it, and, because Turing Machines have virtually unlimited storage, simply use one.

                          D Offline
                          D Offline
                          Dave Kreskowiak
                          wrote on last edited by
                          #52

                          You build the machine and I'll go make the infinite paper tape.

                          System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                          Dave Kreskowiak

                          1 Reply Last reply
                          0
                          • D Dave Kreskowiak

                            It's also known as the Conway Sequence, Look and Say Sequence, and probably some others. It's rather simple. Start with a 1 and then describe what you see for the next iteration. So, starting at 1, the next number is one 1 (11), the next is two 1 (21), then one 2 one 1 (1211), and so on:

                            1
                            11
                            21
                            1211
                            111221
                            312211

                            The question to answer is what's the length in digits of the 100th number in the chain, starting with "1" as the first? The first six numbers have been given above. You could write it out by hand, but I wouldn't recommend it, and as developers, that's not what we do. The seemingly simple challenge is to write the code to come up with the answer. The only hint you get is the 50th number is 894,810 digits long. Oh, and don't bother Googling for code. Those examples will only get you so far and definitely won't get you to the answer.

                            System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                            Dave Kreskowiak

                            P Offline
                            P Offline
                            PIEBALDconsult
                            wrote on last edited by
                            #53

                            The spec isn't clear! Send it back! :wtf: As this is, in essence, a compression algorithm, at line 8->9 (according to the OEIS) I would do:

                            1113213211

                            11 132132 11 <== three subsequences

                            21 2132 21 <== three outputs, eight digits

                            Which is shorter than their naive result of:

                            1113213211

                            111 3 2 1 3 2 11 <== seven subsequences

                            31 13 12 11 13 12 21 <== seven outputs, fourteen digits

                            A 40% saving. The complexity of the algorithm increases due to seeking how to split the input into the fewest subsequences of some repetition length (1 in the naive implementation).

                            D 1 Reply Last reply
                            0
                            • D Dave Kreskowiak

                              It's also known as the Conway Sequence, Look and Say Sequence, and probably some others. It's rather simple. Start with a 1 and then describe what you see for the next iteration. So, starting at 1, the next number is one 1 (11), the next is two 1 (21), then one 2 one 1 (1211), and so on:

                              1
                              11
                              21
                              1211
                              111221
                              312211

                              The question to answer is what's the length in digits of the 100th number in the chain, starting with "1" as the first? The first six numbers have been given above. You could write it out by hand, but I wouldn't recommend it, and as developers, that's not what we do. The seemingly simple challenge is to write the code to come up with the answer. The only hint you get is the 50th number is 894,810 digits long. Oh, and don't bother Googling for code. Those examples will only get you so far and definitely won't get you to the answer.

                              System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                              Dave Kreskowiak

                              U Offline
                              U Offline
                              User 13520686
                              wrote on last edited by
                              #54

                              340472211484 approx (via log extrapolation)

                              D P 2 Replies Last reply
                              0
                              • P PIEBALDconsult

                                The spec isn't clear! Send it back! :wtf: As this is, in essence, a compression algorithm, at line 8->9 (according to the OEIS) I would do:

                                1113213211

                                11 132132 11 <== three subsequences

                                21 2132 21 <== three outputs, eight digits

                                Which is shorter than their naive result of:

                                1113213211

                                111 3 2 1 3 2 11 <== seven subsequences

                                31 13 12 11 13 12 21 <== seven outputs, fourteen digits

                                A 40% saving. The complexity of the algorithm increases due to seeking how to split the input into the fewest subsequences of some repetition length (1 in the naive implementation).

                                D Offline
                                D Offline
                                Dave Kreskowiak
                                wrote on last edited by
                                #55

                                When in the :elephant: is the spec Everclear[^] ? Project Euler specs aren't clear either. We always have to do the best we can with what we've got. :-D

                                1113213211

                                11 132132 11 <== 13?

                                21 132132 21 <== three outputs, eight digits

                                What happened to the 13? The output looks like it should be 10 digits, not 8.

                                1113213211

                                111 32132 11

                                31 32132 21 <== if I understand what you're trying to do

                                There seems to a problem with representation. How do you tell the difference between single values and a run length value?

                                System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                                Dave Kreskowiak

                                P 1 Reply Last reply
                                0
                                • U User 13520686

                                  340472211484 approx (via log extrapolation)

                                  D Offline
                                  D Offline
                                  Dave Kreskowiak
                                  wrote on last edited by
                                  #56

                                  Nope, not even close.

                                  System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                                  Dave Kreskowiak

                                  U 1 Reply Last reply
                                  0
                                  • D Dave Kreskowiak

                                    When in the :elephant: is the spec Everclear[^] ? Project Euler specs aren't clear either. We always have to do the best we can with what we've got. :-D

                                    1113213211

                                    11 132132 11 <== 13?

                                    21 132132 21 <== three outputs, eight digits

                                    What happened to the 13? The output looks like it should be 10 digits, not 8.

                                    1113213211

                                    111 32132 11

                                    31 32132 21 <== if I understand what you're trying to do

                                    There seems to a problem with representation. How do you tell the difference between single values and a run length value?

                                    System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                                    Dave Kreskowiak

                                    P Offline
                                    P Offline
                                    PIEBALDconsult
                                    wrote on last edited by
                                    #57

                                    Dave Kreskowiak wrote:

                                    What happened to the 13?

