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Hardcore Maths Question

Scheduled Pinned Locked Moved Algorithms
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  • J Jon Sagara

    N(1) = 2519 N(2) = 2519 + 2520 = 5039 N(3) = 2519 + 2520 + 2520 = 7559 N(4) = 2519 + 2520 + 2520 + 2520 = 10079 ... N(n) = 2519 + (n - 1)*(2520) No idea what the heck it means, though. Care to enlighten us mathematically-challenged folks?

    Jon Sagara When I grow up, I'm changing my name to Joe Kickass! My Site | My Blog | My Articles

    L Offline
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    leppie
    wrote on last edited by
    #18

    Some other interesting and useless observations:

    1*2*3*4*5*6*7*8*9 is divisible by 2520 = 144
    2520 is divisible by 2 * 3 * 5 * 7 = 12 (product of prime 1 - 9)
    4 * 6 * 8 * 9 is divisible by 144 = 12 (product of 'non' prime 1 - 9)

    :doh:

    **

    xacc.ide-0.2.0.50 - now with partial MSBuild support!

    **

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    • R Raj Lal

      Ok lets me be the first to ask a maths question Find a number which 1. divided by 10 gives a remainder 9 2. divided by 9 gives remainder 8 --- --- so on till divided by 2 gives a remainder 1 Any one ?

      Omit Needless Words - Strunk, William, Jr.


      Online Project Management
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      JenovaProject
      wrote on last edited by
      #19

      10! - 1 = 3628799. Its 1 less than a multiple of 1, 2, 3 ... 10.

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      • J JenovaProject

        10! - 1 = 3628799. Its 1 less than a multiple of 1, 2, 3 ... 10.

        I Offline
        I Offline
        Ingo
        wrote on last edited by
        #20

        ((3628799 + 1) / 10) / (2 * 3 * 4 * 6) + (9 - 7 + 8 - 10) + 1 = 2519. ;)

        ------------------------------ PROST Roleplaying Game War doesn't determine who's right. War determines who's left.

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        • R Raj Lal

          Ok lets me be the first to ask a maths question Find a number which 1. divided by 10 gives a remainder 9 2. divided by 9 gives remainder 8 --- --- so on till divided by 2 gives a remainder 1 Any one ?

          Omit Needless Words - Strunk, William, Jr.


          Online Project Management
          Universal DBA | Ajax Rating | ExplorerTree

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          Bassam Abdul Baki
          wrote on last edited by
          #21

          x = (i - 1) (mod i), 2 ≤ i ≤ 10. Thus, x = LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) * k + LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) - 1 LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) = LCM(5, 7, 8, 9) = 23.32.5.7 = 2520. Thus, x = 2520k + 2519. min(x) = 2519. I had to redo it since I did it backwards.


          "People who want to share their religious views with you almost never want you to share yours with them." - Anonymous Web - Blog - RSS - Math - LinkedIn

          Last modified: Thursday, July 27, 2006 12:08:26 PM --

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          • R Raj Lal

            Ok lets me be the first to ask a maths question Find a number which 1. divided by 10 gives a remainder 9 2. divided by 9 gives remainder 8 --- --- so on till divided by 2 gives a remainder 1 Any one ?

            Omit Needless Words - Strunk, William, Jr.


            Online Project Management
            Universal DBA | Ajax Rating | ExplorerTree

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            K Offline
            Kacee Giger
            wrote on last edited by
            #22

            I know I'm a little late (and a valid solution has already been given), but no real explanation has been made. You first need to find a number that is a multiple of all these multiples (10 * 9, 9 * 8, etc), then one less than that will give the proper remainders. So, to find the least common multiple, first break these into primes: 10 * 9 = 2 * 3 * 3 * 5, 9 * 8 = 2 * 2 * 2 * 3 * 3, 8 * 7 = 2 * 2 * 2 * 7, etc. Take out what is unique for each to get 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520. So, one answer (though you already know) to the original problem is 2519.

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            • J Jon Sagara

              N(1) = 2519 N(2) = 2519 + 2520 = 5039 N(3) = 2519 + 2520 + 2520 = 7559 N(4) = 2519 + 2520 + 2520 + 2520 = 10079 ... N(n) = 2519 + (n - 1)*(2520) No idea what the heck it means, though. Care to enlighten us mathematically-challenged folks?

              Jon Sagara When I grow up, I'm changing my name to Joe Kickass! My Site | My Blog | My Articles

              R Offline
              R Offline
              Raj Lal
              wrote on last edited by
              #23

              its the LCM of all the numbers (2520) - 1

              Omit Needless Words - Strunk, William, Jr.


              Online Project Management
              Universal DBA | Ajax Rating | ExplorerTree

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              • K Kacee Giger

                I know I'm a little late (and a valid solution has already been given), but no real explanation has been made. You first need to find a number that is a multiple of all these multiples (10 * 9, 9 * 8, etc), then one less than that will give the proper remainders. So, to find the least common multiple, first break these into primes: 10 * 9 = 2 * 3 * 3 * 5, 9 * 8 = 2 * 2 * 2 * 3 * 3, 8 * 7 = 2 * 2 * 2 * 7, etc. Take out what is unique for each to get 2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520. So, one answer (though you already know) to the original problem is 2519.

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                U Offline
                User 12346520
                wrote on last edited by
                #24

                thanks: https://movied.org

                1 Reply Last reply
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                • B Bassam Abdul Baki

                  x = (i - 1) (mod i), 2 ≤ i ≤ 10. Thus, x = LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) * k + LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) - 1 LCM(2, 3, 4, 5, 6, 7, 8, 9, 10) = LCM(5, 7, 8, 9) = 23.32.5.7 = 2520. Thus, x = 2520k + 2519. min(x) = 2519. I had to redo it since I did it backwards.


                  "People who want to share their religious views with you almost never want you to share yours with them." - Anonymous Web - Blog - RSS - Math - LinkedIn

                  Last modified: Thursday, July 27, 2006 12:08:26 PM --

                  U Offline
                  U Offline
                  User 12346520
                  wrote on last edited by
                  #25

                  thanks: https://movied.org

                  1 Reply Last reply
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                  • I Ingo

                    ((3628799 + 1) / 10) / (2 * 3 * 4 * 6) + (9 - 7 + 8 - 10) + 1 = 2519. ;)

                    ------------------------------ PROST Roleplaying Game War doesn't determine who's right. War determines who's left.

                    U Offline
                    U Offline
                    User 12346520
                    wrote on last edited by
                    #26

                    thanks: https://movied.org

                    1 Reply Last reply
                    0
                    • J JenovaProject

                      10! - 1 = 3628799. Its 1 less than a multiple of 1, 2, 3 ... 10.

                      U Offline
                      U Offline
                      User 12346520
                      wrote on last edited by
                      #27

                      thanks: https://movied.org

                      1 Reply Last reply
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                      • R Raj Lal

                        its the LCM of all the numbers (2520) - 1

                        Omit Needless Words - Strunk, William, Jr.


                        Online Project Management
                        Universal DBA | Ajax Rating | ExplorerTree

                        U Offline
                        U Offline
                        User 12346520
                        wrote on last edited by
                        #28

                        thanks: https://movied.org

                        1 Reply Last reply
                        0
                        • J Jon Sagara

                          N(1) = 2519 N(2) = 2519 + 2520 = 5039 N(3) = 2519 + 2520 + 2520 = 7559 N(4) = 2519 + 2520 + 2520 + 2520 = 10079 ... N(n) = 2519 + (n - 1)*(2520) No idea what the heck it means, though. Care to enlighten us mathematically-challenged folks?