                                    There are 2 132s , hence 2132.

                                    Dave Kreskowiak wrote:

                                    How do you tell the difference between single values and a run length value?

                                    Doesn't matter, but internally (if I write it) it would be in the data structure. It just wouldn't be apparent in the output unless you want it.

                                    (1,1)
                                    (2,1)
                                    ...
                                    (2,1),(2,132),(2,1)
                                    ...

                                    The question is about only the number of digits.

                                    D 1 Reply Last reply
                                    0
                                    • U User 13520686

                                      340472211484 approx (via log extrapolation)

                                      P Offline
                                      P Offline
                                      PIEBALDconsult
                                      wrote on last edited by
                                      #58

                                      What base? The length is 10 -- in some base I haven't determined yet.

                                      1 Reply Last reply
                                      0
                                      • D Dave Kreskowiak

                                        It's also known as the Conway Sequence, Look and Say Sequence, and probably some others. It's rather simple. Start with a 1 and then describe what you see for the next iteration. So, starting at 1, the next number is one 1 (11), the next is two 1 (21), then one 2 one 1 (1211), and so on:

                                        1
                                        11
                                        21
                                        1211
                                        111221
                                        312211

                                        The question to answer is what's the length in digits of the 100th number in the chain, starting with "1" as the first? The first six numbers have been given above. You could write it out by hand, but I wouldn't recommend it, and as developers, that's not what we do. The seemingly simple challenge is to write the code to come up with the answer. The only hint you get is the 50th number is 894,810 digits long. Oh, and don't bother Googling for code. Those examples will only get you so far and definitely won't get you to the answer.

                                        System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                                        Dave Kreskowiak

                                        K Offline
                                        K Offline
                                        Kenneth Haugland
                                        wrote on last edited by
                                        #59

                                        So I stored booleans in a file:

                                        string Morris(int S, int N)
                                        {
                                        string projectPath = System.IO.Path.GetFullPath(@"..\..\..\");
                                        using (BinaryWriter writer = new BinaryWriter(File.Open(projectPath + "input.txt", FileMode.Create)))
                                        {
                                        writer.Write(S > 2);
                                        writer.Write(S == 2);
                                        }

                                                for (int i = 1; i < N; i++)
                                                {
                                                    Debug.WriteLine(i+1);
                                        
                                                    using (BinaryReader reader = new BinaryReader(File.Open(projectPath + "input.txt", FileMode.Open)))
                                                    {
                                                        int count = 1;
                                                        bool currMSB = reader.ReadBoolean();
                                                        bool currLSB = reader.ReadBoolean();
                                        
                                                        bool nextMSB, nextLSB;
                                        
                                                        using (BinaryWriter writer = new BinaryWriter(File.Open(projectPath + "output.txt", FileMode.Create)))
                                                        {
                                                            while (reader.BaseStream.Position != reader.BaseStream.Length)
                                                            {
                                                                nextMSB = reader.ReadBoolean();
                                                                nextLSB = reader.ReadBoolean();
                                        
                                                                if ((currMSB == nextMSB) && (currLSB == nextLSB))
                                                                {
                                                                    count++;
                                                                }
                                                                else
                                                                {
                                                                    writer.Write(count > 2);
                                                                    writer.Write(count == 2);
                                                                    writer.Write(currMSB);
                                                                    writer.Write(currLSB);
                                        
                                                                    currMSB = nextMSB;
                                                                    currLSB = nextLSB;
                                                                    count = 1;
                                                                }
                                        
                                                            }
                                                            writer.Write(count > 2);
                                                            writer.Write(count == 2);
                                                            writer.Write(currMSB);
                                                            writer.Write(currLSB);
                                                        }
                                                    }
                                        
                                                    File.Delete(projectPath + "input.txt");
                                                    System.IO.File.Copy(projectPath + "output.txt", projectPath + "input.txt");
                                                    System.IO.File.WriteAllText(projectPath + "output.txt", string.Empty);
                                                }
                                        
                                        
                                                StringBuilder output = new StringBuilder();
                                                using (BinaryReader reader = new BinaryReader(File.Open(projectPath + "input.txt", FileMode.Ope
                                        
                                        D 1 Reply Last reply
                                        0
                                        • P PIEBALDconsult

                                          Dave Kreskowiak wrote:

                                          What happened to the 13?

                                          There are 2 132s , hence 2132.

                                          Dave Kreskowiak wrote:

                                          How do you tell the difference between single values and a run length value?

                                          Doesn't matter, but internally (if I write it) it would be in the data structure. It just wouldn't be apparent in the output unless you want it.

                                          (1,1)
                                          (2,1)
                                          ...
                                          (2,1),(2,132),(2,1)
                                          ...

                                          The question is about only the number of digits.

                                          D Offline
                                          D Offline
                                          Dave Kreskowiak
                                          wrote on last edited by
                                          #60

                                          Ah, OK. I missed that. Hmmm. In my implementation, I wrote up a reader/writer that takes care of the "on the fly". This would make an interesting, and challenging, implementation to write. I'll have to look into trying this next weekend. My current implementation writes all the data but there is an option to convert the data to a human-readable format. Not that you'd want to see thousands of pages of 1's, 2's, and 3's, but it did come in handy for analysis when experimenting with implementations.

                                          System.ItDidntWorkException: Something didn't work as expected. C# - How to debug code[^]. Seriously, go read these articles.
                                          Dave Kreskowiak

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