                          Jon Sagara When I grow up, I'm changing my name to Joe Kickass! My Site | My Blog | My Articles

                          U Offline
                          U Offline
                          User 12346520
                          wrote on last edited by
                          #29

                          thanks: https://movied.org

                          1 Reply Last reply
                          0
                          • J Judah Gabriel Himango

                            Quartz... wrote:

                            It's the journey, not the destination

                            Very true. I actually had fun writing a little piece of code to solve it, though, so it was the journey even still. :) I added some more code that added each match to a list box on a Windows Form. Then, after seeing how it froze up the UI, I did it on a background thread. Still, the UI thread would get flooded with matches, almost preventing it from painting, so I further chagned the code to only update during app idle. Voila, cool little WinForms program that solves it. :cool:

                            Tech, life, family, faith: Give me a visit. I'm currently blogging about: Messianic Instrumentals (with audio) The apostle Paul, modernly speaking: Epistles of Paul Judah Himango

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                            User 12346520
                            wrote on last edited by
                            #30

                            thanks: https://movied.org

                            1 Reply Last reply
                            0
                            • L leppie

                              Some other interesting and useless observations:

                              1*2*3*4*5*6*7*8*9 is divisible by 2520 = 144
                              2520 is divisible by 2 * 3 * 5 * 7 = 12 (product of prime 1 - 9)
                              4 * 6 * 8 * 9 is divisible by 144 = 12 (product of 'non' prime 1 - 9)

                              :doh:

                              **

                              xacc.ide-0.2.0.50 - now with partial MSBuild support!

                              **

                              U Offline
                              U Offline
                              User 12346520
                              wrote on last edited by
                              #31

                              thanks: https://movied.org

                              1 Reply Last reply
                              0
                              • L leppie

                                Jon Sagara wrote:

                                N(n) = 2519 + (n - 1)*(2520)

                                N(n) = (n * 2520) - 1 = 2520n - 1

                                **

                                xacc.ide-0.2.0.50 - now with partial MSBuild support!

                                **

                                U Offline
                                U Offline
                                User 12346520
                                wrote on last edited by
                                #32

                                thanks: https://movied.org

                                1 Reply Last reply
                                0
                                • P Paul Conrad

                                  Judah Himango wrote:

                                  Voila, cool little WinForms program that solves it. :cool:

                                  That's cool. Mine is just a plain boring console app :->


                                  I'd like to help but I am too lazy to Google it for you.

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                                  User 12346520
                                  wrote on last edited by
                                  #33

                                  thanks: https://movied.org

                                  1 Reply Last reply
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                                  • P Paul Conrad

                                    There was a question of if there were more number, yes, there are. Here is a modification of your code that shows others :)

                                    #include using namespace std;

                                    int main()
                                    {
                                    int start = 1;
                                    int divisor = 10;
                                    while ( start <1000000 ) // Or whatevery you want in signed 32-bit range
                                    {
                                    while (divisor >= 2)
                                    {
                                    if (start % divisor == divisor - 1)
                                    {
                                    divisor--;
                                    }
                                    else
                                    {
                                    start++;
                                    divisor = 10;
                                    }
                                    }

                                        cout<
                                    
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                                    User 12346520
                                    wrote on last edited by
                                    #34

                                    thanks: https://movied.org

                                    1 Reply Last reply
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                                    • P Paul Conrad

                                      leppie wrote:

                                      So there are more than one of these. I wonder if its some kind of series...

                                      Take a look at the modification of Judah's code that I posted. Your number is one of the numbers that come up :)


                                      I'd like to help but I am too lazy to Google it for you.

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                                      User 12346520
                                      wrote on last edited by
                                      #35

                                      thanks: https://movied.org

                                      1 Reply Last reply
                                      0
                                      • J Judah Gabriel Himango

                                        leppie wrote:

                                        I wonder if its some kind of series...

                                        It appears to be every 2520.

                                        Tech, life, family, faith: Give me a visit. I'm currently blogging about: Messianic Instrumentals (with audio) The apostle Paul, modernly speaking: Epistles of Paul Judah Himango

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                                        User 12346520
                                        wrote on last edited by
                                        #36

                                        thanks: https://movied.org

                                        1 Reply Last reply
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                                        • R Raj Lal

                                          yes thats true there are many , but if you think it might take a day to get the solution , without any computer help, but its worth

                                          Omit Needless Words - Strunk, William, Jr.


                                          Online Project Management
                                          Universal DBA | Ajax Rating | ExplorerTree

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                                          User 12346520
                                          wrote on last edited by
                                          #37

                                          thanks: https://movied.org

                                          1 Reply Last reply
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